Precalculus Examples

$x - 2 y + 3 z = 7$ , $2 x + y + z = 4$ , $- 3 x + 2 y - 2 z = - 10$

Step 1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1

Add $2 y$ to both sides of the equation.

$x + 3 z = 7 + 2 y$

$2 x + y + z = 4$

$- 3 x + 2 y - 2 z = - 10$

Step 1.2

Subtract $3 z$ from both sides of the equation.

$x = 7 + 2 y - 3 z$

$2 x + y + z = 4$

$- 3 x + 2 y - 2 z = - 10$

$x = 7 + 2 y - 3 z$

$2 x + y + z = 4$

$- 3 x + 2 y - 2 z = - 10$

Step 2

Replace all occurrences of $x$ with $7 + 2 y - 3 z$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $2 x + y + z = 4$ with $7 + 2 y - 3 z$ .

$2 (7 + 2 y - 3 z) + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $2 (7 + 2 y - 3 z) + y + z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$2 \cdot 7 + 2 (2 y) + 2 (- 3 z) + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $2$ by $7$ .

$14 + 2 (2 y) + 2 (- 3 z) + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.2.1.1.2.2

Multiply $2$ by $2$ .

$14 + 4 y + 2 (- 3 z) + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.2.1.1.2.3

Multiply $- 3$ by $2$ .

$14 + 4 y - 6 z + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

$14 + 4 y - 6 z + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

$14 + 4 y - 6 z + y + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Add $4 y$ and $y$ .

$14 + 5 y - 6 z + z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.2.1.2.2

Add $- 6 z$ and $z$ .

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 10$

Step 2.3

Replace all occurrences of $x$ in $- 3 x + 2 y - 2 z = - 10$ with $7 + 2 y - 3 z$ .

$- 3 (7 + 2 y - 3 z) + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $- 3 (7 + 2 y - 3 z) + 2 y - 2 z$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$- 3 \cdot 7 - 3 (2 y) - 3 (- 3 z) + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 2.4.1.1.2

Simplify.

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Step 2.4.1.1.2.1

Multiply $- 3$ by $7$ .

$- 21 - 3 (2 y) - 3 (- 3 z) + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 2.4.1.1.2.2

Multiply $2$ by $- 3$ .

$- 21 - 6 y - 3 (- 3 z) + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 2.4.1.1.2.3

Multiply $- 3$ by $- 3$ .

$- 21 - 6 y + 9 z + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 21 - 6 y + 9 z + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 21 - 6 y + 9 z + 2 y - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 2.4.1.2

Simplify by adding terms.

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Step 2.4.1.2.1

Add $- 6 y$ and $2 y$ .

$- 21 - 4 y + 9 z - 2 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 2.4.1.2.2

Subtract $2 z$ from $9 z$ .

$- 21 - 4 y + 7 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 21 - 4 y + 7 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 21 - 4 y + 7 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 21 - 4 y + 7 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 21 - 4 y + 7 z = - 10$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3

Solve for $y$ in $- 21 - 4 y + 7 z = - 10$ .

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Step 3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 3.1.1

Add $21$ to both sides of the equation.

$- 4 y + 7 z = - 10 + 21$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.1.2

Subtract $7 z$ from both sides of the equation.

$- 4 y = - 10 + 21 - 7 z$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.1.3

Add $- 10$ and $21$ .

$- 4 y = 11 - 7 z$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$- 4 y = 11 - 7 z$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.2

Divide each term in $- 4 y = 11 - 7 z$ by $- 4$ and simplify.

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Step 3.2.1

Divide each term in $- 4 y = 11 - 7 z$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{11}{- 4} + \frac{- 7 z}{- 4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $- 4$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{11}{- 4} + \frac{- 7 z}{- 4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{11}{- 4} + \frac{- 7 z}{- 4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$y = \frac{11}{- 4} + \frac{- 7 z}{- 4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$y = \frac{11}{- 4} + \frac{- 7 z}{- 4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Move the negative in front of the fraction.

$y = - \frac{11}{4} + \frac{- 7 z}{- 4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 3.2.3.1.2

Dividing two negative values results in a positive value.

$y = - \frac{11}{4} + \frac{7 z}{4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$14 + 5 y - 5 z = 4$

$x = 7 + 2 y - 3 z$

Step 4

Replace all occurrences of $y$ with $- \frac{11}{4} + \frac{7 z}{4}$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $14 + 5 y - 5 z = 4$ with $- \frac{11}{4} + \frac{7 z}{4}$ .

$14 + 5 (- \frac{11}{4} + \frac{7 z}{4}) - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $14 + 5 (- \frac{11}{4} + \frac{7 z}{4}) - 5 z$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$14 + 5 (- \frac{11}{4}) + 5 (\frac{7 z}{4}) - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.1.2

Multiply $5 (- \frac{11}{4})$ .

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Step 4.2.1.1.2.1

Multiply $- 1$ by $5$ .

