Precalculus Examples

$\frac{x - 2}{x {(x^{2} - 4 x + 5)}^{2}}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor is 2nd order, $2$ terms are required in the numerator. The number of terms required in the numerator is always equal to the order of the factor in the denominator.

$\frac{A}{x} + \frac{B x + C}{{(x^{2} - 4 x + 5)}^{2}}$

Step 1.2

$\frac{A}{x} + \frac{B x + C}{{(x^{2} - 4 x + 5)}^{2}} + \frac{D x + F}{x^{2} - 4 x + 5}$

Step 1.3

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $x {(x^{2} - 4 x + 5)}^{2}$ .

$\frac{(x - 2) (x {(x^{2} - 4 x + 5)}^{2})}{x {(x^{2} - 4 x + 5)}^{2}} = \frac{A (x {(x^{2} - 4 x + 5)}^{2})}{x} + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.4

Cancel the common factor of $x$ .

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Step 1.4.1

Cancel the common factor.

Step 1.4.2

Rewrite the expression.

$\frac{(x - 2) ({(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} = \frac{A (x {(x^{2} - 4 x + 5)}^{2})}{x} + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.5

Cancel the common factor of ${(x^{2} - 4 x + 5)}^{2}$ .

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Step 1.5.1

Cancel the common factor.

$\frac{(x - 2) {(x^{2} - 4 x + 5)}^{2}}{{(x^{2} - 4 x + 5)}^{2}} = \frac{A (x {(x^{2} - 4 x + 5)}^{2})}{x} + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.5.2

Divide $x - 2$ by $1$ .

$x - 2 = \frac{A (x {(x^{2} - 4 x + 5)}^{2})}{x} + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6

Simplify each term.

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Step 1.6.1

Cancel the common factor of $x$ .

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Step 1.6.1.1

Cancel the common factor.

$x - 2 = \frac{A (x {(x^{2} - 4 x + 5)}^{2})}{x} + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.1.2

Divide $A ({(x^{2} - 4 x + 5)}^{2})$ by $1$ .

$x - 2 = A ({(x^{2} - 4 x + 5)}^{2}) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.2

Rewrite ${(x^{2} - 4 x + 5)}^{2}$ as $(x^{2} - 4 x + 5) (x^{2} - 4 x + 5)$ .

$x - 2 = A ((x^{2} - 4 x + 5) (x^{2} - 4 x + 5)) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.3

Expand $(x^{2} - 4 x + 5) (x^{2} - 4 x + 5)$ by multiplying each term in the first expression by each term in the second expression.

$x - 2 = A (x^{2} x^{2} + x^{2} (- 4 x) + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4

Simplify each term.

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Step 1.6.4.1

Multiply $x^{2}$ by $x^{2}$ by adding the exponents.

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Step 1.6.4.1.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 2 = A (x^{2 + 2} + x^{2} (- 4 x) + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.1.2

Add $2$ and $2$ .

$x - 2 = A (x^{4} + x^{2} (- 4 x) + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.2

Rewrite using the commutative property of multiplication.

$x - 2 = A (x^{4} - 4 x^{2} x + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.3

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.6.4.3.1

Move $x$ .

$x - 2 = A (x^{4} - 4 (x \cdot x^{2}) + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.3.2

Multiply $x$ by $x^{2}$ .

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Step 1.6.4.3.2.1

Raise $x$ to the power of $1$ .

Step 1.6.4.3.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 2 = A (x^{4} - 4 x^{1 + 2} + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.3.3

Add $1$ and $2$ .

$x - 2 = A (x^{4} - 4 x^{3} + x^{2} \cdot 5 - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.4

Move $5$ to the left of $x^{2}$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 \cdot x^{2} - 4 x \cdot x^{2} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.5

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 1.6.4.5.1

Move $x^{2}$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 (x^{2} x) - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.5.2

Multiply $x^{2}$ by $x$ .

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Step 1.6.4.5.2.1

Raise $x$ to the power of $1$ .

Step 1.6.4.5.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{2 + 1} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.5.3

Add $2$ and $1$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} - 4 x (- 4 x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.6

Rewrite using the commutative property of multiplication.

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} - 4 \cdot (- 4 x \cdot x) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.7

Multiply $x$ by $x$ by adding the exponents.

