Precalculus Examples

$y = - \frac{1}{3} \cdot \cos (\frac{1}{3} x)$

Step 1

Use the form $a \cos (b x - c) + d$ to find the variables used to find the amplitude, period, phase shift, and vertical shift.

$a = - \frac{1}{3}$

$b = \frac{1}{3}$

$c = 0$

$d = 0$

Step 2

Find the amplitude $| a |$ .

Amplitude: $\frac{1}{3}$

Step 3

Find the period of $- \frac{\cos (\frac{x}{3})}{3}$ .

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Step 3.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 3.2

Replace $b$ with $\frac{1}{3}$ in the formula for period.

$\frac{2 π}{| \frac{1}{3} |}$

Step 3.3

$\frac{1}{3}$ is approximately $0.\overline{3}$ which is positive so remove the absolute value

$\frac{2 π}{\frac{1}{3}}$

Step 3.4

Multiply the numerator by the reciprocal of the denominator.

$2 π \cdot 3$

Step 3.5

Multiply $3$ by $2$ .

$6 π$

Step 4

Find the phase shift using the formula $\frac{c}{b}$ .

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Step 4.1

The phase shift of the function can be calculated from $\frac{c}{b}$ .

Phase Shift: $\frac{c}{b}$

Step 4.2

Replace the values of $c$ and $b$ in the equation for phase shift.

Phase Shift: $\frac{0}{\frac{1}{3}}$

Step 4.3

Multiply the numerator by the reciprocal of the denominator.

Phase Shift: $0 \cdot 3$

Step 4.4

Multiply $0$ by $3$ .

Phase Shift: $0$

Step 5

List the properties of the trigonometric function.

Amplitude: $\frac{1}{3}$

Period: $6 π$

Phase Shift: None

Vertical Shift: None

Step 6

Select a few points to graph.

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Step 6.1

Find the point at $x = 0$ .

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Step 6.1.1

Replace the variable $x$ with $0$ in the expression.

$f (0) = - \frac{\cos (\frac{0}{3})}{3}$

Step 6.1.2

Simplify the result.

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Step 6.1.2.1

Cancel the common factor of $0$ and $3$ .

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Step 6.1.2.1.1

Factor $3$ out of $0$ .

$f (0) = - \frac{\cos (\frac{3 (0)}{3})}{3}$

Step 6.1.2.1.2

Cancel the common factors.

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Step 6.1.2.1.2.1

Factor $3$ out of $3$ .

$f (0) = - \frac{\cos (\frac{3 \cdot 0}{3 \cdot 1})}{3}$

Step 6.1.2.1.2.2

Cancel the common factor.

$f (0) = - \frac{\cos (\frac{3 \cdot 0}{3 \cdot 1})}{3}$

Step 6.1.2.1.2.3

Rewrite the expression.

$f (0) = - \frac{\cos (\frac{0}{1})}{3}$

Step 6.1.2.1.2.4

Divide $0$ by $1$ .

$f (0) = - \frac{\cos (0)}{3}$

Step 6.1.2.2

The exact value of $\cos (0)$ is $1$ .

$f (0) = - \frac{1}{3}$

Step 6.1.2.3

The final answer is $- \frac{1}{3}$ .

$- \frac{1}{3}$

Step 6.2

Find the point at $x = \frac{3 π}{2}$ .

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Step 6.2.1

Replace the variable $x$ with $\frac{3 π}{2}$ in the expression.

$f (\frac{3 π}{2}) = - \frac{\cos (\frac{\frac{3 π}{2}}{3})}{3}$

Step 6.2.2

Simplify the result.

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Step 6.2.2.1

Simplify the numerator.

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Step 6.2.2.1.1

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{3 π}{2}) = - \frac{\cos (\frac{3 π}{2} \cdot \frac{1}{3})}{3}$

Step 6.2.2.1.2

Cancel the common factor of $3$ .

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Step 6.2.2.1.2.1

Factor $3$ out of $3 π$ .

$f (\frac{3 π}{2}) = - \frac{\cos (\frac{3 (π)}{2} \cdot \frac{1}{3})}{3}$

Step 6.2.2.1.2.2

Cancel the common factor.

$f (\frac{3 π}{2}) = - \frac{\cos (\frac{3 π}{2} \cdot \frac{1}{3})}{3}$

Step 6.2.2.1.2.3

Rewrite the expression.

$f (\frac{3 π}{2}) = - \frac{\cos (\frac{π}{2})}{3}$

Step 6.2.2.1.3

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$f (\frac{3 π}{2}) = - \frac{0}{3}$

Step 6.2.2.2

Simplify the expression.

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Step 6.2.2.2.1

Divide $0$ by $3$ .

$f (\frac{3 π}{2}) = - 0$

Step 6.2.2.2.2

Multiply $- 1$ by $0$ .

$f (\frac{3 π}{2}) = 0$

Step 6.2.2.3

The final answer is $0$ .

$0$

Step 6.3

Find the point at $x = 3 π$ .

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Step 6.3.1

Replace the variable $x$ with $3 π$ in the expression.

$f (3 π) = - \frac{\cos (\frac{3 π}{3})}{3}$

Step 6.3.2

Simplify the result.

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Step 6.3.2.1

Cancel the common factor of $3$ .

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Step 6.3.2.1.1

Cancel the common factor.

