Precalculus Examples

$\frac{37 - 11}{(x + 1) (x^{2} - 5 x + 6)}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

Factor the fraction.

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Step 1.1.1

Subtract $11$ from $37$ .

$\frac{26}{(x + 1) (x^{2} - 5 x + 6)}$

Step 1.1.2

Factor.

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Step 1.1.2.1

Factor $x^{2} - 5 x + 6$ using the AC method.

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Step 1.1.2.1.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $6$ and whose sum is $- 5$ .

$- 3, - 2$

Step 1.1.2.1.2

Write the factored form using these integers.

$\frac{26}{(x + 1) ((x - 3) (x - 2))}$

Step 1.1.2.2

Remove unnecessary parentheses.

$\frac{26}{(x + 1) (x - 3) (x - 2)}$

Step 1.2

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $A$ .

$\frac{A}{x + 1}$

Step 1.3

$\frac{A}{x + 1} + \frac{B}{x - 3}$

Step 1.4

$\frac{A}{x + 1} + \frac{B}{x - 3} + \frac{C}{x - 2}$

Step 1.5

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $(x + 1) (x - 3) (x - 2)$ .

$\frac{26 (x + 1) (x - 3) (x - 2)}{(x + 1) (x - 3) (x - 2)} = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.6

Cancel the common factor of $x + 1$ .

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Step 1.6.1

Cancel the common factor.

$\frac{26 (x + 1) (x - 3) (x - 2)}{(x + 1) (x - 3) (x - 2)} = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.6.2

Rewrite the expression.

$\frac{(26 (x - 3)) (x - 2)}{(x - 3) (x - 2)} = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.7

Cancel the common factor of $x - 3$ .

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Step 1.7.1

Cancel the common factor.

$\frac{26 (x - 3) (x - 2)}{(x - 3) (x - 2)} = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.7.2

Rewrite the expression.

$\frac{(26) (x - 2)}{x - 2} = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.8

Cancel the common factor of $x - 2$ .

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Step 1.8.1

Cancel the common factor.

$\frac{26 (x - 2)}{x - 2} = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.8.2

Divide $26$ by $1$ .

$26 = \frac{(A) (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9

Simplify each term.

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Step 1.9.1

Cancel the common factor of $x + 1$ .

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Step 1.9.1.1

Cancel the common factor.

$26 = \frac{A (x + 1) (x - 3) (x - 2)}{x + 1} + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.1.2

Divide $((A) (x - 3)) (x - 2)$ by $1$ .

$26 = ((A) (x - 3)) (x - 2) + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.2

Apply the distributive property.

$26 = (A x + A \cdot - 3) (x - 2) + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.3

Move $- 3$ to the left of $A$ .

$26 = (A x - 3 \cdot A) (x - 2) + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.4

Expand $(A x - 3 A) (x - 2)$ using the FOIL Method.

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Step 1.9.4.1

Apply the distributive property.

$26 = A x (x - 2) - 3 A (x - 2) + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.4.2

Apply the distributive property.

$26 = A x \cdot x + A x \cdot - 2 - 3 A (x - 2) + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.4.3

Apply the distributive property.

$26 = A x \cdot x + A x \cdot - 2 - 3 A x - 3 A \cdot - 2 + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.5

Simplify and combine like terms.

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Step 1.9.5.1

Simplify each term.

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Step 1.9.5.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.9.5.1.1.1

Move $x$ .

$26 = A (x \cdot x) + A x \cdot - 2 - 3 A x - 3 A \cdot - 2 + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.5.1.1.2

Multiply $x$ by $x$ .

$26 = A x^{2} + A x \cdot - 2 - 3 A x - 3 A \cdot - 2 + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.5.1.2

Move $- 2$ to the left of $A x$ .

$26 = A x^{2} - 2 \cdot (A x) - 3 A x - 3 A \cdot - 2 + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.5.1.3

Multiply $- 2$ by $- 3$ .

