Precalculus Examples

$2 \cos (x + \sqrt{3}) = 0$

Step 1

Divide each term in $2 \cos (x + \sqrt{3}) = 0$ by $2$ and simplify.

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Step 1.1

Divide each term in $2 \cos (x + \sqrt{3}) = 0$ by $2$ .

$\frac{2 \cos (x + \sqrt{3})}{2} = \frac{0}{2}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $2$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{2 \cos (x + \sqrt{3})}{2} = \frac{0}{2}$

Step 1.2.1.2

Divide $\cos (x + \sqrt{3})$ by $1$ .

$\cos (x + \sqrt{3}) = \frac{0}{2}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide $0$ by $2$ .

$\cos (x + \sqrt{3}) = 0$

Step 2

Take the inverse cosine of both sides of the equation to extract $x$ from inside the cosine.

$x + \sqrt{3} = \arccos (0)$

Step 3

Simplify the right side.

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Step 3.1

The exact value of $\arccos (0)$ is $\frac{π}{2}$ .

$x + \sqrt{3} = \frac{π}{2}$

Step 4

Subtract $\sqrt{3}$ from both sides of the equation.

$x = \frac{π}{2} - \sqrt{3}$

Step 5

The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the fourth quadrant.

$x + \sqrt{3} = 2 π - \frac{π}{2}$

Step 6

Solve for $x$ .

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Step 6.1

Simplify $2 π - \frac{π}{2}$ .

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Step 6.1.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x + \sqrt{3} = 2 π \cdot \frac{2}{2} - \frac{π}{2}$

Step 6.1.2

Combine fractions.

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Step 6.1.2.1

Combine $2 π$ and $\frac{2}{2}$ .

$x + \sqrt{3} = \frac{2 π \cdot 2}{2} - \frac{π}{2}$

Step 6.1.2.2

Combine the numerators over the common denominator.

$x + \sqrt{3} = \frac{2 π \cdot 2 - π}{2}$

Step 6.1.3

Simplify the numerator.

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Step 6.1.3.1

Multiply $2$ by $2$ .

$x + \sqrt{3} = \frac{4 π - π}{2}$

Step 6.1.3.2

Subtract $π$ from $4 π$ .

$x + \sqrt{3} = \frac{3 π}{2}$

Step 6.2

Subtract $\sqrt{3}$ from both sides of the equation.

$x = \frac{3 π}{2} - \sqrt{3}$

Step 7

Find the period of $\cos (x + \sqrt{3})$ .

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Step 7.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 7.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 7.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 7.4

Divide $2 π$ by $1$ .

$2 π$

Step 8

The period of the $\cos (x + \sqrt{3})$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$x = \frac{π}{2} - \sqrt{3} + 2 π n, \frac{3 π}{2} - \sqrt{3} + 2 π n$ , for any integer $n$

Step 9

Consolidate the answers.

$x = \frac{π}{2} - \sqrt{3} + π n$ , for any integer $n$