Precalculus Examples

$2 p - 3 (4 p - (8 p + 1))$

Step 1

Simplify each term.

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$2 p - 3 (4 p - (8 p) - 1 \cdot 1)$

Step 1.1.2

Multiply $8$ by $- 1$ .

$2 p - 3 (4 p - 8 p - 1 \cdot 1)$

Step 1.1.3

Multiply $- 1$ by $1$ .

$2 p - 3 (4 p - 8 p - 1)$

$2 p - 3 (4 p - 8 p - 1)$

Step 1.2

Subtract $8 p$ from $4 p$ .

$2 p - 3 (- 4 p - 1)$

Step 1.3

Apply the distributive property.

$2 p - 3 (- 4 p) - 3 \cdot - 1$

Step 1.4

Multiply $- 4$ by $- 3$ .

$2 p + 12 p - 3 \cdot - 1$

Step 1.5

Multiply $- 3$ by $- 1$ .

$2 p + 12 p + 3$

$2 p + 12 p + 3$

Step 2

Add $2 p$ and $12 p$ .

$14 p + 3$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$