$26 = A x^{2} - 2 A x - 3 A x + 6 A + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.5.2

Subtract $3 A x$ from $- 2 A x$ .

$26 = A x^{2} - 5 A x + 6 A + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.6

Cancel the common factor of $x - 3$ .

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Step 1.9.6.1

Cancel the common factor.

$26 = A x^{2} - 5 A x + 6 A + \frac{(B) (x + 1) (x - 3) (x - 2)}{x - 3} + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.6.2

Divide $(B) (x + 1) (x - 2)$ by $1$ .

$26 = A x^{2} - 5 A x + 6 A + (B) (x + 1) (x - 2) + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.7

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + (B x + B \cdot 1) (x - 2) + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.8

Multiply $B$ by $1$ .

$26 = A x^{2} - 5 A x + 6 A + (B x + B) (x - 2) + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.9

Expand $(B x + B) (x - 2)$ using the FOIL Method.

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Step 1.9.9.1

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x (x - 2) + B (x - 2) + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.9.2

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x \cdot x + B x \cdot - 2 + B (x - 2) + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.9.3

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x \cdot x + B x \cdot - 2 + B x + B \cdot - 2 + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.10

Simplify and combine like terms.

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Step 1.9.10.1

Simplify each term.

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Step 1.9.10.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.9.10.1.1.1

Move $x$ .

$26 = A x^{2} - 5 A x + 6 A + B (x \cdot x) + B x \cdot - 2 + B x + B \cdot - 2 + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.10.1.1.2

Multiply $x$ by $x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} + B x \cdot - 2 + B x + B \cdot - 2 + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.10.1.2

Move $- 2$ to the left of $B x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - 2 \cdot (B x) + B x + B \cdot - 2 + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.10.1.3

Move $- 2$ to the left of $B$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - 2 B x + B x - 2 B + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.10.2

Add $- 2 B x$ and $B x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.11

Cancel the common factor of $x - 2$ .

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Step 1.9.11.1

Cancel the common factor.

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + \frac{(C) (x + 1) (x - 3) (x - 2)}{x - 2}$

Step 1.9.11.2

Divide $(C) (x + 1) (x - 3)$ by $1$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + (C) (x + 1) (x - 3)$

Step 1.9.12

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + (C x + C \cdot 1) (x - 3)$

Step 1.9.13

Multiply $C$ by $1$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + (C x + C) (x - 3)$

Step 1.9.14

Expand $(C x + C) (x - 3)$ using the FOIL Method.

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Step 1.9.14.1

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x (x - 3) + C (x - 3)$

Step 1.9.14.2

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x \cdot x + C x \cdot - 3 + C (x - 3)$

Step 1.9.14.3

Apply the distributive property.

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x \cdot x + C x \cdot - 3 + C x + C \cdot - 3$

Step 1.9.15

Simplify and combine like terms.

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Step 1.9.15.1

Simplify each term.

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Step 1.9.15.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.9.15.1.1.1

Move $x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C (x \cdot x) + C x \cdot - 3 + C x + C \cdot - 3$

Step 1.9.15.1.1.2

Multiply $x$ by $x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x^{2} + C x \cdot - 3 + C x + C \cdot - 3$

Step 1.9.15.1.2

Move $- 3$ to the left of $C x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x^{2} - 3 \cdot (C x) + C x + C \cdot - 3$

Step 1.9.15.1.3

Move $- 3$ to the left of $C$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x^{2} - 3 C x + C x - 3 C$

Step 1.9.15.2

Add $- 3 C x$ and $C x$ .

$26 = A x^{2} - 5 A x + 6 A + B x^{2} - B x - 2 B + C x^{2} - 2 C x - 3 C$

Step 1.10

Simplify the expression.

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Step 1.10.1

Move $A$ .

