Precalculus Examples

$\frac{5 x^{2} - 4 x - 12}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

Factor the fraction.

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Step 1.1.1

Factor by grouping.

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Step 1.1.1.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 5 \cdot - 12 = - 60$ and whose sum is $b = - 4$ .

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Step 1.1.1.1.1

Factor $- 4$ out of $- 4 x$ .

$\frac{5 x^{2} - 4 (x) - 12}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1.1.1.1.2

Rewrite $- 4$ as $6$ plus $- 10$

$\frac{5 x^{2} + (6 - 10) x - 12}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1.1.1.1.3

Apply the distributive property.

$\frac{5 x^{2} + 6 x - 10 x - 12}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1.1.1.2

Factor out the greatest common factor from each group.

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Step 1.1.1.2.1

Group the first two terms and the last two terms.

$\frac{(5 x^{2} + 6 x) - 10 x - 12}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1.1.1.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{x (5 x + 6) - 2 (5 x + 6)}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1.1.1.3

Factor the polynomial by factoring out the greatest common factor, $5 x + 6$ .

$\frac{(5 x + 6) (x - 2)}{2 x^{3} + 6 x^{2} + 4 x}$

Step 1.1.2

Factor $2 x$ out of $2 x^{3} + 6 x^{2} + 4 x$ .

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Step 1.1.2.1

Factor $2 x$ out of $2 x^{3}$ .

$\frac{(5 x + 6) (x - 2)}{2 x (x^{2}) + 6 x^{2} + 4 x}$

Step 1.1.2.2

Factor $2 x$ out of $6 x^{2}$ .

$\frac{(5 x + 6) (x - 2)}{2 x (x^{2}) + 2 x (3 x) + 4 x}$

Step 1.1.2.3

Factor $2 x$ out of $4 x$ .

$\frac{(5 x + 6) (x - 2)}{2 x (x^{2}) + 2 x (3 x) + 2 x (2)}$

Step 1.1.2.4

Factor $2 x$ out of $2 x (x^{2}) + 2 x (3 x)$ .

$\frac{(5 x + 6) (x - 2)}{2 x (x^{2} + 3 x) + 2 x (2)}$

Step 1.1.2.5

Factor $2 x$ out of $2 x (x^{2} + 3 x) + 2 x (2)$ .

$\frac{(5 x + 6) (x - 2)}{2 x (x^{2} + 3 x + 2)}$

Step 1.1.3

Factor.

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Step 1.1.3.1

Factor $x^{2} + 3 x + 2$ using the AC method.

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Step 1.1.3.1.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $2$ and whose sum is $3$ .

$1, 2$

Step 1.1.3.1.2

Write the factored form using these integers.

$\frac{(5 x + 6) (x - 2)}{2 x ((x + 1) (x + 2))}$

Step 1.1.3.2

Remove unnecessary parentheses.

$\frac{(5 x + 6) (x - 2)}{2 x (x + 1) (x + 2)}$

Step 1.2

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $B$ .

$\frac{A}{x} + \frac{B}{x + 1}$

Step 1.3

$\frac{A}{x} + \frac{B}{x + 1} + \frac{C}{x + 2}$

Step 1.4

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $2 x (x + 1) (x + 2)$ .

$\frac{(5 x + 6) (x - 2) (2 x (x + 1) (x + 2))}{2 x (x + 1) (x + 2)} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5

Reduce the expression by cancelling the common factors.

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Step 1.5.1

Cancel the common factor of $2$ .

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Step 1.5.1.1

Cancel the common factor.

$\frac{(5 x + 6) (x - 2) (2 x (x + 1) (x + 2))}{2 x (x + 1) (x + 2)} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.1.2

Rewrite the expression.

$\frac{(5 x + 6) (x - 2) ((x (x + 1)) (x + 2))}{(x (x + 1)) (x + 2)} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.2

Cancel the common factor of $x$ .

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Step 1.5.2.1

Cancel the common factor.

$\frac{(5 x + 6) (x - 2) (x (x + 1) (x + 2))}{x (x + 1) (x + 2)} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.2.2

Rewrite the expression.

