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Precalculus Examples
sin(5x)=0sin(5x)=0
Step 1
Take the inverse sine of both sides of the equation to extract x from inside the sine.
5x=arcsin(0)
Step 2
Step 2.1
The exact value of arcsin(0) is 0.
5x=0
5x=0
Step 3
Step 3.1
Divide each term in 5x=0 by 5.
5x5=05
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of 5.
Step 3.2.1.1
Cancel the common factor.
5x5=05
Step 3.2.1.2
Divide x by 1.
x=05
x=05
x=05
Step 3.3
Simplify the right side.
Step 3.3.1
Divide 0 by 5.
x=0
x=0
x=0
Step 4
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
5x=π-0
Step 5
Step 5.1
Simplify.
Step 5.1.1
Multiply -1 by 0.
5x=π+0
Step 5.1.2
Add π and 0.
5x=π
5x=π
Step 5.2
Divide each term in 5x=π by 5 and simplify.
Step 5.2.1
Divide each term in 5x=π by 5.
5x5=π5
Step 5.2.2
Simplify the left side.
Step 5.2.2.1
Cancel the common factor of 5.
Step 5.2.2.1.1
Cancel the common factor.
5x5=π5
Step 5.2.2.1.2
Divide x by 1.
x=π5
x=π5
x=π5
x=π5
x=π5
Step 6
Step 6.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 6.2
Replace b with 5 in the formula for period.
2π|5|
Step 6.3
The absolute value is the distance between a number and zero. The distance between 0 and 5 is 5.
2π5
2π5
Step 7
The period of the sin(5x) function is 2π5 so values will repeat every 2π5 radians in both directions.
x=2πn5,π5+2πn5, for any integer n
Step 8
Consolidate the answers.
x=πn5, for any integer n