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Step 1.6.4.7.1

Move $x$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} - 4 \cdot (- 4 (x \cdot x)) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.7.2

Multiply $x$ by $x$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} - 4 \cdot (- 4 x^{2}) - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.8

Multiply $- 4$ by $- 4$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} + 16 x^{2} - 4 x \cdot 5 + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.9

Multiply $5$ by $- 4$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} + 16 x^{2} - 20 x + 5 x^{2} + 5 (- 4 x) + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.10

Multiply $- 4$ by $5$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} + 16 x^{2} - 20 x + 5 x^{2} - 20 x + 5 \cdot 5) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.4.11

Multiply $5$ by $5$ .

$x - 2 = A (x^{4} - 4 x^{3} + 5 x^{2} - 4 x^{3} + 16 x^{2} - 20 x + 5 x^{2} - 20 x + 25) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.5

Subtract $4 x^{3}$ from $- 4 x^{3}$ .

$x - 2 = A (x^{4} - 8 x^{3} + 5 x^{2} + 16 x^{2} - 20 x + 5 x^{2} - 20 x + 25) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.6

Add $5 x^{2}$ and $16 x^{2}$ .

$x - 2 = A (x^{4} - 8 x^{3} + 21 x^{2} - 20 x + 5 x^{2} - 20 x + 25) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.7

Add $21 x^{2}$ and $5 x^{2}$ .

$x - 2 = A (x^{4} - 8 x^{3} + 26 x^{2} - 20 x - 20 x + 25) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.8

Subtract $20 x$ from $- 20 x$ .

$x - 2 = A (x^{4} - 8 x^{3} + 26 x^{2} - 40 x + 25) + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.9

Apply the distributive property.

$x - 2 = A x^{4} + A (- 8 x^{3}) + A (26 x^{2}) + A (- 40 x) + A \cdot 25 + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.10

Simplify.

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Step 1.6.10.1

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + A (26 x^{2}) + A (- 40 x) + A \cdot 25 + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.10.2

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} + A (- 40 x) + A \cdot 25 + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.10.3

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + A \cdot 25 + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.10.4

Move $25$ to the left of $A$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 \cdot A + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.11

Cancel the common factor of ${(x^{2} - 4 x + 5)}^{2}$ .

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Step 1.6.11.1

Cancel the common factor.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + \frac{(B x + C) (x {(x^{2} - 4 x + 5)}^{2})}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.11.2

Divide $(B x + C) (x)$ by $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + (B x + C) (x) + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.12

Apply the distributive property.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x \cdot x + C x + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.13

Multiply $x$ by $x$ by adding the exponents.

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Step 1.6.13.1

Move $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B (x \cdot x) + C x + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.13.2

Multiply $x$ by $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + \frac{(D x + F) (x {(x^{2} - 4 x + 5)}^{2})}{x^{2} - 4 x + 5}$

Step 1.6.14

Cancel the common factor of ${(x^{2} - 4 x + 5)}^{2}$ and $x^{2} - 4 x + 5$ .

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Step 1.6.14.1

Factor $x^{2} - 4 x + 5$ out of $(D x + F) (x {(x^{2} - 4 x + 5)}^{2})$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + \frac{(x^{2} - 4 x + 5) ((D x + F) (x (x^{2} - 4 x + 5)))}{x^{2} - 4 x + 5}$

Step 1.6.14.2

Cancel the common factors.

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Step 1.6.14.2.1

Multiply by $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + \frac{(x^{2} - 4 x + 5) ((D x + F) (x (x^{2} - 4 x + 5)))}{(x^{2} - 4 x + 5) \cdot 1}$

Step 1.6.14.2.2

Cancel the common factor.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + \frac{(x^{2} - 4 x + 5) ((D x + F) (x (x^{2} - 4 x + 5)))}{(x^{2} - 4 x + 5) \cdot 1}$

Step 1.6.14.2.3

Rewrite the expression.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + \frac{(D x + F) (x (x^{2} - 4 x + 5))}{1}$

Step 1.6.14.2.4

Divide $(D x + F) (x (x^{2} - 4 x + 5))$ by $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x (x^{2} - 4 x + 5))$

Step 1.6.15

Apply the distributive property.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x \cdot x^{2} + x (- 4 x) + x \cdot 5)$

Step 1.6.16

Simplify.

