Pre-Algebra Examples

 $\begin{array}{r} h = & \frac{21}{9} \\ l = & \frac{15}{9} \\ w = & \frac{21}{6} \end{array}$

Step 1

The surface area of a pyramid is equal to the sum of the areas of each side of the pyramid. The base of the pyramid has area $l w$ , and $s_{l}$ and $s_{w}$ represent the slant height on the length and slant height on the width.

$(l e n g t h) \cdot (w i d t h) + (w i d t h) \cdot s_{l} + (l e n g t h) \cdot s_{w}$

Step 2

Substitute the values of the length $l = \frac{15}{9}$ , the width $w = \frac{21}{6}$ , and the height $h = \frac{21}{9}$ into the formula for surface area of a pyramid.

$\frac{15}{9} \cdot \frac{21}{6} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3

Simplify each term.

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Step 3.1

Cancel the common factor of $3$ .

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Step 3.1.1

Factor $3$ out of $15$ .

$\frac{3 (5)}{9} \cdot \frac{21}{6} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.1.2

Factor $3$ out of $6$ .

$\frac{3 \cdot 5}{9} \cdot \frac{21}{3 \cdot 2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.1.3

Cancel the common factor.

Step 3.1.4

Rewrite the expression.

$\frac{5}{9} \cdot \frac{21}{2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.2

Cancel the common factor of $3$ .

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Step 3.2.1

Factor $3$ out of $9$ .

$\frac{5}{3 (3)} \cdot \frac{21}{2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.2.2

Factor $3$ out of $21$ .

$\frac{5}{3 \cdot 3} \cdot \frac{3 \cdot 7}{2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.2.3

Cancel the common factor.

Step 3.2.4

Rewrite the expression.

$\frac{5}{3} \cdot \frac{7}{2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.3

Multiply $\frac{5}{3}$ by $\frac{7}{2}$ .

$\frac{5 \cdot 7}{3 \cdot 2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.4

Multiply $5$ by $7$ .

$\frac{35}{3 \cdot 2} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.5

Multiply $3$ by $2$ .

$\frac{35}{6} + \frac{21}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.6

Cancel the common factor of $21$ and $6$ .

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Step 3.6.1

Factor $3$ out of $21$ .

$\frac{35}{6} + \frac{3 (7)}{6} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.6.2

Cancel the common factors.

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Step 3.6.2.1

Factor $3$ out of $6$ .

$\frac{35}{6} + \frac{3 \cdot 7}{3 \cdot 2} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.6.2.2

Cancel the common factor.

$\frac{35}{6} + \frac{3 \cdot 7}{3 \cdot 2} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.6.2.3

Rewrite the expression.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{\frac{15}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.7

Cancel the common factor of $15$ and $9$ .

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Step 3.7.1

Factor $3$ out of $15$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{\frac{3 (5)}{9}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.7.2

Cancel the common factors.

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Step 3.7.2.1

Factor $3$ out of $9$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{\frac{3 \cdot 5}{3 \cdot 3}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.7.2.2

Cancel the common factor.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{\frac{3 \cdot 5}{3 \cdot 3}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.7.2.3

Rewrite the expression.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{\frac{5}{3}}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.8

Multiply the numerator by the reciprocal of the denominator.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{5}{3} \cdot \frac{1}{2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.9

Multiply $\frac{5}{3} \cdot \frac{1}{2}$ .

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Step 3.9.1

Multiply $\frac{5}{3}$ by $\frac{1}{2}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{5}{3 \cdot 2})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.9.2

Multiply $3$ by $2$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{{(\frac{5}{6})}^{2} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.10

Apply the product rule to $\frac{5}{6}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{5^{2}}{6^{2}} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.11

Raise $5$ to the power of $2$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{6^{2}} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.12

Raise $6$ to the power of $2$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + {(\frac{21}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.13

Cancel the common factor of $21$ and $9$ .

