Precalculus Examples

Solve Using the Quadratic Formula x^2+30x+200=0
x2+30x+200=0x2+30x+200=0
Step 1
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2ab±b24(ac)2a
Step 2
Substitute the values a=1a=1, b=30b=30, and c=200c=200 into the quadratic formula and solve for xx.
-30±302-4(1200)2130±3024(1200)21
Step 3
Simplify.
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Step 3.1
Simplify the numerator.
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Step 3.1.1
Raise 3030 to the power of 22.
x=-30±900-4120021x=30±9004120021
Step 3.1.2
Multiply -4120041200.
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Step 3.1.2.1
Multiply -44 by 11.
x=-30±900-420021x=30±900420021
Step 3.1.2.2
Multiply -44 by 200200.
x=-30±900-80021x=30±90080021
x=-30±900-80021x=30±90080021
Step 3.1.3
Subtract 800800 from 900900.
x=-30±10021x=30±10021
Step 3.1.4
Rewrite 100100 as 102102.
x=-30±10221x=30±10221
Step 3.1.5
Pull terms out from under the radical, assuming positive real numbers.
x=-30±1021x=30±1021
x=-30±1021x=30±1021
Step 3.2
Multiply 22 by 11.
x=-30±102x=30±102
Step 3.3
Simplify -30±10230±102.
x=-15±5x=15±5
x=-15±5x=15±5
Step 4
The final answer is the combination of both solutions.
x=-10,-20x=10,20
 [x2  12  π  xdx ]  x2  12  π  xdx