Pre-Algebra Examples

 $\begin{array}{r} h = & 8 cm \\ r = & 5 cm \end{array}$

Step 1

The surface area of a cone is equal to the area of the base plus the area of the cone.

$(π \cdot (r a d i u s)) \cdot ((r a d i u s) + \sqrt{{(r a d i u s)}^{2} + {(h e i g h t)}^{2}})$

Step 2

Substitute the values of the length $r = 5$ and height $h = 8$ into the formula. Pi $π$ is approximately equal to $3.14$ .

$(π \cdot 5) (5 + \sqrt{{(5)}^{2} + {(8)}^{2}})$

Step 3

Move $5$ to the left of $π$ .

$5 \cdot π (5 + \sqrt{{(5)}^{2} + {(8)}^{2}})$

Step 4

Simplify each term.

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Step 4.1

Raise $5$ to the power of $2$ .

$5 π (5 + \sqrt{25 + {(8)}^{2}})$

Step 4.2

Raise $8$ to the power of $2$ .

$5 π (5 + \sqrt{25 + 64})$

Step 4.3

Add $25$ and $64$ .

$5 π (5 + \sqrt{89})$

Step 5

Simplify by multiplying through.

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Step 5.1

Apply the distributive property.

$5 π \cdot 5 + 5 π \sqrt{89}$

Step 5.2

Multiply $5$ by $5$ .

$25 π + 5 π \sqrt{89}$

$25 π + 5 π \sqrt{89} {(cm)}^{2}$