Enter a problem...
Precalculus Examples
3ln(5x)=103ln(5x)=10
Step 1
Step 1.1
Divide each term in 3ln(5x)=103ln(5x)=10 by 33.
3ln(5x)3=1033ln(5x)3=103
Step 1.2
Simplify the left side.
Step 1.2.1
Cancel the common factor of 33.
Step 1.2.1.1
Cancel the common factor.
3ln(5x)3=103
Step 1.2.1.2
Divide ln(5x) by 1.
ln(5x)=103
ln(5x)=103
ln(5x)=103
ln(5x)=103
Step 2
To solve for x, rewrite the equation using properties of logarithms.
eln(5x)=e103
Step 3
Rewrite ln(5x)=103 in exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then logb(x)=y is equivalent to by=x.
e103=5x
Step 4
Step 4.1
Rewrite the equation as 5x=e103.
5x=e103
Step 4.2
Divide each term in 5x=e103 by 5 and simplify.
Step 4.2.1
Divide each term in 5x=e103 by 5.
5x5=e1035
Step 4.2.2
Simplify the left side.
Step 4.2.2.1
Cancel the common factor of 5.
Step 4.2.2.1.1
Cancel the common factor.
5x5=e1035
Step 4.2.2.1.2
Divide x by 1.
x=e1035
x=e1035
x=e1035
x=e1035
x=e1035
Step 5
The result can be shown in multiple forms.
Exact Form:
x=e1035
Decimal Form:
x=5.60632497…