Pre-Algebra Examples

 $\begin{array}{r} h = & L \\ r = & H \end{array}$

Step 1

The surface area of a cylinder is equal to the sum of the areas of the bases each having an area of $π \cdot r^{2}$ , plus the area of the side. The area of the side is equal to the area of a rectangle with length $2 π r$ (the circumference of the base) times the height.

$2 π \cdot {(r a d i u s)}^{2} + 2 π \cdot (r a d i u s) \cdot (h e i g h t)$

Step 2

Substitute the values of the radius $r = H$ and height $h = L$ into the formula. Pi $π$ is approximately equal to $3.14$ .

$2 (π) {(H)}^{2} + 2 (π) (H) (L)$

Step 3

Multiply $2$ by $π$ .

$2 π H^{2} + 2 π H L$