$26 = A x^{2} - 5 x A + 6 A + B x^{2} - B x - 2 B + C x^{2} - 2 C x - 3 C$

Step 1.10.2

Reorder $B$ and $x^{2}$ .

$26 = A x^{2} - 5 x A + 6 A + B x^{2} - B x - 2 B + C x^{2} - 2 C x - 3 C$

Step 1.10.3

Move $B$ .

$26 = A x^{2} - 5 x A + 6 A + B x^{2} - 1 x B - 2 B + C x^{2} - 2 C x - 3 C$

Step 1.10.4

Move $- 2 B$ .

$26 = A x^{2} - 5 x A + 6 A + B x^{2} - 1 x B + C x^{2} - 2 C x - 2 B - 3 C$

Step 1.10.5

Move $6 A$ .

$26 = A x^{2} - 5 x A + B x^{2} - 1 x B + C x^{2} - 2 C x + 6 A - 2 B - 3 C$

Step 1.10.6

Move $- 1 x B$ .

$26 = A x^{2} - 5 x A + B x^{2} + C x^{2} - 1 x B - 2 C x + 6 A - 2 B - 3 C$

Step 1.10.7

Move $- 5 x A$ .

$26 = A x^{2} + B x^{2} + C x^{2} - 5 x A - 1 x B - 2 C x + 6 A - 2 B - 3 C$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = A + B + C$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = - 5 A - 1 B - 2 C$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$26 = 6 A - 2 B - 3 C$

Step 2.4

Set up the system of equations to find the coefficients of the partial fractions.

$0 = A + B + C$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

$0 = A + B + C$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $A$ in $0 = A + B + C$ .

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Step 3.1.1

Rewrite the equation as $A + B + C = 0$ .

$A + B + C = 0$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

Step 3.1.2

Move all terms not containing $A$ to the right side of the equation.

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Step 3.1.2.1

Subtract $B$ from both sides of the equation.

$A + C = - B$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

Step 3.1.2.2

Subtract $C$ from both sides of the equation.

$A = - B - C$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

$A = - B - C$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

$A = - B - C$

$0 = - 5 A - 1 B - 2 C$

$26 = 6 A - 2 B - 3 C$

Step 3.2

Replace all occurrences of $A$ with $- B - C$ in each equation.

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Step 3.2.1

Replace all occurrences of $A$ in $0 = - 5 A - 1 B - 2 C$ with $- B - C$ .

$0 = - 5 (- B - C) - 1 B - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Simplify $- 5 (- B - C) - 1 B - 2 C$ .

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Step 3.2.2.1.1

Simplify each term.

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Step 3.2.2.1.1.1

Apply the distributive property.

$0 = - 5 (- B) - 5 (- C) - 1 B - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.2.1.1.2

Multiply $- 1$ by $- 5$ .

$0 = 5 B - 5 (- C) - 1 B - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.2.1.1.3

Multiply $- 1$ by $- 5$ .

$0 = 5 B + 5 C - 1 B - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.2.1.1.4

Rewrite $- 1 B$ as $- B$ .

$0 = 5 B + 5 C - B - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

$0 = 5 B + 5 C - B - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.2.1.2

Simplify by adding terms.

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Step 3.2.2.1.2.1

Subtract $B$ from $5 B$ .

$0 = 4 B + 5 C - 2 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.2.1.2.2

Subtract $2 C$ from $5 C$ .

$0 = 4 B + 3 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = 6 A - 2 B - 3 C$

Step 3.2.3

Replace all occurrences of $A$ in $26 = 6 A - 2 B - 3 C$ with $- B - C$ .

$26 = 6 (- B - C) - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.2.4

Simplify the right side.

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Step 3.2.4.1

Simplify $6 (- B - C) - 2 B - 3 C$ .

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Step 3.2.4.1.1

Simplify each term.

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Step 3.2.4.1.1.1

Apply the distributive property.

$26 = 6 (- B) + 6 (- C) - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.2.4.1.1.2

Multiply $- 1$ by $6$ .

