Precalculus Examples

Solve for x square root of x^2+8-3=0
x2+8-3=0
Step 1
Use axn=axn to rewrite x2+8 as (x2+8)12.
(x2+8)12-3=0
Step 2
Add 3 to both sides of the equation.
(x2+8)12=3
Step 3
Raise each side of the equation to the power of 2 to eliminate the fractional exponent on the left side.
((x2+8)12)2=32
Step 4
Simplify the exponent.
Tap for more steps...
Step 4.1
Simplify the left side.
Tap for more steps...
Step 4.1.1
Simplify ((x2+8)12)2.
Tap for more steps...
Step 4.1.1.1
Multiply the exponents in ((x2+8)12)2.
Tap for more steps...
Step 4.1.1.1.1
Apply the power rule and multiply exponents, (am)n=amn.
(x2+8)122=32
Step 4.1.1.1.2
Cancel the common factor of 2.
Tap for more steps...
Step 4.1.1.1.2.1
Cancel the common factor.
(x2+8)122=32
Step 4.1.1.1.2.2
Rewrite the expression.
(x2+8)1=32
(x2+8)1=32
(x2+8)1=32
Step 4.1.1.2
Simplify.
x2+8=32
x2+8=32
x2+8=32
Step 4.2
Simplify the right side.
Tap for more steps...
Step 4.2.1
Raise 3 to the power of 2.
x2+8=9
x2+8=9
x2+8=9
Step 5
Solve for x.
Tap for more steps...
Step 5.1
Move all terms not containing x to the right side of the equation.
Tap for more steps...
Step 5.1.1
Subtract 8 from both sides of the equation.
x2=9-8
Step 5.1.2
Subtract 8 from 9.
x2=1
x2=1
Step 5.2
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
x=±1
Step 5.3
Any root of 1 is 1.
x=±1
Step 5.4
The complete solution is the result of both the positive and negative portions of the solution.
Tap for more steps...
Step 5.4.1
First, use the positive value of the ± to find the first solution.
x=1
Step 5.4.2
Next, use the negative value of the ± to find the second solution.
x=-1
Step 5.4.3
The complete solution is the result of both the positive and negative portions of the solution.
x=1,-1
x=1,-1
x=1,-1
x2+82-3=0
(
(
)
)
|
|
[
[
]
]
7
7
8
8
9
9
°
°
θ
θ
4
4
5
5
6
6
/
/
^
^
×
×
>
>
π
π
1
1
2
2
3
3
-
-
+
+
÷
÷
<
<
,
,
0
0
.
.
%
%
=
=
 [x2  12  π  xdx ]