$\frac{(5 x + 6) (x - 2) ((x + 1) (x + 2))}{(x + 1) (x + 2)} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.3

Cancel the common factor of $x + 1$ .

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Step 1.5.3.1

Cancel the common factor.

$\frac{(5 x + 6) (x - 2) ((x + 1) (x + 2))}{(x + 1) (x + 2)} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.3.2

Rewrite the expression.

$\frac{(5 x + 6) (x - 2) (x + 2)}{x + 2} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.4

Cancel the common factor of $x + 2$ .

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Step 1.5.4.1

Cancel the common factor.

$\frac{(5 x + 6) (x - 2) (x + 2)}{x + 2} = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.5.4.2

Divide $(5 x + 6) (x - 2)$ by $1$ .

$(5 x + 6) (x - 2) = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.6

Expand $(5 x + 6) (x - 2)$ using the FOIL Method.

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Step 1.6.1

Apply the distributive property.

$5 x (x - 2) + 6 (x - 2) = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.6.2

Apply the distributive property.

$5 x \cdot x + 5 x \cdot - 2 + 6 (x - 2) = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.6.3

Apply the distributive property.

$5 x \cdot x + 5 x \cdot - 2 + 6 x + 6 \cdot - 2 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.7

Simplify and combine like terms.

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Step 1.7.1

Simplify each term.

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Step 1.7.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.7.1.1.1

Move $x$ .

$5 (x \cdot x) + 5 x \cdot - 2 + 6 x + 6 \cdot - 2 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.7.1.1.2

Multiply $x$ by $x$ .

$5 x^{2} + 5 x \cdot - 2 + 6 x + 6 \cdot - 2 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.7.1.2

Multiply $- 2$ by $5$ .

$5 x^{2} - 10 x + 6 x + 6 \cdot - 2 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.7.1.3

Multiply $6$ by $- 2$ .

$5 x^{2} - 10 x + 6 x - 12 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.7.2

Add $- 10 x$ and $6 x$ .

$5 x^{2} - 4 x - 12 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8

Simplify each term.

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Step 1.8.1

Cancel the common factor of $x$ .

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Step 1.8.1.1

Cancel the common factor.

$5 x^{2} - 4 x - 12 = \frac{A (2 x (x + 1) (x + 2))}{x} + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.1.2

Divide $A ((2 (x + 1)) (x + 2))$ by $1$ .

$5 x^{2} - 4 x - 12 = A ((2 (x + 1)) (x + 2)) + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.2

Rewrite using the commutative property of multiplication.

$5 x^{2} - 4 x - 12 = 2 A (x + 1) (x + 2) + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.3

Apply the distributive property.

$5 x^{2} - 4 x - 12 = (2 A x + 2 A \cdot 1) (x + 2) + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.4

Multiply $2$ by $1$ .

$5 x^{2} - 4 x - 12 = (2 A x + 2 A) (x + 2) + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.5

Expand $(2 A x + 2 A) (x + 2)$ using the FOIL Method.

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Step 1.8.5.1

Apply the distributive property.

$5 x^{2} - 4 x - 12 = 2 A x (x + 2) + 2 A (x + 2) + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.5.2

Apply the distributive property.

$5 x^{2} - 4 x - 12 = 2 A x \cdot x + 2 A x \cdot 2 + 2 A (x + 2) + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.5.3

Apply the distributive property.

$5 x^{2} - 4 x - 12 = 2 A x \cdot x + 2 A x \cdot 2 + 2 A x + 2 A \cdot 2 + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.6

Simplify and combine like terms.

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Step 1.8.6.1

Simplify each term.

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Step 1.8.6.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.8.6.1.1.1

Move $x$ .

$5 x^{2} - 4 x - 12 = 2 A (x \cdot x) + 2 A x \cdot 2 + 2 A x + 2 A \cdot 2 + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.6.1.1.2

Multiply $x$ by $x$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 2 A x \cdot 2 + 2 A x + 2 A \cdot 2 + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.6.1.2

Multiply $2$ by $2$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 4 A x + 2 A x + 2 A \cdot 2 + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.6.1.3

Multiply $2$ by $2$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 4 A x + 2 A x + 4 A + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.6.2

Add $4 A x$ and $2 A x$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + \frac{(B) (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.7

Cancel the common factor of $x + 1$ .

