Pre-Algebra Examples

$(1, 1)$ , $(0, - 2)$

Step 1

Find the value of the slope.

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Step 1.1

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

Step 1.2

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Step 1.3

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{- 2 - (1)}{0 - (1)}$

Step 1.4

Simplify.

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Step 1.4.1

Simplify the numerator.

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Step 1.4.1.1

Multiply $- 1$ by $1$ .

$m = \frac{- 2 - 1}{0 - (1)}$

Step 1.4.1.2

Subtract $1$ from $- 2$ .

$m = \frac{- 3}{0 - (1)}$

Step 1.4.2

Simplify the denominator.

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Step 1.4.2.1

Multiply $- 1$ by $1$ .

$m = \frac{- 3}{0 - 1}$

Step 1.4.2.2

Subtract $1$ from $0$ .

$m = \frac{- 3}{- 1}$

Step 1.4.3

Divide $- 3$ by $- 1$ .

$m = 3$

Step 2

Find the value of the y-intercept.

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Step 2.1

Substitute the value of $m$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (3) \cdot x + b$

Step 2.2

Substitute the value of $x$ into the slope-intercept form of the equation, $y = m x + b$ .

$y = (3) \cdot (1) + b$

Step 2.3

Substitute the value of $y$ into the slope-intercept form of the equation, $y = m x + b$ .

$1 = (3) \cdot (1) + b$

Step 2.4

Rewrite the equation as $(3) \cdot (1) + b = 1$ .

$(3) \cdot (1) + b = 1$

Step 2.5

Multiply $3$ by $1$ .

$3 + b = 1$

Step 2.6

Move all terms not containing $b$ to the right side of the equation.

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Step 2.6.1

Subtract $3$ from both sides of the equation.

$b = 1 - 3$

Step 2.6.2

Subtract $3$ from $1$ .

$b = - 2$

Step 3

List the slope and y-intercept.

Slope: $3$

y-intercept: $(0, - 2)$

Step 4