Precalculus Examples

$f (x) = \frac{x - 2}{x^{2} - 2 x}$

Step 1

Consider the difference quotient formula.

$\frac{f (x + h) - f (x)}{h}$

Step 2

Find the components of the definition.

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Step 2.1

Evaluate the function at $x = x + h$ .

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Step 2.1.1

Replace the variable $x$ with $x + h$ in the expression.

$f (x + h) = \frac{(x + h) - 2}{{(x + h)}^{2} - 2 (x + h)}$

Step 2.1.2

Simplify the result.

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Step 2.1.2.1

Factor $x + h$ out of ${(x + h)}^{2} - 2 (x + h)$ .

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Step 2.1.2.1.1

Factor $x + h$ out of ${(x + h)}^{2}$ .

$f (x + h) = \frac{x + h - 2}{(x + h) (x + h) - 2 (x + h)}$

Step 2.1.2.1.2

Factor $x + h$ out of $- 2 (x + h)$ .

$f (x + h) = \frac{x + h - 2}{(x + h) (x + h) + (x + h) \cdot - 2}$

Step 2.1.2.1.3

Factor $x + h$ out of $(x + h) (x + h) + (x + h) \cdot - 2$ .

$f (x + h) = \frac{x + h - 2}{(x + h) (x + h - 2)}$

Step 2.1.2.2

Cancel the common factor of $x + h - 2$ .

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Step 2.1.2.2.1

Cancel the common factor.

$f (x + h) = \frac{x + h - 2}{(x + h) (x + h - 2)}$

Step 2.1.2.2.2

Rewrite the expression.

$f (x + h) = \frac{1}{x + h}$

Step 2.1.2.3

The final answer is $\frac{1}{x + h}$ .

$\frac{1}{x + h}$

Step 2.2

Find the components of the definition.

$f (x + h) = \frac{1}{x + h}$

$f (x) = \frac{1}{x}$

$f (x + h) = \frac{1}{x + h}$

$f (x) = \frac{1}{x}$

Step 3

Plug in the components.

$\frac{f (x + h) - f (x)}{h} = \frac{\frac{1}{x + h} - (\frac{1}{x})}{h}$

Step 4

Simplify.

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Step 4.1

Simplify the numerator.

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Step 4.1.1

To write $\frac{1}{x + h}$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$\frac{\frac{1}{x + h} \cdot \frac{x}{x} - \frac{1}{x}}{h}$

Step 4.1.2

To write $- \frac{1}{x}$ as a fraction with a common denominator, multiply by $\frac{x + h}{x + h}$ .

$\frac{\frac{1}{x + h} \cdot \frac{x}{x} - \frac{1}{x} \cdot \frac{x + h}{x + h}}{h}$

Step 4.1.3

Write each expression with a common denominator of $(x + h) x$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.1.3.1

Multiply $\frac{1}{x + h}$ by $\frac{x}{x}$ .

$\frac{\frac{x}{(x + h) x} - \frac{1}{x} \cdot \frac{x + h}{x + h}}{h}$

Step 4.1.3.2

Multiply $\frac{1}{x}$ by $\frac{x + h}{x + h}$ .

$\frac{\frac{x}{(x + h) x} - \frac{x + h}{x (x + h)}}{h}$

Step 4.1.3.3

Reorder the factors of $(x + h) x$ .

$\frac{\frac{x}{x (x + h)} - \frac{x + h}{x (x + h)}}{h}$

Step 4.1.4

Combine the numerators over the common denominator.

$\frac{\frac{x - (x + h)}{x (x + h)}}{h}$

Step 4.1.5

Rewrite $\frac{x - (x + h)}{x (x + h)}$ in a factored form.

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Step 4.1.5.1

Apply the distributive property.

$\frac{\frac{x - x - h}{x (x + h)}}{h}$

Step 4.1.5.2

Subtract $x$ from $x$ .

$\frac{\frac{0 - h}{x (x + h)}}{h}$

Step 4.1.5.3

Subtract $h$ from $0$ .

$\frac{\frac{- h}{x (x + h)}}{h}$

Step 4.1.6

Move the negative in front of the fraction.

$\frac{- \frac{h}{x (x + h)}}{h}$

Step 4.2

Multiply the numerator by the reciprocal of the denominator.

$- \frac{h}{x (x + h)} \cdot \frac{1}{h}$

Step 4.3

Cancel the common factor of $h$ .

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Step 4.3.1

Move the leading negative in $- \frac{h}{x (x + h)}$ into the numerator.

$\frac{- h}{x (x + h)} \cdot \frac{1}{h}$

Step 4.3.2

Factor $h$ out of $- h$ .

$\frac{h \cdot - 1}{x (x + h)} \cdot \frac{1}{h}$

Step 4.3.3

Cancel the common factor.

$\frac{h \cdot - 1}{x (x + h)} \cdot \frac{1}{h}$

Step 4.3.4

Rewrite the expression.

$\frac{- 1}{x (x + h)}$

Step 4.4

Move the negative in front of the fraction.

$- \frac{1}{x (x + h)}$

Step 5