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Step 1.8.7.1

Cancel the common factor.

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + \frac{B (2 x (x + 1) (x + 2))}{x + 1} + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.7.2

Divide $(B) (2 x (x + 2))$ by $1$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + (B) (2 x (x + 2)) + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.8

Rewrite using the commutative property of multiplication.

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x (x + 2) + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.9

Apply the distributive property.

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x \cdot x + 2 B x \cdot 2 + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.10

Multiply $x$ by $x$ by adding the exponents.

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Step 1.8.10.1

Move $x$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B (x \cdot x) + 2 B x \cdot 2 + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.10.2

Multiply $x$ by $x$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 2 B x \cdot 2 + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.11

Multiply $2$ by $2$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + \frac{(C) (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.12

Cancel the common factor of $x + 2$ .

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Step 1.8.12.1

Cancel the common factor.

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + \frac{C (2 x (x + 1) (x + 2))}{x + 2}$

Step 1.8.12.2

Divide $(C) (2 x (x + 1))$ by $1$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + (C) (2 x (x + 1))$

Step 1.8.13

Rewrite using the commutative property of multiplication.

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + 2 C x (x + 1)$

Step 1.8.14

Apply the distributive property.

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + 2 C x \cdot x + 2 C x \cdot 1$

Step 1.8.15

Multiply $x$ by $x$ by adding the exponents.

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Step 1.8.15.1

Move $x$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + 2 C (x \cdot x) + 2 C x \cdot 1$

Step 1.8.15.2

Multiply $x$ by $x$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + 2 C x^{2} + 2 C x \cdot 1$

Step 1.8.16

Multiply $2$ by $1$ .

$5 x^{2} - 4 x - 12 = 2 A x^{2} + 6 A x + 4 A + 2 B x^{2} + 4 B x + 2 C x^{2} + 2 C x$

Step 1.9

Reorder.

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Step 1.9.1

Move $A$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 6 A x + 4 A + 2 B x^{2} + 4 B x + 2 C x^{2} + 2 C x$

Step 1.9.2

Move $A$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 6 x A + 4 A + 2 B x^{2} + 4 B x + 2 C x^{2} + 2 C x$

Step 1.9.3

Move $B$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 6 x A + 4 A + 2 x^{2} B + 4 B x + 2 C x^{2} + 2 C x$

Step 1.9.4

Move $B$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 6 x A + 4 A + 2 x^{2} B + 4 x B + 2 C x^{2} + 2 C x$

Step 1.9.5

Move $4 A$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 6 x A + 2 x^{2} B + 4 x B + 2 C x^{2} + 2 C x + 4 A$

Step 1.9.6

Move $4 x B$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 6 x A + 2 x^{2} B + 2 C x^{2} + 4 x B + 2 C x + 4 A$

Step 1.9.7

Move $6 x A$ .

$5 x^{2} - 4 x - 12 = 2 x^{2} A + 2 x^{2} B + 2 C x^{2} + 6 x A + 4 x B + 2 C x + 4 A$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$5 = 2 A + 2 B + 2 C$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$- 4 = 6 A + 4 B + 2 C$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$- 12 = 4 A$

Step 2.4

Set up the system of equations to find the coefficients of the partial fractions.

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$- 12 = 4 A$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$- 12 = 4 A$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $A$ in $- 12 = 4 A$ .

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Step 3.1.1

Rewrite the equation as $4 A = - 12$ .

$4 A = - 12$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

Step 3.1.2

Divide each term in $4 A = - 12$ by $4$ and simplify.

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Step 3.1.2.1

Divide each term in $4 A = - 12$ by $4$ .

$\frac{4 A}{4} = \frac{- 12}{4}$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

Step 3.1.2.2

Simplify the left side.

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Step 3.1.2.2.1

Cancel the common factor of $4$ .

