Pre-Algebra Examples

$| x | \leq 12$

Step 1

Write $| x | \leq 12$ as a piecewise.

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Step 1.1

To find the interval for the first piece, find where the inside of the absolute value is non-negative.

$x \geq 0$

Step 1.2

In the piece where $x$ is non-negative, remove the absolute value.

$x \leq 12$

Step 1.3

To find the interval for the second piece, find where the inside of the absolute value is negative.

$x < 0$

Step 1.4

In the piece where $x$ is negative, remove the absolute value and multiply by $- 1$ .

$- x \leq 12$

Step 1.5

Write as a piecewise.

${\begin{cases} x \leq 12 & x \geq 0 \\ - x \leq 12 & x < 0 \end{cases}$

Step 2

Find the intersection of $x \leq 12$ and $x \geq 0$ .

$0 \leq x \leq 12$

Step 3

Solve $- x \leq 12$ when $x < 0$ .

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Step 3.1

Divide each term in $- x \leq 12$ by $- 1$ and simplify.

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Step 3.1.1

Divide each term in $- x \leq 12$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} \geq \frac{12}{- 1}$

Step 3.1.2

Simplify the left side.

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Step 3.1.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} \geq \frac{12}{- 1}$

Step 3.1.2.2

Divide $x$ by $1$ .

$x \geq \frac{12}{- 1}$

Step 3.1.3

Simplify the right side.

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Step 3.1.3.1

Divide $12$ by $- 1$ .

$x \geq - 12$

Step 3.2

Find the intersection of $x \geq - 12$ and $x < 0$ .

$- 12 \leq x < 0$

Step 4

Find the union of the solutions.

$- 12 \leq x \leq 12$

Step 5

The result can be shown in multiple forms.

Inequality Form:

$- 12 \leq x \leq 12$

Interval Notation:

$[- 12, 12]$

Step 6