Precalculus Examples

$\frac{4}{2 - 3 i} + \frac{2}{1 + i}$

Step 1

Simplify each term.

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Step 1.1

Multiply the numerator and denominator of $\frac{4}{2 - 3 i}$ by the conjugate of $2 - 3 i$ to make the denominator real.

$\frac{4}{2 - 3 i} \cdot \frac{2 + 3 i}{2 + 3 i} + \frac{2}{1 + i}$

Step 1.2

Multiply.

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Step 1.2.1

Combine.

$\frac{4 (2 + 3 i)}{(2 - 3 i) (2 + 3 i)} + \frac{2}{1 + i}$

Step 1.2.2

Simplify the numerator.

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Step 1.2.2.1

Apply the distributive property.

$\frac{4 \cdot 2 + 4 (3 i)}{(2 - 3 i) (2 + 3 i)} + \frac{2}{1 + i}$

Step 1.2.2.2

Multiply $4$ by $2$ .

$\frac{8 + 4 (3 i)}{(2 - 3 i) (2 + 3 i)} + \frac{2}{1 + i}$

Step 1.2.2.3

Multiply $3$ by $4$ .

$\frac{8 + 12 i}{(2 - 3 i) (2 + 3 i)} + \frac{2}{1 + i}$

Step 1.2.3

Simplify the denominator.

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Step 1.2.3.1

Expand $(2 - 3 i) (2 + 3 i)$ using the FOIL Method.

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Step 1.2.3.1.1

Apply the distributive property.

$\frac{8 + 12 i}{2 (2 + 3 i) - 3 i (2 + 3 i)} + \frac{2}{1 + i}$

Step 1.2.3.1.2

Apply the distributive property.

$\frac{8 + 12 i}{2 \cdot 2 + 2 (3 i) - 3 i (2 + 3 i)} + \frac{2}{1 + i}$

Step 1.2.3.1.3

Apply the distributive property.

$\frac{8 + 12 i}{2 \cdot 2 + 2 (3 i) - 3 i \cdot 2 - 3 i (3 i)} + \frac{2}{1 + i}$

Step 1.2.3.2

Simplify.

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Step 1.2.3.2.1

Multiply $2$ by $2$ .

$\frac{8 + 12 i}{4 + 2 (3 i) - 3 i \cdot 2 - 3 i (3 i)} + \frac{2}{1 + i}$

Step 1.2.3.2.2

Multiply $3$ by $2$ .

$\frac{8 + 12 i}{4 + 6 i - 3 i \cdot 2 - 3 i (3 i)} + \frac{2}{1 + i}$

Step 1.2.3.2.3

Multiply $2$ by $- 3$ .

$\frac{8 + 12 i}{4 + 6 i - 6 i - 3 i (3 i)} + \frac{2}{1 + i}$

Step 1.2.3.2.4

Multiply $3$ by $- 3$ .

$\frac{8 + 12 i}{4 + 6 i - 6 i - 9 i i} + \frac{2}{1 + i}$

Step 1.2.3.2.5

Raise $i$ to the power of $1$ .

$\frac{8 + 12 i}{4 + 6 i - 6 i - 9 (i^{1} i)} + \frac{2}{1 + i}$

Step 1.2.3.2.6

Raise $i$ to the power of $1$ .

$\frac{8 + 12 i}{4 + 6 i - 6 i - 9 (i^{1} i^{1})} + \frac{2}{1 + i}$

Step 1.2.3.2.7

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8 + 12 i}{4 + 6 i - 6 i - 9 i^{1 + 1}} + \frac{2}{1 + i}$

Step 1.2.3.2.8

Add $1$ and $1$ .

$\frac{8 + 12 i}{4 + 6 i - 6 i - 9 i^{2}} + \frac{2}{1 + i}$

Step 1.2.3.2.9

Subtract $6 i$ from $6 i$ .

$\frac{8 + 12 i}{4 + 0 - 9 i^{2}} + \frac{2}{1 + i}$

Step 1.2.3.2.10

Add $4$ and $0$ .

$\frac{8 + 12 i}{4 - 9 i^{2}} + \frac{2}{1 + i}$

Step 1.2.3.3

Simplify each term.

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Step 1.2.3.3.1

Rewrite $i^{2}$ as $- 1$ .

$\frac{8 + 12 i}{4 - 9 \cdot - 1} + \frac{2}{1 + i}$

Step 1.2.3.3.2

Multiply $- 9$ by $- 1$ .

$\frac{8 + 12 i}{4 + 9} + \frac{2}{1 + i}$

Step 1.2.3.4

Add $4$ and $9$ .

$\frac{8 + 12 i}{13} + \frac{2}{1 + i}$

Step 1.3

Split the fraction $\frac{8 + 12 i}{13}$ into two fractions.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2}{1 + i}$

Step 1.4

Multiply the numerator and denominator of $\frac{2}{1 + 1 i}$ by the conjugate of $1 + 1 i$ to make the denominator real.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2}{1 + 1 i} \cdot \frac{1 - i}{1 - i}$

Step 1.5

Multiply.