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Step 3.1.2.2.1.1

Cancel the common factor.

$\frac{4 A}{4} = \frac{- 12}{4}$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

Step 3.1.2.2.1.2

Divide $A$ by $1$ .

$A = \frac{- 12}{4}$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$A = \frac{- 12}{4}$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$A = \frac{- 12}{4}$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

Step 3.1.2.3

Simplify the right side.

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Step 3.1.2.3.1

Divide $- 12$ by $4$ .

$A = - 3$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$A = - 3$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$A = - 3$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

$A = - 3$

$5 = 2 A + 2 B + 2 C$

$- 4 = 6 A + 4 B + 2 C$

Step 3.2

Replace all occurrences of $A$ with $- 3$ in each equation.

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Step 3.2.1

Replace all occurrences of $A$ in $5 = 2 A + 2 B + 2 C$ with $- 3$ .

$5 = 2 (- 3) + 2 B + 2 C$

$A = - 3$

$- 4 = 6 A + 4 B + 2 C$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Multiply $2$ by $- 3$ .

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$- 4 = 6 A + 4 B + 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$- 4 = 6 A + 4 B + 2 C$

Step 3.2.3

Replace all occurrences of $A$ in $- 4 = 6 A + 4 B + 2 C$ with $- 3$ .

$- 4 = 6 (- 3) + 4 B + 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.2.4

Simplify the right side.

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Step 3.2.4.1

Multiply $6$ by $- 3$ .

$- 4 = - 18 + 4 B + 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$- 4 = - 18 + 4 B + 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$- 4 = - 18 + 4 B + 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3

Solve for $B$ in $- 4 = - 18 + 4 B + 2 C$ .

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Step 3.3.1

Rewrite the equation as $- 18 + 4 B + 2 C = - 4$ .

$- 18 + 4 B + 2 C = - 4$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.2

Move all terms not containing $B$ to the right side of the equation.

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Step 3.3.2.1

Add $18$ to both sides of the equation.

$4 B + 2 C = - 4 + 18$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.2.2

Subtract $2 C$ from both sides of the equation.

$4 B = - 4 + 18 - 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.2.3

Add $- 4$ and $18$ .

$4 B = 14 - 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$4 B = 14 - 2 C$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3

Divide each term in $4 B = 14 - 2 C$ by $4$ and simplify.

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Step 3.3.3.1

Divide each term in $4 B = 14 - 2 C$ by $4$ .

$\frac{4 B}{4} = \frac{14}{4} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.2

Simplify the left side.

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Step 3.3.3.2.1

Cancel the common factor of $4$ .

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Step 3.3.3.2.1.1

Cancel the common factor.

$\frac{4 B}{4} = \frac{14}{4} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.2.1.2

Divide $B$ by $1$ .

$B = \frac{14}{4} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{14}{4} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{14}{4} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3

Simplify the right side.

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Step 3.3.3.3.1

Simplify each term.

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Step 3.3.3.3.1.1

Cancel the common factor of $14$ and $4$ .

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Step 3.3.3.3.1.1.1

Factor $2$ out of $14$ .

$B = \frac{2 (7)}{4} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.1.2

Cancel the common factors.

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Step 3.3.3.3.1.1.2.1

Factor $2$ out of $4$ .

$B = \frac{2 \cdot 7}{2 \cdot 2} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.1.2.2

Cancel the common factor.

$B = \frac{2 \cdot 7}{2 \cdot 2} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.1.2.3

Rewrite the expression.

$B = \frac{7}{2} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} + \frac{- 2 C}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.2

Cancel the common factor of $- 2$ and $4$ .

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Step 3.3.3.3.1.2.1

Factor $2$ out of $- 2 C$ .

$B = \frac{7}{2} + \frac{2 (- C)}{4}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.2.2

Cancel the common factors.

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Step 3.3.3.3.1.2.2.1

Factor $2$ out of $4$ .

$B = \frac{7}{2} + \frac{2 (- C)}{2 (2)}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.2.2.2

Cancel the common factor.

$B = \frac{7}{2} + \frac{2 (- C)}{2 \cdot 2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.2.2.3

Rewrite the expression.

