Precalculus Examples

Solve for ? 2sin(x)- square root of 3=0
2sin(x)-3=02sin(x)3=0
Step 1
Add 33 to both sides of the equation.
2sin(x)=32sin(x)=3
Step 2
Divide each term in 2sin(x)=3 by 2 and simplify.
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Step 2.1
Divide each term in 2sin(x)=3 by 2.
2sin(x)2=32
Step 2.2
Simplify the left side.
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Step 2.2.1
Cancel the common factor of 2.
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Step 2.2.1.1
Cancel the common factor.
2sin(x)2=32
Step 2.2.1.2
Divide sin(x) by 1.
sin(x)=32
sin(x)=32
sin(x)=32
sin(x)=32
Step 3
Take the inverse sine of both sides of the equation to extract x from inside the sine.
x=arcsin(32)
Step 4
Simplify the right side.
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Step 4.1
The exact value of arcsin(32) is π3.
x=π3
x=π3
Step 5
The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from π to find the solution in the second quadrant.
x=π-π3
Step 6
Simplify π-π3.
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Step 6.1
To write π as a fraction with a common denominator, multiply by 33.
x=π33-π3
Step 6.2
Combine fractions.
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Step 6.2.1
Combine π and 33.
x=π33-π3
Step 6.2.2
Combine the numerators over the common denominator.
x=π3-π3
x=π3-π3
Step 6.3
Simplify the numerator.
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Step 6.3.1
Move 3 to the left of π.
x=3π-π3
Step 6.3.2
Subtract π from 3π.
x=2π3
x=2π3
x=2π3
Step 7
Find the period of sin(x).
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Step 7.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 7.2
Replace b with 1 in the formula for period.
2π|1|
Step 7.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
2π1
Step 7.4
Divide 2π by 1.
2π
2π
Step 8
The period of the sin(x) function is 2π so values will repeat every 2π radians in both directions.
x=π3+2πn,2π3+2πn, for any integer n
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