Precalculus Examples

Solve the Function Operation f(x)=(x-3)^2-2 if x!=3; 2 if x=3 Find f(3)
f(x)={(x-3)2-2x32x=3 Find f(3)
Step 1
Identify the piece that describes the function at x=3. In this case, x=3 falls within the interval x=3, therefore use 2 to evaluate f(3).
f(x)={(x-3)2-2x32x=3
Step 2
The function is equal to 2 at x=3.
f(x)=2(]x=3)
Step 3
Evaluate the function at x=3.
f(3)=2
 [x2  12  π  xdx ]