$26 = - 6 B + 6 (- C) - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.2.4.1.1.3

Multiply $- 1$ by $6$ .

$26 = - 6 B - 6 C - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = - 6 B - 6 C - 2 B - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.2.4.1.2

Simplify by adding terms.

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Step 3.2.4.1.2.1

Subtract $2 B$ from $- 6 B$ .

$26 = - 8 B - 6 C - 3 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.2.4.1.2.2

Subtract $3 C$ from $- 6 C$ .

$26 = - 8 B - 9 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = - 8 B - 9 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = - 8 B - 9 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = - 8 B - 9 C$

$0 = 4 B + 3 C$

$A = - B - C$

$26 = - 8 B - 9 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3

Solve for $B$ in $26 = - 8 B - 9 C$ .

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Step 3.3.1

Rewrite the equation as $- 8 B - 9 C = 26$ .

$- 8 B - 9 C = 26$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.2

Add $9 C$ to both sides of the equation.

$- 8 B = 26 + 9 C$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3

Divide each term in $- 8 B = 26 + 9 C$ by $- 8$ and simplify.

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Step 3.3.3.1

Divide each term in $- 8 B = 26 + 9 C$ by $- 8$ .

$\frac{- 8 B}{- 8} = \frac{26}{- 8} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.2

Simplify the left side.

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Step 3.3.3.2.1

Cancel the common factor of $- 8$ .

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Step 3.3.3.2.1.1

Cancel the common factor.

$\frac{- 8 B}{- 8} = \frac{26}{- 8} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.2.1.2

Divide $B$ by $1$ .

$B = \frac{26}{- 8} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = \frac{26}{- 8} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = \frac{26}{- 8} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.3

Simplify the right side.

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Step 3.3.3.3.1

Simplify each term.

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Step 3.3.3.3.1.1

Cancel the common factor of $26$ and $- 8$ .

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Step 3.3.3.3.1.1.1

Factor $2$ out of $26$ .

$B = \frac{2 (13)}{- 8} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.3.1.1.2

Cancel the common factors.

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Step 3.3.3.3.1.1.2.1

Factor $2$ out of $- 8$ .

$B = \frac{2 \cdot 13}{2 \cdot - 4} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.3.1.1.2.2

Cancel the common factor.

$B = \frac{2 \cdot 13}{2 \cdot - 4} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.3.1.1.2.3

Rewrite the expression.

$B = \frac{13}{- 4} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = \frac{13}{- 4} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = \frac{13}{- 4} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.3.1.2

Move the negative in front of the fraction.

$B = - \frac{13}{4} + \frac{9 C}{- 8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.3.3.3.1.3

Move the negative in front of the fraction.

$B = - \frac{13}{4} - \frac{9 C}{8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$0 = 4 B + 3 C$

$A = - B - C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$0 = 4 B + 3 C$

$A = - B - C$

Step 3.4

Replace all occurrences of $B$ with $- \frac{13}{4} - \frac{9 C}{8}$ in each equation.

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Step 3.4.1

Replace all occurrences of $B$ in $0 = 4 B + 3 C$ with $- \frac{13}{4} - \frac{9 C}{8}$ .

$0 = 4 (- \frac{13}{4} - \frac{9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $4 (- \frac{13}{4} - \frac{9 C}{8}) + 3 C$ .

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Step 3.4.2.1.1

Simplify each term.

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Step 3.4.2.1.1.1

Apply the distributive property.

$0 = 4 (- \frac{13}{4}) + 4 (- \frac{9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.2

Cancel the common factor of $4$ .

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Step 3.4.2.1.1.2.1

Move the leading negative in $- \frac{13}{4}$ into the numerator.

$0 = 4 (\frac{- 13}{4}) + 4 (- \frac{9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.2.2

Cancel the common factor.

$0 = 4 (\frac{- 13}{4}) + 4 (- \frac{9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.2.3

Rewrite the expression.