$14 - 5 (\frac{11}{4}) + 5 (\frac{7 z}{4}) - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.1.2.2

Combine $- 5$ and $\frac{11}{4}$ .

$14 + \frac{- 5 \cdot 11}{4} + 5 (\frac{7 z}{4}) - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.1.2.3

Multiply $- 5$ by $11$ .

$14 + \frac{- 55}{4} + 5 (\frac{7 z}{4}) - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

$14 + \frac{- 55}{4} + 5 (\frac{7 z}{4}) - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.1.3

Multiply $5 \frac{7 z}{4}$ .

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Step 4.2.1.1.3.1

Combine $5$ and $\frac{7 z}{4}$ .

$14 + \frac{- 55}{4} + \frac{5 (7 z)}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.1.3.2

Multiply $7$ by $5$ .

$14 + \frac{- 55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

$14 + \frac{- 55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.1.4

Move the negative in front of the fraction.

$14 - \frac{55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

$14 - \frac{55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.2

To write $14$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$14 \cdot \frac{4}{4} - \frac{55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.3

Combine $14$ and $\frac{4}{4}$ .

$\frac{14 \cdot 4}{4} - \frac{55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.4

Combine the numerators over the common denominator.

$\frac{14 \cdot 4 - 55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.5

Simplify the numerator.

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Step 4.2.1.5.1

Multiply $14$ by $4$ .

$\frac{56 - 55}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.5.2

Subtract $55$ from $56$ .

$\frac{1}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

$\frac{1}{4} + \frac{35 z}{4} - 5 z = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.6

To write $- 5 z$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{1}{4} + \frac{35 z}{4} - 5 z \cdot \frac{4}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.7

Combine $- 5 z$ and $\frac{4}{4}$ .

$\frac{1}{4} + \frac{35 z}{4} + \frac{- 5 z \cdot 4}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.8

Combine the numerators over the common denominator.

$\frac{1}{4} + \frac{35 z - 5 z \cdot 4}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.9

Combine the numerators over the common denominator.

$\frac{1 + 35 z - 5 z \cdot 4}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.10

Multiply $4$ by $- 5$ .

$\frac{1 + 35 z - 20 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.2.1.11

Subtract $20 z$ from $35 z$ .

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + 2 y - 3 z$

Step 4.3

Replace all occurrences of $y$ in $x = 7 + 2 y - 3 z$ with $- \frac{11}{4} + \frac{7 z}{4}$ .

$x = 7 + 2 (- \frac{11}{4} + \frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $7 + 2 (- \frac{11}{4} + \frac{7 z}{4}) - 3 z$ .

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Step 4.4.1.1

Simplify each term.

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Step 4.4.1.1.1

Apply the distributive property.

$x = 7 + 2 (- \frac{11}{4}) + 2 (\frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.2

Cancel the common factor of $2$ .

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Step 4.4.1.1.2.1

Move the leading negative in $- \frac{11}{4}$ into the numerator.

$x = 7 + 2 (\frac{- 11}{4}) + 2 (\frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.2.2

Factor $2$ out of $4$ .

$x = 7 + 2 (\frac{- 11}{2 (2)}) + 2 (\frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.2.3

Cancel the common factor.

$x = 7 + 2 (\frac{- 11}{2 \cdot 2}) + 2 (\frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.2.4

Rewrite the expression.

$x = 7 + \frac{- 11}{2} + 2 (\frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + \frac{- 11}{2} + 2 (\frac{7 z}{4}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.3

Cancel the common factor of $2$ .

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Step 4.4.1.1.3.1

Factor $2$ out of $4$ .

$x = 7 + \frac{- 11}{2} + 2 (\frac{7 z}{2 (2)}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.3.2

Cancel the common factor.

$x = 7 + \frac{- 11}{2} + 2 (\frac{7 z}{2 \cdot 2}) - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.3.3

Rewrite the expression.

$x = 7 + \frac{- 11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 + \frac{- 11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.1.4

Move the negative in front of the fraction.

$x = 7 - \frac{11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 7 - \frac{11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.2

To write $7$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = 7 \cdot \frac{2}{2} - \frac{11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.3

Combine $7$ and $\frac{2}{2}$ .

$x = \frac{7 \cdot 2}{2} - \frac{11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.4

Combine the numerators over the common denominator.

$x = \frac{7 \cdot 2 - 11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.5

Simplify the numerator.

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Step 4.4.1.5.1

Multiply $7$ by $2$ .

$x = \frac{14 - 11}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.5.2

Subtract $11$ from $14$ .

$x = \frac{3}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = \frac{3}{2} + \frac{7 z}{2} - 3 z$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.6

To write $- 3 z$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = \frac{3}{2} + \frac{7 z}{2} - 3 z \cdot \frac{2}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.7

Combine $- 3 z$ and $\frac{2}{2}$ .

$x = \frac{3}{2} + \frac{7 z}{2} + \frac{- 3 z \cdot 2}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.8

Combine the numerators over the common denominator.