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Step 3.13.1

Factor $3$ out of $21$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + {(\frac{3 (7)}{9})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.13.2

Cancel the common factors.

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Step 3.13.2.1

Factor $3$ out of $9$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + {(\frac{3 \cdot 7}{3 \cdot 3})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.13.2.2

Cancel the common factor.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + {(\frac{3 \cdot 7}{3 \cdot 3})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.13.2.3

Rewrite the expression.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + {(\frac{7}{3})}^{2}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.14

Apply the product rule to $\frac{7}{3}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + \frac{7^{2}}{3^{2}}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.15

Raise $7$ to the power of $2$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + \frac{49}{3^{2}}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.16

Raise $3$ to the power of $2$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + \frac{49}{9}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.17

To write $\frac{49}{9}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + \frac{49}{9} \cdot \frac{4}{4}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.18

Write each expression with a common denominator of $36$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.18.1

Multiply $\frac{49}{9}$ by $\frac{4}{4}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + \frac{49 \cdot 4}{9 \cdot 4}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.18.2

Multiply $9$ by $4$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25}{36} + \frac{49 \cdot 4}{36}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.19

Combine the numerators over the common denominator.

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25 + 49 \cdot 4}{36}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.20

Simplify the numerator.

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Step 3.20.1

Multiply $49$ by $4$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{25 + 196}{36}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.20.2

Add $25$ and $196$ .

$\frac{35}{6} + \frac{7}{2} \cdot \sqrt{\frac{221}{36}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.21

Rewrite $\sqrt{\frac{221}{36}}$ as $\frac{\sqrt{221}}{\sqrt{36}}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \frac{\sqrt{221}}{\sqrt{36}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.22

Simplify the denominator.

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Step 3.22.1

Rewrite $36$ as $6^{2}$ .

$\frac{35}{6} + \frac{7}{2} \cdot \frac{\sqrt{221}}{\sqrt{6^{2}}} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.22.2

Pull terms out from under the radical, assuming positive real numbers.

$\frac{35}{6} + \frac{7}{2} \cdot \frac{\sqrt{221}}{6} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.23

Multiply $\frac{7}{2} \cdot \frac{\sqrt{221}}{6}$ .

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Step 3.23.1

Multiply $\frac{7}{2}$ by $\frac{\sqrt{221}}{6}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{2 \cdot 6} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.23.2

Multiply $2$ by $6$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{15}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.24

Cancel the common factor of $15$ and $9$ .

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Step 3.24.1

Factor $3$ out of $15$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{3 (5)}{9} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.24.2

Cancel the common factors.

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Step 3.24.2.1

Factor $3$ out of $9$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{3 \cdot 5}{3 \cdot 3} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.24.2.2

Cancel the common factor.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{3 \cdot 5}{3 \cdot 3} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.24.2.3

Rewrite the expression.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{\frac{21}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.25

Cancel the common factor of $21$ and $6$ .

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Step 3.25.1

Factor $3$ out of $21$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{\frac{3 (7)}{6}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.25.2

Cancel the common factors.

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Step 3.25.2.1

Factor $3$ out of $6$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{\frac{3 \cdot 7}{3 \cdot 2}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.25.2.2

Cancel the common factor.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{\frac{3 \cdot 7}{3 \cdot 2}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.25.2.3

Rewrite the expression.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{\frac{7}{2}}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.26

Multiply the numerator by the reciprocal of the denominator.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{7}{2} \cdot \frac{1}{2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.27

Multiply $\frac{7}{2} \cdot \frac{1}{2}$ .

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Step 3.27.1

Multiply $\frac{7}{2}$ by $\frac{1}{2}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{7}{2 \cdot 2})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.27.2

Multiply $2$ by $2$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{{(\frac{7}{4})}^{2} + {(\frac{21}{9})}^{2}}$

Step 3.28

Apply the product rule to $\frac{7}{4}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{7^{2}}{4^{2}} + {(\frac{21}{9})}^{2}}$

Step 3.29

Raise $7$ to the power of $2$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{4^{2}} + {(\frac{21}{9})}^{2}}$

Step 3.30

Raise $4$ to the power of $2$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + {(\frac{21}{9})}^{2}}$

Step 3.31

Cancel the common factor of $21$ and $9$ .

