Precalculus Examples

Simplify ( square root of h^2+1+1)( square root of h^2+1-1)
(h2+1+1)(h2+1-1)(h2+1+1)(h2+11)
Step 1
Expand (h2+1+1)(h2+1-1)(h2+1+1)(h2+11) using the FOIL Method.
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Step 1.1
Apply the distributive property.
h2+1(h2+1-1)+1(h2+1-1)h2+1(h2+11)+1(h2+11)
Step 1.2
Apply the distributive property.
h2+1h2+1+h2+1-1+1(h2+1-1)h2+1h2+1+h2+11+1(h2+11)
Step 1.3
Apply the distributive property.
h2+1h2+1+h2+1-1+1h2+1+1-1h2+1h2+1+h2+11+1h2+1+11
h2+1h2+1+h2+1-1+1h2+1+1-1h2+1h2+1+h2+11+1h2+1+11
Step 2
Simplify and combine like terms.
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Step 2.1
Simplify each term.
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Step 2.1.1
Multiply h2+1h2+1h2+1h2+1.
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Step 2.1.1.1
Raise h2+1h2+1 to the power of 11.
h2+11h2+1+h2+1-1+1h2+1+1-1h2+11h2+1+h2+11+1h2+1+11
Step 2.1.1.2
Raise h2+1h2+1 to the power of 11.
h2+11h2+11+h2+1-1+1h2+1+1-1h2+11h2+11+h2+11+1h2+1+11
Step 2.1.1.3
Use the power rule aman=am+naman=am+n to combine exponents.
h2+11+1+h2+1-1+1h2+1+1-1h2+11+1+h2+11+1h2+1+11
Step 2.1.1.4
Add 11 and 11.
h2+12+h2+1-1+1h2+1+1-1h2+12+h2+11+1h2+1+11
h2+12+h2+1-1+1h2+1+1-1h2+12+h2+11+1h2+1+11
Step 2.1.2
Rewrite h2+12h2+12 as h2+1h2+1.
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Step 2.1.2.1
Use nax=axnnax=axn to rewrite h2+1h2+1 as (h2+1)12(h2+1)12.
((h2+1)12)2+h2+1-1+1h2+1+1-1((h2+1)12)2+h2+11+1h2+1+11
Step 2.1.2.2
Apply the power rule and multiply exponents, (am)n=amn(am)n=amn.
(h2+1)122+h2+1-1+1h2+1+1-1(h2+1)122+h2+11+1h2+1+11
Step 2.1.2.3
Combine 1212 and 22.
(h2+1)22+h2+1-1+1h2+1+1-1(h2+1)22+h2+11+1h2+1+11
Step 2.1.2.4
Cancel the common factor of 22.
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Step 2.1.2.4.1
Cancel the common factor.
(h2+1)22+h2+1-1+1h2+1+1-1
Step 2.1.2.4.2
Rewrite the expression.
(h2+1)1+h2+1-1+1h2+1+1-1
(h2+1)1+h2+1-1+1h2+1+1-1
Step 2.1.2.5
Simplify.
h2+1+h2+1-1+1h2+1+1-1
h2+1+h2+1-1+1h2+1+1-1
Step 2.1.3
Move -1 to the left of h2+1.
h2+1-1h2+1+1h2+1+1-1
Step 2.1.4
Rewrite -1h2+1 as -h2+1.
h2+1-h2+1+1h2+1+1-1
Step 2.1.5
Multiply h2+1 by 1.
h2+1-h2+1+h2+1+1-1
Step 2.1.6
Multiply -1 by 1.
h2+1-h2+1+h2+1-1
h2+1-h2+1+h2+1-1
Step 2.2
Subtract 1 from 1.
h2+0-h2+1+h2+1
Step 2.3
Add h2 and 0.
h2-h2+1+h2+1
Step 2.4
Add -h2+1 and h2+1.
h2+0
Step 2.5
Add h2 and 0.
h2
h2
 [x2  12  π  xdx ]