$x = \frac{3}{2} + \frac{7 z - 3 z \cdot 2}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.9

Combine the numerators over the common denominator.

$x = \frac{3 + 7 z - 3 z \cdot 2}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.10

Multiply $2$ by $- 3$ .

$x = \frac{3 + 7 z - 6 z}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 4.4.1.11

Subtract $6 z$ from $7 z$ .

$x = \frac{3 + z}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = \frac{3 + z}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = \frac{3 + z}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = \frac{3 + z}{2}$

$\frac{1 + 15 z}{4} = 4$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5

Solve for $z$ in $\frac{1 + 15 z}{4} = 4$ .

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Step 5.1

Multiply both sides by $4$ .

$\frac{1 + 15 z}{4} \cdot 4 = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.2

Simplify.

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Step 5.2.1

Simplify the left side.

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Step 5.2.1.1

Simplify $\frac{1 + 15 z}{4} \cdot 4$ .

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Step 5.2.1.1.1

Cancel the common factor of $4$ .

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Step 5.2.1.1.1.1

Cancel the common factor.

$\frac{1 + 15 z}{4} \cdot 4 = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.2.1.1.1.2

Rewrite the expression.

$1 + 15 z = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$1 + 15 z = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.2.1.1.2

Reorder $1$ and $15 z$ .

$15 z + 1 = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$15 z + 1 = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$15 z + 1 = 4 \cdot 4$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.2.2

Simplify the right side.

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Step 5.2.2.1

Multiply $4$ by $4$ .

$15 z + 1 = 16$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$15 z + 1 = 16$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$15 z + 1 = 16$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.3

Solve for $z$ .

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Step 5.3.1

Move all terms not containing $z$ to the right side of the equation.

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Step 5.3.1.1

Subtract $1$ from both sides of the equation.

$15 z = 16 - 1$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.3.1.2

Subtract $1$ from $16$ .

$15 z = 15$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$15 z = 15$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.3.2

Divide each term in $15 z = 15$ by $15$ and simplify.

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Step 5.3.2.1

Divide each term in $15 z = 15$ by $15$ .

$\frac{15 z}{15} = \frac{15}{15}$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.3.2.2

Simplify the left side.

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Step 5.3.2.2.1

Cancel the common factor of $15$ .

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Step 5.3.2.2.1.1

Cancel the common factor.

$\frac{15 z}{15} = \frac{15}{15}$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.3.2.2.1.2

Divide $z$ by $1$ .

$z = \frac{15}{15}$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$z = \frac{15}{15}$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$z = \frac{15}{15}$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 5.3.2.3

Simplify the right side.

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Step 5.3.2.3.1

Divide $15$ by $15$ .

$z = 1$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$z = 1$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$z = 1$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$z = 1$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$z = 1$

$x = \frac{3 + z}{2}$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 6

Replace all occurrences of $z$ with $1$ in each equation.

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Step 6.1

Replace all occurrences of $z$ in $x = \frac{3 + z}{2}$ with $1$ .

$x = \frac{3 + 1}{2}$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 6.2

Simplify $x = \frac{3 + 1}{2}$ .

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Step 6.2.1

Simplify the left side.

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Step 6.2.1.1

Remove parentheses.

$x = \frac{3 + 1}{2}$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = \frac{3 + 1}{2}$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 6.2.2

Simplify the right side.

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Step 6.2.2.1

Simplify $\frac{3 + 1}{2}$ .

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Step 6.2.2.1.1

Add $3$ and $1$ .

$x = \frac{4}{2}$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 6.2.2.1.2

Divide $4$ by $2$ .

$x = 2$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 2$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 2$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

$x = 2$

$z = 1$

$y = - \frac{11}{4} + \frac{7 z}{4}$

Step 6.3

Replace all occurrences of $z$ in $y = - \frac{11}{4} + \frac{7 z}{4}$ with $1$ .

$y = - \frac{11}{4} + \frac{7 (1)}{4}$

$x = 2$

$z = 1$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $- \frac{11}{4} + \frac{7 (1)}{4}$ .

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Step 6.4.1.1

Combine the numerators over the common denominator.

$y = \frac{- 11 + 7 (1)}{4}$

$x = 2$

$z = 1$

Step 6.4.1.2

Simplify the expression.

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Step 6.4.1.2.1

Multiply $7$ by $1$ .

$y = \frac{- 11 + 7}{4}$

$x = 2$

$z = 1$

Step 6.4.1.2.2

Add $- 11$ and $7$ .

$y = \frac{- 4}{4}$

$x = 2$

$z = 1$

Step 6.4.1.2.3

Divide $- 4$ by $4$ .

$y = - 1$

$x = 2$

$z = 1$

$y = - 1$

$x = 2$

$z = 1$

$y = - 1$

$x = 2$

$z = 1$

$y = - 1$

$x = 2$

$z = 1$

$y = - 1$

$x = 2$

$z = 1$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, - 1, 1)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(2, - 1, 1)$

Equation Form:

$x = 2, y = - 1, z = 1$