Precalculus Examples

Solve for ? square root of 3tan(x)-1=0
3tan(x)-1=0
Step 1
Add 1 to both sides of the equation.
3tan(x)=1
Step 2
Divide each term in 3tan(x)=1 by 3 and simplify.
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Step 2.1
Divide each term in 3tan(x)=1 by 3.
3tan(x)3=13
Step 2.2
Simplify the left side.
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Step 2.2.1
Cancel the common factor of 3.
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Step 2.2.1.1
Cancel the common factor.
3tan(x)3=13
Step 2.2.1.2
Divide tan(x) by 1.
tan(x)=13
tan(x)=13
tan(x)=13
Step 2.3
Simplify the right side.
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Step 2.3.1
Multiply 13 by 33.
tan(x)=1333
Step 2.3.2
Combine and simplify the denominator.
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Step 2.3.2.1
Multiply 13 by 33.
tan(x)=333
Step 2.3.2.2
Raise 3 to the power of 1.
tan(x)=3313
Step 2.3.2.3
Raise 3 to the power of 1.
tan(x)=33131
Step 2.3.2.4
Use the power rule aman=am+n to combine exponents.
tan(x)=331+1
Step 2.3.2.5
Add 1 and 1.
tan(x)=332
Step 2.3.2.6
Rewrite 32 as 3.
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Step 2.3.2.6.1
Use axn=axn to rewrite 3 as 312.
tan(x)=3(312)2
Step 2.3.2.6.2
Apply the power rule and multiply exponents, (am)n=amn.
tan(x)=33122
Step 2.3.2.6.3
Combine 12 and 2.
tan(x)=3322
Step 2.3.2.6.4
Cancel the common factor of 2.
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Step 2.3.2.6.4.1
Cancel the common factor.
tan(x)=3322
Step 2.3.2.6.4.2
Rewrite the expression.
tan(x)=331
tan(x)=331
Step 2.3.2.6.5
Evaluate the exponent.
tan(x)=33
tan(x)=33
tan(x)=33
tan(x)=33
tan(x)=33
Step 3
Take the inverse tangent of both sides of the equation to extract x from inside the tangent.
x=arctan(33)
Step 4
Simplify the right side.
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Step 4.1
The exact value of arctan(33) is π6.
x=π6
x=π6
Step 5
The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from π to find the solution in the fourth quadrant.
x=π+π6
Step 6
Simplify π+π6.
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Step 6.1
To write π as a fraction with a common denominator, multiply by 66.
x=π66+π6
Step 6.2
Combine fractions.
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Step 6.2.1
Combine π and 66.
x=π66+π6
Step 6.2.2
Combine the numerators over the common denominator.
x=π6+π6
x=π6+π6
Step 6.3
Simplify the numerator.
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Step 6.3.1
Move 6 to the left of π.
x=6π+π6
Step 6.3.2
Add 6π and π.
x=7π6
x=7π6
x=7π6
Step 7
Find the period of tan(x).
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Step 7.1
The period of the function can be calculated using π|b|.
π|b|
Step 7.2
Replace b with 1 in the formula for period.
π|1|
Step 7.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
π1
Step 7.4
Divide π by 1.
π
π
Step 8
The period of the tan(x) function is π so values will repeat every π radians in both directions.
x=π6+πn,7π6+πn, for any integer n
Step 9
Consolidate the answers.
x=π6+πn, for any integer n
32tan(x)-1=0
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