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Step 1.6.16.1

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 1.6.16.1.1

Multiply $x$ by $x^{2}$ .

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Step 1.6.16.1.1.1

Raise $x$ to the power of $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x \cdot x^{2} + x (- 4 x) + x \cdot 5)$

Step 1.6.16.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{1 + 2} + x (- 4 x) + x \cdot 5)$

Step 1.6.16.1.2

Add $1$ and $2$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{3} + x (- 4 x) + x \cdot 5)$

Step 1.6.16.2

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{3} - 4 x \cdot x + x \cdot 5)$

Step 1.6.16.3

Move $5$ to the left of $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{3} - 4 x \cdot x + 5 \cdot x)$

Step 1.6.17

Multiply $x$ by $x$ by adding the exponents.

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Step 1.6.17.1

Move $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{3} - 4 (x \cdot x) + 5 \cdot x)$

Step 1.6.17.2

Multiply $x$ by $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{3} - 4 x^{2} + 5 \cdot x)$

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + (D x + F) (x^{3} - 4 x^{2} + 5 x)$

Step 1.6.18

Expand $(D x + F) (x^{3} - 4 x^{2} + 5 x)$ by multiplying each term in the first expression by each term in the second expression.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x \cdot x^{3} + D x (- 4 x^{2}) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19

Simplify each term.

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Step 1.6.19.1

Multiply $x$ by $x^{3}$ by adding the exponents.

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Step 1.6.19.1.1

Move $x^{3}$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D (x^{3} x) + D x (- 4 x^{2}) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.1.2

Multiply $x^{3}$ by $x$ .

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Step 1.6.19.1.2.1

Raise $x$ to the power of $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D (x^{3} x) + D x (- 4 x^{2}) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{3 + 1} + D x (- 4 x^{2}) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.1.3

Add $3$ and $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} + D x (- 4 x^{2}) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.2

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x \cdot x^{2} + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.3

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 1.6.19.3.1

Move $x^{2}$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D (x^{2} x) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.3.2

Multiply $x^{2}$ by $x$ .

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Step 1.6.19.3.2.1

Raise $x$ to the power of $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D (x^{2} x) + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.3.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{2 + 1} + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.3.3

Add $2$ and $1$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + D x (5 x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.4

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x \cdot x + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.5

Multiply $x$ by $x$ by adding the exponents.

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Step 1.6.19.5.1

Move $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D (x \cdot x) + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.5.2

Multiply $x$ by $x$ .

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} + F (- 4 x^{2}) + F (5 x)$

Step 1.6.19.6

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + F (5 x)$

Step 1.6.19.7

Rewrite using the commutative property of multiplication.

$x - 2 = A x^{4} - 8 A x^{3} + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + 5 F x$

Step 1.7

Simplify the expression.

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Step 1.7.1

Move $A$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 A x^{2} - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + 5 F x$

Step 1.7.2

Move $A$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 A x + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + 5 F x$

Step 1.7.3

Move $A$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + 5 F x$

Step 1.7.4

Reorder $B$ and $x^{2}$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + 5 F x$

Step 1.7.5

Reorder $F$ and $x^{3}$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 F x^{2} + 5 F x$

Step 1.7.6

Move $F$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 x^{2} F + 5 F x$

Step 1.7.7

Move $F$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + 25 A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 x^{2} F + 5 x F$

Step 1.7.8

Move $25 A$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + B x^{2} + C x + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 x^{2} F + 5 x F + 25 A$

Step 1.7.9

Move $C x$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A - 40 x A + B x^{2} + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 x^{2} F + C x + 5 x F + 25 A$

Step 1.7.10

Move $- 40 x A$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A + B x^{2} + D x^{4} - 4 D x^{3} + 5 D x^{2} + F x^{3} - 4 x^{2} F - 40 x A + C x + 5 x F + 25 A$

Step 1.7.11

Move $5 D x^{2}$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A + B x^{2} + D x^{4} - 4 D x^{3} + F x^{3} + 5 D x^{2} - 4 x^{2} F - 40 x A + C x + 5 x F + 25 A$

Step 1.7.12

Move $B x^{2}$ .