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Step 1.5.1

Combine.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 (1 - i)}{(1 + 1 i) (1 - i)}$

Step 1.5.2

Simplify the numerator.

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Step 1.5.2.1

Apply the distributive property.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 \cdot 1 + 2 (- i)}{(1 + 1 i) (1 - i)}$

Step 1.5.2.2

Multiply $2$ by $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 + 2 (- i)}{(1 + 1 i) (1 - i)}$

Step 1.5.2.3

Multiply $- 1$ by $2$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{(1 + 1 i) (1 - i)}$

Step 1.5.3

Simplify the denominator.

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Step 1.5.3.1

Expand $(1 + 1 i) (1 - i)$ using the FOIL Method.

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Step 1.5.3.1.1

Apply the distributive property.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 (1 - i) + 1 i (1 - i)}$

Step 1.5.3.1.2

Apply the distributive property.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 \cdot 1 + 1 (- i) + 1 i (1 - i)}$

Step 1.5.3.1.3

Apply the distributive property.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 \cdot 1 + 1 (- i) + 1 i \cdot 1 + 1 i (- i)}$

Step 1.5.3.2

Simplify.

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Step 1.5.3.2.1

Multiply $1$ by $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 + 1 (- i) + 1 i \cdot 1 + 1 i (- i)}$

Step 1.5.3.2.2

Multiply $- 1$ by $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i \cdot 1 + 1 i (- i)}$

Step 1.5.3.2.3

Multiply $1$ by $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i + 1 i (- i)}$

Step 1.5.3.2.4

Multiply $- 1$ by $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i - i i}$

Step 1.5.3.2.5

Raise $i$ to the power of $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i - (i^{1} i)}$

Step 1.5.3.2.6

Raise $i$ to the power of $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i - (i^{1} i^{1})}$

Step 1.5.3.2.7

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i - i^{1 + 1}}$

Step 1.5.3.2.8

Add $1$ and $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - 1 i + 1 i - i^{2}}$

Step 1.5.3.2.9

Add $- 1 i$ and $1 i$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 + 0 - i^{2}}$

Step 1.5.3.2.10

Add $1$ and $0$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - i^{2}}$

Step 1.5.3.3

Simplify each term.

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Step 1.5.3.3.1

Rewrite $i^{2}$ as $- 1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 - - 1}$

Step 1.5.3.3.2

Multiply $- 1$ by $- 1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{1 + 1}$

Step 1.5.3.4

Add $1$ and $1$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 - 2 i}{2}$

Step 1.6

Cancel the common factor of $2 - 2 i$ and $2$ .

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Step 1.6.1

Factor $2$ out of $2$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 \cdot 1 - 2 i}{2}$

Step 1.6.2

Factor $2$ out of $- 2 i$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 \cdot 1 + 2 (- i)}{2}$

Step 1.6.3

Factor $2$ out of $2 (1) + 2 (- i)$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 (1 - i)}{2}$

Step 1.6.4

Cancel the common factors.

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Step 1.6.4.1

Factor $2$ out of $2$ .

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 (1 - i)}{2 (1)}$

Step 1.6.4.2

Cancel the common factor.

$\frac{8}{13} + \frac{12 i}{13} + \frac{2 (1 - i)}{2 \cdot 1}$

Step 1.6.4.3

Rewrite the expression.

$\frac{8}{13} + \frac{12 i}{13} + \frac{1 - i}{1}$

Step 1.6.4.4

Divide $1 - i$ by $1$ .

$\frac{8}{13} + \frac{12 i}{13} + 1 - i$

Step 2

Simplify the expression.

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Step 2.1

Write $1$ as a fraction with a common denominator.

$\frac{8}{13} + \frac{13}{13} + \frac{12 i}{13} - i$

Step 2.2

Combine the numerators over the common denominator.

$\frac{8 + 13}{13} + \frac{12 i}{13} - i$

Step 2.3

Add $8$ and $13$ .

$\frac{21}{13} + \frac{12 i}{13} - i$

Step 3

To write $- i$ as a fraction with a common denominator, multiply by $\frac{13}{13}$ .

$\frac{21}{13} + \frac{12 i}{13} - i \cdot \frac{13}{13}$

Step 4

Combine $- i$ and $\frac{13}{13}$ .

$\frac{21}{13} + \frac{12 i}{13} + \frac{- i \cdot 13}{13}$

Step 5

Simplify the expression.

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Step 5.1

Combine the numerators over the common denominator.

$\frac{21}{13} + \frac{- i}{13}$

Step 5.2

Move the negative in front of the fraction.

$\frac{21}{13} - \frac{i}{13}$