Precalculus Examples

Solve for x 6x^2+12x+7=0
6x2+12x+7=0
Step 1
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Step 2
Substitute the values a=6, b=12, and c=7 into the quadratic formula and solve for x.
-12±122-4(67)26
Step 3
Simplify.
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Step 3.1
Simplify the numerator.
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Step 3.1.1
Raise 12 to the power of 2.
x=-12±144-46726
Step 3.1.2
Multiply -467.
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Step 3.1.2.1
Multiply -4 by 6.
x=-12±144-24726
Step 3.1.2.2
Multiply -24 by 7.
x=-12±144-16826
x=-12±144-16826
Step 3.1.3
Subtract 168 from 144.
x=-12±-2426
Step 3.1.4
Rewrite -24 as -1(24).
x=-12±-12426
Step 3.1.5
Rewrite -1(24) as -124.
x=-12±-12426
Step 3.1.6
Rewrite -1 as i.
x=-12±i2426
Step 3.1.7
Rewrite 24 as 226.
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Step 3.1.7.1
Factor 4 out of 24.
x=-12±i4(6)26
Step 3.1.7.2
Rewrite 4 as 22.
x=-12±i22626
x=-12±i22626
Step 3.1.8
Pull terms out from under the radical.
x=-12±i(26)26
Step 3.1.9
Move 2 to the left of i.
x=-12±2i626
x=-12±2i626
Step 3.2
Multiply 2 by 6.
x=-12±2i612
Step 3.3
Simplify -12±2i612.
x=-6±i66
x=-6±i66
Step 4
The final answer is the combination of both solutions.
x=-6-i66,-6+i66
6x2+12x+7=0
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 [x2  12  π  xdx ]