$x - 2 = A x^{4} - 8 x^{3} A + 26 x^{2} A + D x^{4} - 4 D x^{3} + F x^{3} + B x^{2} + 5 D x^{2} - 4 x^{2} F - 40 x A + C x + 5 x F + 25 A$

Step 1.7.13

Move $26 x^{2} A$ .

$x - 2 = A x^{4} - 8 x^{3} A + D x^{4} - 4 D x^{3} + F x^{3} + 26 x^{2} A + B x^{2} + 5 D x^{2} - 4 x^{2} F - 40 x A + C x + 5 x F + 25 A$

Step 1.7.14

Move $- 8 x^{3} A$ .

$x - 2 = A x^{4} + D x^{4} - 8 x^{3} A - 4 D x^{3} + F x^{3} + 26 x^{2} A + B x^{2} + 5 D x^{2} - 4 x^{2} F - 40 x A + C x + 5 x F + 25 A$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{4}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = A + D$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x^{3}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = - 8 A - 4 D + F$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = 26 A + B + 5 D - 4 F$

Step 2.4

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$1 = - 40 A + C + 5 F$

Step 2.5

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$- 2 = 25 A$

Step 2.6

Set up the system of equations to find the coefficients of the partial fractions.

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$- 2 = 25 A$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$- 2 = 25 A$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $A$ in $- 2 = 25 A$ .

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Step 3.1.1

Rewrite the equation as $25 A = - 2$ .

$25 A = - 2$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.1.2

Divide each term in $25 A = - 2$ by $25$ and simplify.

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Step 3.1.2.1

Divide each term in $25 A = - 2$ by $25$ .

$\frac{25 A}{25} = \frac{- 2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.1.2.2

Simplify the left side.

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Step 3.1.2.2.1

Cancel the common factor of $25$ .

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Step 3.1.2.2.1.1

Cancel the common factor.

$\frac{25 A}{25} = \frac{- 2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.1.2.2.1.2

Divide $A$ by $1$ .

$A = \frac{- 2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$A = \frac{- 2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$A = \frac{- 2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.1.2.3

Simplify the right side.

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Step 3.1.2.3.1

Move the negative in front of the fraction.

$A = - \frac{2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$A = - \frac{2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$A = - \frac{2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$A = - \frac{2}{25}$

$0 = A + D$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2

Replace all occurrences of $A$ with $- \frac{2}{25}$ in each equation.

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Step 3.2.1

Replace all occurrences of $A$ in $0 = A + D$ with $- \frac{2}{25}$ .

$0 = (- \frac{2}{25}) + D$

$A = - \frac{2}{25}$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Remove parentheses.

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = - 8 A - 4 D + F$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2.3

Replace all occurrences of $A$ in $0 = - 8 A - 4 D + F$ with $- \frac{2}{25}$ .

$0 = - 8 (- \frac{2}{25}) - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2.4

Simplify the right side.

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Step 3.2.4.1

Multiply $- 8 (- \frac{2}{25})$ .

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Step 3.2.4.1.1

Multiply $- 1$ by $- 8$ .

$0 = 8 (\frac{2}{25}) - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2.4.1.2

Combine $8$ and $\frac{2}{25}$ .

$0 = \frac{8 \cdot 2}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2.4.1.3

Multiply $8$ by $2$ .

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$0 = 26 A + B + 5 D - 4 F$

$1 = - 40 A + C + 5 F$

Step 3.2.5

Replace all occurrences of $A$ in $0 = 26 A + B + 5 D - 4 F$ with $- \frac{2}{25}$ .

$0 = 26 (- \frac{2}{25}) + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

Step 3.2.6

Simplify the right side.

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Step 3.2.6.1

Simplify each term.

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Step 3.2.6.1.1

Multiply $26 (- \frac{2}{25})$ .

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Step 3.2.6.1.1.1

Multiply $- 1$ by $26$ .

$0 = - 26 (\frac{2}{25}) + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

Step 3.2.6.1.1.2

Combine $- 26$ and $\frac{2}{25}$ .

$0 = \frac{- 26 \cdot 2}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

Step 3.2.6.1.1.3

Multiply $- 26$ by $2$ .

