Precalculus Examples

Find the Sum of the Series 1+3+5+7+...+101
1+3+5+7++1011+3+5+7++101
Step 1
This is an arithmetic sequence since there is a common difference between each term. In this case, adding 22 to the previous term in the sequence gives the next term. In other words, an=a1+d(n-1)an=a1+d(n1).
Arithmetic Sequence: d=2d=2
Step 2
Use the formula for an arithmetic sequence an=a1+d(n-1)an=a1+d(n1) to find the number of terms, nn.
Tap for more steps...
Step 2.1
Substitute the values of the first term, last term, and difference between terms into the formula.
101=1+2(n-1)101=1+2(n1)
Step 2.2
Solve for nn.
Tap for more steps...
Step 2.2.1
Rewrite the equation as 1+2(n-1)=1011+2(n1)=101.
1+2(n-1)=1011+2(n1)=101
Step 2.2.2
Simplify 1+2(n-1)1+2(n1).
Tap for more steps...
Step 2.2.2.1
Simplify each term.
Tap for more steps...
Step 2.2.2.1.1
Apply the distributive property.
1+2n+2-1=1011+2n+21=101
Step 2.2.2.1.2
Multiply 22 by -11.
1+2n-2=1011+2n2=101
1+2n-2=1011+2n2=101
Step 2.2.2.2
Subtract 22 from 11.
2n-1=1012n1=101
2n-1=1012n1=101
Step 2.2.3
Move all terms not containing nn to the right side of the equation.
Tap for more steps...
Step 2.2.3.1
Add 11 to both sides of the equation.
2n=101+12n=101+1
Step 2.2.3.2
Add 101101 and 11.
2n=1022n=102
2n=1022n=102
Step 2.2.4
Divide each term in 2n=1022n=102 by 22 and simplify.
Tap for more steps...
Step 2.2.4.1
Divide each term in 2n=1022n=102 by 22.
2n2=10222n2=1022
Step 2.2.4.2
Simplify the left side.
Tap for more steps...
Step 2.2.4.2.1
Cancel the common factor of 22.
Tap for more steps...
Step 2.2.4.2.1.1
Cancel the common factor.
2n2=1022
Step 2.2.4.2.1.2
Divide n by 1.
n=1022
n=1022
n=1022
Step 2.2.4.3
Simplify the right side.
Tap for more steps...
Step 2.2.4.3.1
Divide 102 by 2.
n=51
n=51
n=51
n=51
n=51
Step 3
Use the formula for the sum of an arithmetic sequence Sn=n2(a1+an) to find the sum.
Tap for more steps...
Step 3.1
Substitute the values of the first term, last term, and the number of terms into the sum formula.
Sn=512(1+101)
Step 3.2
Simplify.
Tap for more steps...
Step 3.2.1
Add 1 and 101.
Sn=512102
Step 3.2.2
Cancel the common factor of 2.
Tap for more steps...
Step 3.2.2.1
Factor 2 out of 102.
Sn=512(2(51))
Step 3.2.2.2
Cancel the common factor.
Sn=512(251)
Step 3.2.2.3
Rewrite the expression.
Sn=5151
Sn=5151
Step 3.2.3
Multiply 51 by 51.
Sn=2601
Sn=2601
Sn=2601
 [x2  12  π  xdx ]