$0 = - 13 + 4 (- \frac{9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 + 4 (- \frac{9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.3

Cancel the common factor of $4$ .

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Step 3.4.2.1.1.3.1

Move the leading negative in $- \frac{9 C}{8}$ into the numerator.

$0 = - 13 + 4 (\frac{- 9 C}{8}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.3.2

Factor $4$ out of $8$ .

$0 = - 13 + 4 (\frac{- 9 C}{4 (2)}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.3.3

Cancel the common factor.

$0 = - 13 + 4 (\frac{- 9 C}{4 \cdot 2}) + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.3.4

Rewrite the expression.

$0 = - 13 + \frac{- 9 C}{2} + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 + \frac{- 9 C}{2} + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.1.4

Move the negative in front of the fraction.

$0 = - 13 - \frac{9 C}{2} + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 - \frac{9 C}{2} + 3 C$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.2

To write $3 C$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$0 = - 13 - \frac{9 C}{2} + 3 C \cdot \frac{2}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.3

Simplify terms.

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Step 3.4.2.1.3.1

Combine $3 C$ and $\frac{2}{2}$ .

$0 = - 13 - \frac{9 C}{2} + \frac{3 C \cdot 2}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.3.2

Combine the numerators over the common denominator.

$0 = - 13 + \frac{- 9 C + 3 C \cdot 2}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 + \frac{- 9 C + 3 C \cdot 2}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.4

Simplify each term.

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Step 3.4.2.1.4.1

Simplify the numerator.

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Step 3.4.2.1.4.1.1

Factor $3 C$ out of $- 9 C + 3 C \cdot 2$ .

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Step 3.4.2.1.4.1.1.1

Factor $3 C$ out of $- 9 C$ .

$0 = - 13 + \frac{3 C (- 3) + 3 C \cdot 2}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.4.1.1.2

Factor $3 C$ out of $3 C \cdot 2$ .

$0 = - 13 + \frac{3 C (- 3) + 3 C (2)}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.4.1.1.3

Factor $3 C$ out of $3 C (- 3) + 3 C (2)$ .

$0 = - 13 + \frac{3 C (- 3 + 2)}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 + \frac{3 C (- 3 + 2)}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.4.1.2

Add $- 3$ and $2$ .

$0 = - 13 + \frac{3 C \cdot - 1}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.4.1.3

Multiply $- 1$ by $3$ .

$0 = - 13 + \frac{- 3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 + \frac{- 3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.2.1.4.2

Move the negative in front of the fraction.

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = - B - C$

Step 3.4.3

Replace all occurrences of $B$ in $A = - B - C$ with $- \frac{13}{4} - \frac{9 C}{8}$ .

$A = - (- \frac{13}{4} - \frac{9 C}{8}) - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4

Simplify the right side.

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Step 3.4.4.1

Simplify $- (- \frac{13}{4} - \frac{9 C}{8}) - C$ .

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Step 3.4.4.1.1

Simplify each term.

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Step 3.4.4.1.1.1

Apply the distributive property.

$A = \frac{13}{4} + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.1.2

Multiply $- - \frac{13}{4}$ .

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Step 3.4.4.1.1.2.1

Multiply $- 1$ by $- 1$ .

$A = 1 (\frac{13}{4}) + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.1.2.2

Multiply $\frac{13}{4}$ by $1$ .

$A = \frac{13}{4} + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.1.3

Multiply $- - \frac{9 C}{8}$ .

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Step 3.4.4.1.1.3.1

Multiply $- 1$ by $- 1$ .

$A = \frac{13}{4} + 1 (\frac{9 C}{8}) - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.1.3.2

Multiply $\frac{9 C}{8}$ by $1$ .

$A = \frac{13}{4} + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{9 C}{8} - C$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.2

To write $- C$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$A = \frac{13}{4} + \frac{9 C}{8} - C \cdot \frac{8}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.3

Simplify terms.