$0 = \frac{- 52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

$0 = \frac{- 52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

Step 3.2.6.1.2

Move the negative in front of the fraction.

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 40 A + C + 5 F$

Step 3.2.7

Replace all occurrences of $A$ in $1 = - 40 A + C + 5 F$ with $- \frac{2}{25}$ .

$1 = - 40 (- \frac{2}{25}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8

Simplify the right side.

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Step 3.2.8.1

Simplify each term.

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Step 3.2.8.1.1

Cancel the common factor of $5$ .

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Step 3.2.8.1.1.1

Move the leading negative in $- \frac{2}{25}$ into the numerator.

$1 = - 40 (\frac{- 2}{25}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8.1.1.2

Factor $5$ out of $- 40$ .

$1 = 5 (- 8) (\frac{- 2}{25}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8.1.1.3

Factor $5$ out of $25$ .

$1 = 5 \cdot (- 8 \frac{- 2}{5 \cdot 5}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8.1.1.4

Cancel the common factor.

$1 = 5 \cdot (- 8 \frac{- 2}{5 \cdot 5}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8.1.1.5

Rewrite the expression.

$1 = - 8 (\frac{- 2}{5}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = - 8 (\frac{- 2}{5}) + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8.1.2

Combine $- 8$ and $\frac{- 2}{5}$ .

$1 = \frac{- 8 \cdot - 2}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.2.8.1.3

Multiply $- 8$ by $- 2$ .

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$0 = - \frac{2}{25} + D$

$A = - \frac{2}{25}$

Step 3.3

Solve for $D$ in $0 = - \frac{2}{25} + D$ .

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Step 3.3.1

Rewrite the equation as $- \frac{2}{25} + D = 0$ .

$- \frac{2}{25} + D = 0$

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.3.2

Add $\frac{2}{25}$ to both sides of the equation.

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = - \frac{52}{25} + B + 5 D - 4 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4

Replace all occurrences of $D$ with $\frac{2}{25}$ in each equation.

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Step 3.4.1

Replace all occurrences of $D$ in $0 = - \frac{52}{25} + B + 5 D - 4 F$ with $\frac{2}{25}$ .

$0 = - \frac{52}{25} + B + 5 (\frac{2}{25}) - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $- \frac{52}{25} + B + 5 (\frac{2}{25}) - 4 F$ .

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Step 3.4.2.1.1

Cancel the common factor of $5$ .

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Step 3.4.2.1.1.1

Factor $5$ out of $25$ .

$0 = - \frac{52}{25} + B + 5 (\frac{2}{5 (5)}) - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.1.2

Cancel the common factor.

$0 = - \frac{52}{25} + B + 5 (\frac{2}{5 \cdot 5}) - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.1.3

Rewrite the expression.

$0 = - \frac{52}{25} + B + \frac{2}{5} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

$0 = - \frac{52}{25} + B + \frac{2}{5} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.2

To write $\frac{2}{5}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$0 = B - \frac{52}{25} + \frac{2}{5} \cdot \frac{5}{5} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.3

Write each expression with a common denominator of $25$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.4.2.1.3.1

Multiply $\frac{2}{5}$ by $\frac{5}{5}$ .

$0 = B - \frac{52}{25} + \frac{2 \cdot 5}{5 \cdot 5} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.3.2

Multiply $5$ by $5$ .

$0 = B - \frac{52}{25} + \frac{2 \cdot 5}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

$0 = B - \frac{52}{25} + \frac{2 \cdot 5}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.4

Combine the numerators over the common denominator.

$0 = B + \frac{- 52 + 2 \cdot 5}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.5

Simplify the numerator.

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Step 3.4.2.1.5.1

Multiply $2$ by $5$ .

$0 = B + \frac{- 52 + 10}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.5.2

Add $- 52$ and $10$ .

$0 = B + \frac{- 42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

$0 = B + \frac{- 42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.2.1.6

Move the negative in front of the fraction.

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$0 = \frac{16}{25} - 4 D + F$

$A = - \frac{2}{25}$

Step 3.4.3

Replace all occurrences of $D$ in $0 = \frac{16}{25} - 4 D + F$ with $\frac{2}{25}$ .

