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Precalculus Examples
2x+2y-z=22x+2y−z=2 , x-3y+z=-28 , -x+y=4
Step 1
Step 1.1
Add 3y to both sides of the equation.
x+z=-28+3y
2x+2y-z=2
-x+y=4
Step 1.2
Subtract z from both sides of the equation.
x=-28+3y-z
2x+2y-z=2
-x+y=4
x=-28+3y-z
2x+2y-z=2
-x+y=4
Step 2
Step 2.1
Replace all occurrences of x in 2x+2y-z=2 with -28+3y-z.
2(-28+3y-z)+2y-z=2
x=-28+3y-z
-x+y=4
Step 2.2
Simplify the left side.
Step 2.2.1
Simplify 2(-28+3y-z)+2y-z.
Step 2.2.1.1
Simplify each term.
Step 2.2.1.1.1
Apply the distributive property.
2⋅-28+2(3y)+2(-z)+2y-z=2
x=-28+3y-z
-x+y=4
Step 2.2.1.1.2
Simplify.
Step 2.2.1.1.2.1
Multiply 2 by -28.
-56+2(3y)+2(-z)+2y-z=2
x=-28+3y-z
-x+y=4
Step 2.2.1.1.2.2
Multiply 3 by 2.
-56+6y+2(-z)+2y-z=2
x=-28+3y-z
-x+y=4
Step 2.2.1.1.2.3
Multiply -1 by 2.
-56+6y-2z+2y-z=2
x=-28+3y-z
-x+y=4
-56+6y-2z+2y-z=2
x=-28+3y-z
-x+y=4
-56+6y-2z+2y-z=2
x=-28+3y-z
-x+y=4
Step 2.2.1.2
Simplify by adding terms.
Step 2.2.1.2.1
Add 6y and 2y.
-56+8y-2z-z=2
x=-28+3y-z
-x+y=4
Step 2.2.1.2.2
Subtract z from -2z.
-56+8y-3z=2
x=-28+3y-z
-x+y=4
-56+8y-3z=2
x=-28+3y-z
-x+y=4
-56+8y-3z=2
x=-28+3y-z
-x+y=4
-56+8y-3z=2
x=-28+3y-z
-x+y=4
Step 2.3
Replace all occurrences of x in -x+y=4 with -28+3y-z.
-(-28+3y-z)+y=4
-56+8y-3z=2
x=-28+3y-z
Step 2.4
Simplify the left side.
Step 2.4.1
Simplify -(-28+3y-z)+y.
Step 2.4.1.1
Simplify each term.
Step 2.4.1.1.1
Apply the distributive property.
28-(3y)+z+y=4
-56+8y-3z=2
x=-28+3y-z
Step 2.4.1.1.2
Simplify.
Step 2.4.1.1.2.1
Multiply -1 by -28.
28-(3y)+z+y=4
-56+8y-3z=2
x=-28+3y-z
Step 2.4.1.1.2.2
Multiply 3 by -1.
28-3y+z+y=4
-56+8y-3z=2
x=-28+3y-z
Step 2.4.1.1.2.3
Multiply --z.
Step 2.4.1.1.2.3.1
Multiply -1 by -1.
28-3y+1z+y=4
-56+8y-3z=2
x=-28+3y-z
Step 2.4.1.1.2.3.2
Multiply z by 1.
28-3y+z+y=4
-56+8y-3z=2
x=-28+3y-z
28-3y+z+y=4
-56+8y-3z=2
x=-28+3y-z
28-3y+z+y=4
-56+8y-3z=2
x=-28+3y-z
28-3y+z+y=4
-56+8y-3z=2
x=-28+3y-z
Step 2.4.1.2
Add -3y and y.
28-2y+z=4
-56+8y-3z=2
x=-28+3y-z
28-2y+z=4
-56+8y-3z=2
x=-28+3y-z
28-2y+z=4
-56+8y-3z=2
x=-28+3y-z
28-2y+z=4
-56+8y-3z=2
x=-28+3y-z
Step 3
Step 3.1
Subtract 28 from both sides of the equation.
-2y+z=4-28
-56+8y-3z=2
x=-28+3y-z
Step 3.2
Add 2y to both sides of the equation.
z=4-28+2y
-56+8y-3z=2
x=-28+3y-z
Step 3.3
Subtract 28 from 4.
z=-24+2y
-56+8y-3z=2
x=-28+3y-z
z=-24+2y
-56+8y-3z=2
x=-28+3y-z
Step 4
Step 4.1
Replace all occurrences of z in -56+8y-3z=2 with -24+2y.
-56+8y-3(-24+2y)=2
z=-24+2y
x=-28+3y-z
Step 4.2
Simplify the left side.
Step 4.2.1
Simplify -56+8y-3(-24+2y).