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Step 3.4.4.1.3.1

Combine $- C$ and $\frac{8}{8}$ .

$A = \frac{13}{4} + \frac{9 C}{8} + \frac{- C \cdot 8}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.3.2

Combine the numerators over the common denominator.

$A = \frac{13}{4} + \frac{9 C - C \cdot 8}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{9 C - C \cdot 8}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.4

Simplify each term.

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Step 3.4.4.1.4.1

Simplify the numerator.

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Step 3.4.4.1.4.1.1

Factor $C$ out of $9 C - C \cdot 8$ .

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Step 3.4.4.1.4.1.1.1

Factor $C$ out of $9 C$ .

$A = \frac{13}{4} + \frac{C \cdot 9 - C \cdot 8}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.4.1.1.2

Factor $C$ out of $- C \cdot 8$ .

$A = \frac{13}{4} + \frac{C \cdot 9 + C (- 1 \cdot 8)}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.4.1.1.3

Factor $C$ out of $C \cdot 9 + C (- 1 \cdot 8)$ .

$A = \frac{13}{4} + \frac{C (9 - 1 \cdot 8)}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{C (9 - 1 \cdot 8)}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.4.1.2

Multiply $- 1$ by $8$ .

$A = \frac{13}{4} + \frac{C (9 - 8)}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.4.1.3

Subtract $8$ from $9$ .

$A = \frac{13}{4} + \frac{C \cdot 1}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{C \cdot 1}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.4.4.1.4.2

Multiply $C$ by $1$ .

$A = \frac{13}{4} + \frac{C}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{C}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{C}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{C}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{C}{8}$

$0 = - 13 - \frac{3 C}{2}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5

Solve for $C$ in $0 = - 13 - \frac{3 C}{2}$ .

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Step 3.5.1

Rewrite the equation as $- 13 - \frac{3 C}{2} = 0$ .

$- 13 - \frac{3 C}{2} = 0$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.2

Add $13$ to both sides of the equation.

$- \frac{3 C}{2} = 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.3

Multiply both sides of the equation by $- \frac{2}{3}$ .

$- \frac{2}{3} \cdot (- \frac{3 C}{2}) = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4

Simplify both sides of the equation.

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Step 3.5.4.1

Simplify the left side.

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Step 3.5.4.1.1

Simplify $- \frac{2}{3} (- \frac{3 C}{2})$ .

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Step 3.5.4.1.1.1

Cancel the common factor of $2$ .

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Step 3.5.4.1.1.1.1

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$\frac{- 2}{3} \cdot (- \frac{3 C}{2}) = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.1.2

Move the leading negative in $- \frac{3 C}{2}$ into the numerator.

$\frac{- 2}{3} \cdot \frac{- 3 C}{2} = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.1.3

Factor $2$ out of $- 2$ .

$\frac{2 (- 1)}{3} \cdot \frac{- 3 C}{2} = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.1.4

Cancel the common factor.

$\frac{2 \cdot - 1}{3} \cdot \frac{- 3 C}{2} = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.1.5

Rewrite the expression.

$\frac{- 1}{3} \cdot (- 3 C) = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$\frac{- 1}{3} \cdot (- 3 C) = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.2

Cancel the common factor of $3$ .

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Step 3.5.4.1.1.2.1

Factor $3$ out of $- 3 C$ .

$\frac{- 1}{3} \cdot (3 (- C)) = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.2.2

Cancel the common factor.

$\frac{- 1}{3} \cdot (3 (- C)) = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.2.3

Rewrite the expression.

$C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.3

Multiply.

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Step 3.5.4.1.1.3.1

Multiply $- 1$ by $- 1$ .

$1 C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.1.1.3.2

Multiply $C$ by $1$ .

$C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{2}{3} \cdot 13$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.2

Simplify the right side.

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Step 3.5.4.2.1

Simplify $- \frac{2}{3} \cdot 13$ .