$0 = \frac{16}{25} - 4 (\frac{2}{25}) + F$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.4.4

Simplify the right side.

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Step 3.4.4.1

Simplify $\frac{16}{25} - 4 (\frac{2}{25}) + F$ .

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Step 3.4.4.1.1

Simplify each term.

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Step 3.4.4.1.1.1

Multiply $- 4 (\frac{2}{25})$ .

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Step 3.4.4.1.1.1.1

Combine $- 4$ and $\frac{2}{25}$ .

$0 = \frac{16}{25} + \frac{- 4 \cdot 2}{25} + F$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.4.4.1.1.1.2

Multiply $- 4$ by $2$ .

$0 = \frac{16}{25} + \frac{- 8}{25} + F$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = \frac{16}{25} + \frac{- 8}{25} + F$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.4.4.1.1.2

Move the negative in front of the fraction.

$0 = \frac{16}{25} - \frac{8}{25} + F$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = \frac{16}{25} - \frac{8}{25} + F$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.4.4.1.2

Combine fractions.

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Step 3.4.4.1.2.1

Combine the numerators over the common denominator.

$0 = F + \frac{16 - 8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.4.4.1.2.2

Subtract $8$ from $16$ .

$0 = F + \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = F + \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = F + \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = F + \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = F + \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.5

Solve for $F$ in $0 = F + \frac{8}{25}$ .

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Step 3.5.1

Rewrite the equation as $F + \frac{8}{25} = 0$ .

$F + \frac{8}{25} = 0$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.5.2

Subtract $\frac{8}{25}$ from both sides of the equation.

$F = - \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$F = - \frac{8}{25}$

$0 = B - \frac{42}{25} - 4 F$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6

Replace all occurrences of $F$ with $- \frac{8}{25}$ in each equation.

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Step 3.6.1

Replace all occurrences of $F$ in $0 = B - \frac{42}{25} - 4 F$ with $- \frac{8}{25}$ .

$0 = B - \frac{42}{25} - 4 (- \frac{8}{25})$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $B - \frac{42}{25} - 4 (- \frac{8}{25})$ .

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Step 3.6.2.1.1

Multiply $- 4 (- \frac{8}{25})$ .

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Step 3.6.2.1.1.1

Multiply $- 1$ by $- 4$ .

$0 = B - \frac{42}{25} + 4 (\frac{8}{25})$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.1.2

Combine $4$ and $\frac{8}{25}$ .

$0 = B - \frac{42}{25} + \frac{4 \cdot 8}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.1.3

Multiply $4$ by $8$ .

$0 = B - \frac{42}{25} + \frac{32}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B - \frac{42}{25} + \frac{32}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.2

Combine fractions.

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Step 3.6.2.1.2.1

Combine the numerators over the common denominator.

$0 = B + \frac{- 42 + 32}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.2.2

Add $- 42$ and $32$ .

$0 = B + \frac{- 10}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B + \frac{- 10}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.3

Simplify each term.

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Step 3.6.2.1.3.1

Cancel the common factor of $- 10$ and $25$ .

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Step 3.6.2.1.3.1.1

Factor $5$ out of $- 10$ .

$0 = B + \frac{5 (- 2)}{25}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.3.1.2

Cancel the common factors.

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Step 3.6.2.1.3.1.2.1

Factor $5$ out of $25$ .

$0 = B + \frac{5 \cdot - 2}{5 \cdot 5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.3.1.2.2

Cancel the common factor.

$0 = B + \frac{5 \cdot - 2}{5 \cdot 5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.3.1.2.3

Rewrite the expression.

$0 = B + \frac{- 2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B + \frac{- 2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B + \frac{- 2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.2.1.3.2

Move the negative in front of the fraction.

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$1 = \frac{16}{5} + C + 5 F$

$A = - \frac{2}{25}$

Step 3.6.3

Replace all occurrences of $F$ in $1 = \frac{16}{5} + C + 5 F$ with $- \frac{8}{25}$ .

$1 = \frac{16}{5} + C + 5 (- \frac{8}{25})$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4

Simplify the right side.

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Step 3.6.4.1

Simplify $\frac{16}{5} + C + 5 (- \frac{8}{25})$ .