Step 4.2.1.1
Simplify each term.
Step 4.2.1.1.1
Apply the distributive property.
-56+8y-3⋅-24-3(2y)=2
z=-24+2y
x=-28+3y-z
Step 4.2.1.1.2
Multiply -3 by -24.
-56+8y+72-3(2y)=2
z=-24+2y
x=-28+3y-z
Step 4.2.1.1.3
Multiply 2 by -3.
-56+8y+72-6y=2
z=-24+2y
x=-28+3y-z
-56+8y+72-6y=2
z=-24+2y
x=-28+3y-z
Step 4.2.1.2
Simplify by adding terms.
Step 4.2.1.2.1
Add -56 and 72.
8y+16-6y=2
z=-24+2y
x=-28+3y-z
Step 4.2.1.2.2
Subtract 6y from 8y.
2y+16=2
z=-24+2y
x=-28+3y-z
2y+16=2
z=-24+2y
x=-28+3y-z
2y+16=2
z=-24+2y
x=-28+3y-z
2y+16=2
z=-24+2y
x=-28+3y-z
Step 4.3
Replace all occurrences of z in x=-28+3y-z with -24+2y.
x=-28+3y-(-24+2y)
2y+16=2
z=-24+2y
Step 4.4
Simplify the right side.
Step 4.4.1
Simplify -28+3y-(-24+2y).
Step 4.4.1.1
Simplify each term.
Step 4.4.1.1.1
Apply the distributive property.
x=-28+3y+24-(2y)
2y+16=2
z=-24+2y
Step 4.4.1.1.2
Multiply -1 by -24.
x=-28+3y+24-(2y)
2y+16=2
z=-24+2y
Step 4.4.1.1.3
Multiply 2 by -1.
x=-28+3y+24-2y
2y+16=2
z=-24+2y
x=-28+3y+24-2y
2y+16=2
z=-24+2y
Step 4.4.1.2
Simplify by adding terms.
Step 4.4.1.2.1
Add -28 and 24.
x=3y-4-2y
2y+16=2
z=-24+2y
Step 4.4.1.2.2
Subtract 2y from 3y.
x=y-4
2y+16=2
z=-24+2y
x=y-4
2y+16=2
z=-24+2y
x=y-4
2y+16=2
z=-24+2y
x=y-4
2y+16=2
z=-24+2y
x=y-4
2y+16=2
z=-24+2y
Step 5
Step 5.1
Move all terms not containing y to the right side of the equation.
Step 5.1.1
Subtract 16 from both sides of the equation.
2y=2-16
x=y-4
z=-24+2y
Step 5.1.2
Subtract 16 from 2.
2y=-14
x=y-4
z=-24+2y
2y=-14
x=y-4
z=-24+2y
Step 5.2
Divide each term in 2y=-14 by 2 and simplify.
Step 5.2.1
Divide each term in 2y=-14 by 2.
2y2=-142
x=y-4
z=-24+2y
Step 5.2.2
Simplify the left side.
Step 5.2.2.1
Cancel the common factor of 2.
Step 5.2.2.1.1
Cancel the common factor.
2y2=-142
x=y-4
z=-24+2y
Step 5.2.2.1.2
Divide y by 1.
y=-142
x=y-4
z=-24+2y
y=-142
x=y-4
z=-24+2y
y=-142
x=y-4
z=-24+2y
Step 5.2.3
Simplify the right side.
Step 5.2.3.1
Divide -14 by 2.
y=-7
x=y-4
z=-24+2y
y=-7
x=y-4
z=-24+2y
y=-7
x=y-4
z=-24+2y
y=-7
x=y-4
z=-24+2y
Step 6
Step 6.1
Replace all occurrences of y in x=y-4 with -7.
x=(-7)-4
y=-7
z=-24+2y
Step 6.2
Simplify the right side.
Step 6.2.1
Subtract 4 from -7.
x=-11
y=-7
z=-24+2y
x=-11
y=-7
z=-24+2y
Step 6.3
Replace all occurrences of y in z=-24+2y with -7.
z=-24+2(-7)
x=-11
y=-7
Step 6.4
Simplify the right side.
Step 6.4.1
Simplify -24+2(-7).
Step 6.4.1.1
Multiply 2 by -7.
z=-24-14
x=-11
y=-7
Step 6.4.1.2
Subtract 14 from -24.
z=-38
x=-11
y=-7
z=-38
x=-11
y=-7
z=-38
x=-11
y=-7
z=-38
x=-11
y=-7
Step 7
The solution to the system is the complete set of ordered pairs that are valid solutions.
(-11,-7,-38)
Step 8
The result can be shown in multiple forms.
Point Form:
(-11,-7,-38)
Equation Form:
x=-11,y=-7,z=-38