Precalculus Examples

$\log_{8} (6) - \log_{8} (3) + \log_{8} (2)$

Step 1

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log_{8} (\frac{6}{3}) + \log_{8} (2)$

Step 2

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{8} (\frac{6}{3} \cdot 2)$

Step 3

Divide $6$ by $3$ .

$\log_{8} (2 \cdot 2)$

Step 4

Multiply $2$ by $2$ .

$\log_{8} (4)$

Step 5

Logarithm base $8$ of $4$ is $\frac{2}{3}$ .

$\frac{2}{3}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$\frac{2}{3}$

Decimal Form:

$0.\overline{6}$