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Step 3.5.4.2.1.1

Multiply $- \frac{2}{3} \cdot 13$ .

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Step 3.5.4.2.1.1.1

Multiply $13$ by $- 1$ .

$C = - 13 (\frac{2}{3})$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.2.1.1.2

Combine $- 13$ and $\frac{2}{3}$ .

$C = \frac{- 13 \cdot 2}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.2.1.1.3

Multiply $- 13$ by $2$ .

$C = \frac{- 26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = \frac{- 26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.5.4.2.1.2

Move the negative in front of the fraction.

$C = - \frac{26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$C = - \frac{26}{3}$

$A = \frac{13}{4} + \frac{C}{8}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6

Replace all occurrences of $C$ with $- \frac{26}{3}$ in each equation.

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Step 3.6.1

Replace all occurrences of $C$ in $A = \frac{13}{4} + \frac{C}{8}$ with $- \frac{26}{3}$ .

$A = \frac{13}{4} + \frac{- \frac{26}{3}}{8}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $\frac{13}{4} + \frac{- \frac{26}{3}}{8}$ .

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Step 3.6.2.1.1

Simplify each term.

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Step 3.6.2.1.1.1

Multiply the numerator by the reciprocal of the denominator.

$A = \frac{13}{4} - \frac{26}{3} \cdot \frac{1}{8}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.2

Cancel the common factor of $2$ .

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Step 3.6.2.1.1.2.1

Move the leading negative in $- \frac{26}{3}$ into the numerator.

$A = \frac{13}{4} + \frac{- 26}{3} \cdot \frac{1}{8}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.2.2

Factor $2$ out of $- 26$ .

$A = \frac{13}{4} + \frac{2 (- 13)}{3} \cdot \frac{1}{8}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.2.3

Factor $2$ out of $8$ .

$A = \frac{13}{4} + \frac{2 \cdot - 13}{3} \cdot \frac{1}{2 \cdot 4}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.2.4

Cancel the common factor.

$A = \frac{13}{4} + \frac{2 \cdot - 13}{3} \cdot \frac{1}{2 \cdot 4}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.2.5

Rewrite the expression.

$A = \frac{13}{4} + \frac{- 13}{3} \cdot \frac{1}{4}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} + \frac{- 13}{3} \cdot \frac{1}{4}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.3

Multiply $\frac{- 13}{3}$ by $\frac{1}{4}$ .

$A = \frac{13}{4} + \frac{- 13}{3 \cdot 4}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.4

Multiply $3$ by $4$ .

$A = \frac{13}{4} + \frac{- 13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.1.5

Move the negative in front of the fraction.

$A = \frac{13}{4} - \frac{13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{4} - \frac{13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.2

To write $\frac{13}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$A = \frac{13}{4} \cdot \frac{3}{3} - \frac{13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.3

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.6.2.1.3.1

Multiply $\frac{13}{4}$ by $\frac{3}{3}$ .

$A = \frac{13 \cdot 3}{4 \cdot 3} - \frac{13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.3.2

Multiply $4$ by $3$ .

$A = \frac{13 \cdot 3}{12} - \frac{13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13 \cdot 3}{12} - \frac{13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.4

Combine the numerators over the common denominator.

$A = \frac{13 \cdot 3 - 13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.5

Simplify the numerator.

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Step 3.6.2.1.5.1

Multiply $13$ by $3$ .

$A = \frac{39 - 13}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.5.2

Subtract $13$ from $39$ .

$A = \frac{26}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{26}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.6

Cancel the common factor of $26$ and $12$ .

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Step 3.6.2.1.6.1

Factor $2$ out of $26$ .

$A = \frac{2 (13)}{12}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.6.2

Cancel the common factors.

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Step 3.6.2.1.6.2.1

Factor $2$ out of $12$ .

$A = \frac{2 \cdot 13}{2 \cdot 6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.6.2.2

Cancel the common factor.

