Precalculus Examples

$\sqrt{7 - 3 x}$

Step 1

Set the radicand in $\sqrt{7 - 3 x}$ greater than or equal to $0$ to find where the expression is defined.

$7 - 3 x \geq 0$

Step 2

Solve for $x$ .

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Step 2.1

Subtract $7$ from both sides of the inequality.

$- 3 x \geq - 7$

Step 2.2

Divide each term in $- 3 x \geq - 7$ by $- 3$ and simplify.

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Step 2.2.1

Divide each term in $- 3 x \geq - 7$ by $- 3$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 3 x}{- 3} \leq \frac{- 7}{- 3}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of $- 3$ .

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Step 2.2.2.1.1

Cancel the common factor.

$\frac{- 3 x}{- 3} \leq \frac{- 7}{- 3}$

Step 2.2.2.1.2

Divide $x$ by $1$ .

$x \leq \frac{- 7}{- 3}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Dividing two negative values results in a positive value.

$x \leq \frac{7}{3}$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, \frac{7}{3}]$

Set-Builder Notation:

${x | x \leq \frac{7}{3}}$

Step 4