$B = \frac{7}{2} + \frac{- C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} + \frac{- C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} + \frac{- C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.3.3.3.1.3

Move the negative in front of the fraction.

$B = \frac{7}{2} - \frac{C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} - \frac{C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} - \frac{C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} - \frac{C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

$B = \frac{7}{2} - \frac{C}{2}$

$5 = - 6 + 2 B + 2 C$

$A = - 3$

Step 3.4

Replace all occurrences of $B$ with $\frac{7}{2} - \frac{C}{2}$ in each equation.

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Step 3.4.1

Replace all occurrences of $B$ in $5 = - 6 + 2 B + 2 C$ with $\frac{7}{2} - \frac{C}{2}$ .

$5 = - 6 + 2 (\frac{7}{2} - \frac{C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $- 6 + 2 (\frac{7}{2} - \frac{C}{2}) + 2 C$ .

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Step 3.4.2.1.1

Simplify each term.

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Step 3.4.2.1.1.1

Apply the distributive property.

$5 = - 6 + 2 (\frac{7}{2}) + 2 (- \frac{C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.1.2

Cancel the common factor of $2$ .

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Step 3.4.2.1.1.2.1

Cancel the common factor.

$5 = - 6 + 2 (\frac{7}{2}) + 2 (- \frac{C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.1.2.2

Rewrite the expression.

$5 = - 6 + 7 + 2 (- \frac{C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = - 6 + 7 + 2 (- \frac{C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.1.3

Cancel the common factor of $2$ .

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Step 3.4.2.1.1.3.1

Move the leading negative in $- \frac{C}{2}$ into the numerator.

$5 = - 6 + 7 + 2 (\frac{- C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.1.3.2

Cancel the common factor.

$5 = - 6 + 7 + 2 (\frac{- C}{2}) + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.1.3.3

Rewrite the expression.

$5 = - 6 + 7 - C + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = - 6 + 7 - C + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = - 6 + 7 - C + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.2

Simplify by adding terms.

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Step 3.4.2.1.2.1

Add $- 6$ and $7$ .

$5 = 1 - C + 2 C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.4.2.1.2.2

Add $- C$ and $2 C$ .

$5 = 1 + C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = 1 + C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = 1 + C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = 1 + C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$5 = 1 + C$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.5

Solve for $C$ in $5 = 1 + C$ .

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Step 3.5.1

Rewrite the equation as $1 + C = 5$ .

$1 + C = 5$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.5.2

Move all terms not containing $C$ to the right side of the equation.

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Step 3.5.2.1

Subtract $1$ from both sides of the equation.

$C = 5 - 1$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.5.2.2

Subtract $1$ from $5$ .

$C = 4$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$C = 4$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

$C = 4$

$B = \frac{7}{2} - \frac{C}{2}$

$A = - 3$

Step 3.6

Replace all occurrences of $C$ with $4$ in each equation.

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Step 3.6.1

Replace all occurrences of $C$ in $B = \frac{7}{2} - \frac{C}{2}$ with $4$ .

$B = \frac{7}{2} - \frac{4}{2}$

$C = 4$

$A = - 3$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $\frac{7}{2} - \frac{4}{2}$ .

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Step 3.6.2.1.1

Combine the numerators over the common denominator.

$B = \frac{7 - 4}{2}$

$C = 4$

$A = - 3$

Step 3.6.2.1.2

Subtract $4$ from $7$ .

$B = \frac{3}{2}$

$C = 4$

$A = - 3$

$B = \frac{3}{2}$

$C = 4$

$A = - 3$

$B = \frac{3}{2}$

$C = 4$

$A = - 3$

$B = \frac{3}{2}$

$C = 4$

$A = - 3$

Step 3.7

List all of the solutions.

$B = \frac{3}{2}, C = 4, A = - 3$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{x} + \frac{B}{x + 1} + \frac{C}{x + 2}$ with the values found for $A$ , $B$ , and $C$ .

$- \frac{3}{x} + \frac{\frac{3}{2}}{x + 1} + \frac{4}{x + 2}$