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Step 3.6.4.1.1

Simplify each term.

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Step 3.6.4.1.1.1

Cancel the common factor of $5$ .

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Step 3.6.4.1.1.1.1

Move the leading negative in $- \frac{8}{25}$ into the numerator.

$1 = \frac{16}{5} + C + 5 (\frac{- 8}{25})$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4.1.1.1.2

Factor $5$ out of $25$ .

$1 = \frac{16}{5} + C + 5 (\frac{- 8}{5 (5)})$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4.1.1.1.3

Cancel the common factor.

$1 = \frac{16}{5} + C + 5 (\frac{- 8}{5 \cdot 5})$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4.1.1.1.4

Rewrite the expression.

$1 = \frac{16}{5} + C + \frac{- 8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$1 = \frac{16}{5} + C + \frac{- 8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4.1.1.2

Move the negative in front of the fraction.

$1 = \frac{16}{5} + C - \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$1 = \frac{16}{5} + C - \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4.1.2

Combine fractions.

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Step 3.6.4.1.2.1

Combine the numerators over the common denominator.

$1 = C + \frac{16 - 8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.6.4.1.2.2

Subtract $8$ from $16$ .

$1 = C + \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$1 = C + \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$1 = C + \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$1 = C + \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$1 = C + \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.7

Solve for $C$ in $1 = C + \frac{8}{5}$ .

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Step 3.7.1

Rewrite the equation as $C + \frac{8}{5} = 1$ .

$C + \frac{8}{5} = 1$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.7.2

Move all terms not containing $C$ to the right side of the equation.

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Step 3.7.2.1

Subtract $\frac{8}{5}$ from both sides of the equation.

$C = 1 - \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.7.2.2

Write $1$ as a fraction with a common denominator.

$C = \frac{5}{5} - \frac{8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.7.2.3

Combine the numerators over the common denominator.

$C = \frac{5 - 8}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.7.2.4

Subtract $8$ from $5$ .

$C = \frac{- 3}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.7.2.5

Move the negative in front of the fraction.

$C = - \frac{3}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$C = - \frac{3}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$C = - \frac{3}{5}$

$0 = B - \frac{2}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.8

Replace all occurrences of $C$ with $- \frac{3}{5}$ in each equation.

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Step 3.8.1

Rewrite the equation as $B - \frac{2}{5} = 0$ .

$B - \frac{2}{5} = 0$

$C = - \frac{3}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.8.2

Add $\frac{2}{5}$ to both sides of the equation.

$B = \frac{2}{5}$

$C = - \frac{3}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

$B = \frac{2}{5}$

$C = - \frac{3}{5}$

$F = - \frac{8}{25}$

$D = \frac{2}{25}$

$A = - \frac{2}{25}$

Step 3.9

List all of the solutions.

$B = \frac{2}{5}, C = - \frac{3}{5}, F = - \frac{8}{25}, D = \frac{2}{25}, A = - \frac{2}{25}$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{x} + \frac{B x + C}{{(x^{2} - 4 x + 5)}^{2}} + \frac{D x + F}{x^{2} - 4 x + 5}$ with the values found for $A$ , $B$ , $C$ , $D$ , and $F$ .

$- \frac{\frac{2}{25}}{x} + \frac{\frac{2}{5 x} - \frac{3}{5}}{{(x^{2} - 4 x + 5)}^{2}} + \frac{\frac{2}{25 x} - \frac{8}{25}}{x^{2} - 4 x + 5}$

Step 5

Simplify.

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Step 5.1

Combine $\frac{2}{5}$ and $x$ .

$\frac{- \frac{2}{25}}{x} + \frac{\frac{2 x}{5} - \frac{3}{5}}{{(x^{2} - 4 x + 5)}^{2}} + \frac{(\frac{2}{25}) x - \frac{8}{25}}{x^{2} - 4 x + 5}$

Step 5.2

Combine $\frac{2}{25}$ and $x$ .

$\frac{- \frac{2}{25}}{x} + \frac{\frac{2 x}{5} - \frac{3}{5}}{{(x^{2} - 4 x + 5)}^{2}} + \frac{\frac{2 x}{25} - \frac{8}{25}}{x^{2} - 4 x + 5}$