Precalculus Examples

$y = x^{2} + 6 x + 9$

Step 1

Rewrite the equation in vertex form.

Tap for more steps...

Step 1.1

Complete the square for $x^{2} + 6 x + 9$ .

Tap for more steps...

Step 1.1.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 6$

$c = 9$

Step 1.1.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 1.1.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

Tap for more steps...

Step 1.1.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{6}{2 \cdot 1}$

Step 1.1.3.2

Cancel the common factor of $6$ and $2$ .

Tap for more steps...

Step 1.1.3.2.1

Factor $2$ out of $6$ .

$d = \frac{2 \cdot 3}{2 \cdot 1}$

Step 1.1.3.2.2

Cancel the common factors.

Tap for more steps...

Step 1.1.3.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 3}{2 (1)}$

Step 1.1.3.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot 3}{2 \cdot 1}$

Step 1.1.3.2.2.3

Rewrite the expression.

$d = \frac{3}{1}$

Step 1.1.3.2.2.4

Divide $3$ by $1$ .

$d = 3$

Step 1.1.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

Tap for more steps...

Step 1.1.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 9 - \frac{6^{2}}{4 \cdot 1}$

Step 1.1.4.2

Simplify the right side.

Tap for more steps...

Step 1.1.4.2.1

Simplify each term.

Tap for more steps...

Step 1.1.4.2.1.1

Raise $6$ to the power of $2$ .

$e = 9 - \frac{36}{4 \cdot 1}$

Step 1.1.4.2.1.2

Multiply $4$ by $1$ .

$e = 9 - \frac{36}{4}$

Step 1.1.4.2.1.3

Divide $36$ by $4$ .

$e = 9 - 1 \cdot 9$

Step 1.1.4.2.1.4

Multiply $- 1$ by $9$ .

$e = 9 - 9$

Step 1.1.4.2.2

Subtract $9$ from $9$ .

$e = 0$

Step 1.1.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 3)}^{2} + 0$ .

${(x + 3)}^{2} + 0$

Step 1.2

Set $y$ equal to the new right side.

$y = {(x + 3)}^{2} + 0$

Step 2

Use the vertex form, $y = a {(x - h)}^{2} + k$ , to determine the values of $a$ , $h$ , and $k$ .

$a = 1$

$h = - 3$

$k = 0$

Step 3

Find the vertex $(h, k)$ .

$(- 3, 0)$

Step 4