$f (3 π) = - \frac{\cos (\frac{3 π}{3})}{3}$

Step 6.3.2.1.2

Divide $π$ by $1$ .

$f (3 π) = - \frac{\cos (π)}{3}$

Step 6.3.2.2

Simplify the numerator.

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Step 6.3.2.2.1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the second quadrant.

$f (3 π) = - \frac{- \cos (0)}{3}$

Step 6.3.2.2.2

The exact value of $\cos (0)$ is $1$ .

$f (3 π) = - \frac{- 1 \cdot 1}{3}$

Step 6.3.2.2.3

Multiply $- 1$ by $1$ .

$f (3 π) = - \frac{- 1}{3}$

Step 6.3.2.3

Move the negative in front of the fraction.

$f (3 π) = \frac{1}{3}$

Step 6.3.2.4

The final answer is $\frac{1}{3}$ .

$\frac{1}{3}$

Step 6.4

Find the point at $x = \frac{9 π}{2}$ .

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Step 6.4.1

Replace the variable $x$ with $\frac{9 π}{2}$ in the expression.

$f (\frac{9 π}{2}) = - \frac{\cos (\frac{\frac{9 π}{2}}{3})}{3}$

Step 6.4.2

Simplify the result.

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Step 6.4.2.1

Simplify the numerator.

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Step 6.4.2.1.1

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{9 π}{2}) = - \frac{\cos (\frac{9 π}{2} \cdot \frac{1}{3})}{3}$

Step 6.4.2.1.2

Cancel the common factor of $3$ .

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Step 6.4.2.1.2.1

Factor $3$ out of $9 π$ .

$f (\frac{9 π}{2}) = - \frac{\cos (\frac{3 (3 π)}{2} \cdot \frac{1}{3})}{3}$

Step 6.4.2.1.2.2

Cancel the common factor.

$f (\frac{9 π}{2}) = - \frac{\cos (\frac{3 (3 π)}{2} \cdot \frac{1}{3})}{3}$

Step 6.4.2.1.2.3

Rewrite the expression.

$f (\frac{9 π}{2}) = - \frac{\cos (\frac{3 π}{2})}{3}$

Step 6.4.2.1.3

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.

$f (\frac{9 π}{2}) = - \frac{\cos (\frac{π}{2})}{3}$

Step 6.4.2.1.4

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$f (\frac{9 π}{2}) = - \frac{0}{3}$

Step 6.4.2.2

Simplify the expression.

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Step 6.4.2.2.1

Divide $0$ by $3$ .

$f (\frac{9 π}{2}) = - 0$

Step 6.4.2.2.2

Multiply $- 1$ by $0$ .

$f (\frac{9 π}{2}) = 0$

Step 6.4.2.3

The final answer is $0$ .

$0$

Step 6.5

Find the point at $x = 6 π$ .

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Step 6.5.1

Replace the variable $x$ with $6 π$ in the expression.

$f (6 π) = - \frac{\cos (\frac{6 π}{3})}{3}$

Step 6.5.2

Simplify the result.

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Step 6.5.2.1

Cancel the common factor of $6$ and $3$ .

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Step 6.5.2.1.1

Factor $3$ out of $6 π$ .

$f (6 π) = - \frac{\cos (\frac{3 (2 π)}{3})}{3}$

Step 6.5.2.1.2

Cancel the common factors.

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Step 6.5.2.1.2.1

Factor $3$ out of $3$ .

$f (6 π) = - \frac{\cos (\frac{3 (2 π)}{3 (1)})}{3}$

Step 6.5.2.1.2.2

Cancel the common factor.

$f (6 π) = - \frac{\cos (\frac{3 (2 π)}{3 \cdot 1})}{3}$

Step 6.5.2.1.2.3

Rewrite the expression.

$f (6 π) = - \frac{\cos (\frac{2 π}{1})}{3}$

Step 6.5.2.1.2.4

Divide $2 π$ by $1$ .

$f (6 π) = - \frac{\cos (2 π)}{3}$

Step 6.5.2.2

Simplify the numerator.

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Step 6.5.2.2.1

Subtract full rotations of $2 π$ until the angle is greater than or equal to $0$ and less than $2 π$ .

$f (6 π) = - \frac{\cos (0)}{3}$

Step 6.5.2.2.2

The exact value of $\cos (0)$ is $1$ .

$f (6 π) = - \frac{1}{3}$

Step 6.5.2.3

The final answer is $- \frac{1}{3}$ .

$- \frac{1}{3}$

Step 6.6

List the points in a table.

$\begin{array}{c} x & f (x) \\ 0 & - \frac{1}{3} \\ \frac{3 π}{2} & 0 \\ 3 π & \frac{1}{3} \\ \frac{9 π}{2} & 0 \\ 6 π & - \frac{1}{3} \end{array}$

Step 7

The trig function can be graphed using the amplitude, period, phase shift, vertical shift, and the points.

Amplitude: $\frac{1}{3}$

Period: $6 π$

Phase Shift: None

Vertical Shift: None

$\begin{array}{c} x & f (x) \\ 0 & - \frac{1}{3} \\ \frac{3 π}{2} & 0 \\ 3 π & \frac{1}{3} \\ \frac{9 π}{2} & 0 \\ 6 π & - \frac{1}{3} \end{array}$

Step 8