$A = \frac{2 \cdot 13}{2 \cdot 6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.2.1.6.2.3

Rewrite the expression.

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{9 C}{8}$

Step 3.6.3

Replace all occurrences of $C$ in $B = - \frac{13}{4} - \frac{9 C}{8}$ with $- \frac{26}{3}$ .

$B = - \frac{13}{4} - \frac{9 (- \frac{26}{3})}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4

Simplify the right side.

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Step 3.6.4.1

Simplify $- \frac{13}{4} - \frac{9 (- \frac{26}{3})}{8}$ .

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Step 3.6.4.1.1

Simplify each term.

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Step 3.6.4.1.1.1

Simplify the numerator.

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Step 3.6.4.1.1.1.1

Multiply $- 1$ by $9$ .

$B = - \frac{13}{4} - \frac{- 9 (\frac{26}{3})}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.1.2

Combine $- 9$ and $\frac{26}{3}$ .

$B = - \frac{13}{4} - \frac{\frac{- 9 \cdot 26}{3}}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{\frac{- 9 \cdot 26}{3}}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.2

Multiply $- 9$ by $26$ .

$B = - \frac{13}{4} - \frac{\frac{- 234}{3}}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.3

Divide $- 234$ by $3$ .

$B = - \frac{13}{4} - \frac{- 78}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.4

Cancel the common factor of $- 78$ and $8$ .

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Step 3.6.4.1.1.4.1

Factor $2$ out of $- 78$ .

$B = - \frac{13}{4} - \frac{2 (- 39)}{8}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.4.2

Cancel the common factors.

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Step 3.6.4.1.1.4.2.1

Factor $2$ out of $8$ .

$B = - \frac{13}{4} - \frac{2 \cdot - 39}{2 \cdot 4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.4.2.2

Cancel the common factor.

$B = - \frac{13}{4} - \frac{2 \cdot - 39}{2 \cdot 4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.4.2.3

Rewrite the expression.

$B = - \frac{13}{4} - \frac{- 39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{- 39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} - \frac{- 39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.5

Move the negative in front of the fraction.

$B = - \frac{13}{4} + \frac{39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.6

Multiply $- - \frac{39}{4}$ .

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Step 3.6.4.1.1.6.1

Multiply $- 1$ by $- 1$ .

$B = - \frac{13}{4} + 1 (\frac{39}{4})$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.1.6.2

Multiply $\frac{39}{4}$ by $1$ .

$B = - \frac{13}{4} + \frac{39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} + \frac{39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = - \frac{13}{4} + \frac{39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.2

Simplify terms.

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Step 3.6.4.1.2.1

Combine the numerators over the common denominator.

$B = \frac{- 13 + 39}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.2.2

Add $- 13$ and $39$ .

$B = \frac{26}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.2.3

Cancel the common factor of $26$ and $4$ .

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Step 3.6.4.1.2.3.1

Factor $2$ out of $26$ .

$B = \frac{2 (13)}{4}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.2.3.2

Cancel the common factors.

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Step 3.6.4.1.2.3.2.1

Factor $2$ out of $4$ .

$B = \frac{2 \cdot 13}{2 \cdot 2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.2.3.2.2

Cancel the common factor.

$B = \frac{2 \cdot 13}{2 \cdot 2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.6.4.1.2.3.2.3

Rewrite the expression.

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

$B = \frac{13}{2}$

$A = \frac{13}{6}$

$C = - \frac{26}{3}$

Step 3.7

List all of the solutions.

$B = \frac{13}{2}, A = \frac{13}{6}, C = - \frac{26}{3}$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{x + 1} + \frac{B}{x - 3} + \frac{C}{x - 2}$ with the values found for $A$ , $B$ , and $C$ .

$\frac{\frac{13}{6}}{x + 1} + \frac{\frac{13}{2}}{x - 3} + \frac{- \frac{26}{3}}{x - 2}$