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Step 3.31.1

Factor $3$ out of $21$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + {(\frac{3 (7)}{9})}^{2}}$

Step 3.31.2

Cancel the common factors.

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Step 3.31.2.1

Factor $3$ out of $9$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + {(\frac{3 \cdot 7}{3 \cdot 3})}^{2}}$

Step 3.31.2.2

Cancel the common factor.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + {(\frac{3 \cdot 7}{3 \cdot 3})}^{2}}$

Step 3.31.2.3

Rewrite the expression.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + {(\frac{7}{3})}^{2}}$

Step 3.32

Apply the product rule to $\frac{7}{3}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + \frac{7^{2}}{3^{2}}}$

Step 3.33

Raise $7$ to the power of $2$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + \frac{49}{3^{2}}}$

Step 3.34

Raise $3$ to the power of $2$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} + \frac{49}{9}}$

Step 3.35

To write $\frac{49}{16}$ as a fraction with a common denominator, multiply by $\frac{9}{9}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} \cdot \frac{9}{9} + \frac{49}{9}}$

Step 3.36

To write $\frac{49}{9}$ as a fraction with a common denominator, multiply by $\frac{16}{16}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49}{16} \cdot \frac{9}{9} + \frac{49}{9} \cdot \frac{16}{16}}$

Step 3.37

Write each expression with a common denominator of $144$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.37.1

Multiply $\frac{49}{16}$ by $\frac{9}{9}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49 \cdot 9}{16 \cdot 9} + \frac{49}{9} \cdot \frac{16}{16}}$

Step 3.37.2

Multiply $16$ by $9$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49 \cdot 9}{144} + \frac{49}{9} \cdot \frac{16}{16}}$

Step 3.37.3

Multiply $\frac{49}{9}$ by $\frac{16}{16}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49 \cdot 9}{144} + \frac{49 \cdot 16}{9 \cdot 16}}$

Step 3.37.4

Multiply $9$ by $16$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49 \cdot 9}{144} + \frac{49 \cdot 16}{144}}$

Step 3.38

Combine the numerators over the common denominator.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{49 \cdot 9 + 49 \cdot 16}{144}}$

Step 3.39

Simplify the numerator.

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Step 3.39.1

Multiply $49$ by $9$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{441 + 49 \cdot 16}{144}}$

Step 3.39.2

Multiply $49$ by $16$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{441 + 784}{144}}$

Step 3.39.3

Add $441$ and $784$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \sqrt{\frac{1225}{144}}$

Step 3.40

Rewrite $\sqrt{\frac{1225}{144}}$ as $\frac{\sqrt{1225}}{\sqrt{144}}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \frac{\sqrt{1225}}{\sqrt{144}}$

Step 3.41

Simplify the numerator.

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Step 3.41.1

Rewrite $1225$ as $35^{2}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \frac{\sqrt{35^{2}}}{\sqrt{144}}$

Step 3.41.2

Pull terms out from under the radical, assuming positive real numbers.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \frac{35}{\sqrt{144}}$

Step 3.42

Simplify the denominator.

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Step 3.42.1

Rewrite $144$ as $12^{2}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \frac{35}{\sqrt{12^{2}}}$

Step 3.42.2

Pull terms out from under the radical, assuming positive real numbers.

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5}{3} \cdot \frac{35}{12}$

Step 3.43

Multiply $\frac{5}{3} \cdot \frac{35}{12}$ .

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Step 3.43.1

Multiply $\frac{5}{3}$ by $\frac{35}{12}$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{5 \cdot 35}{3 \cdot 12}$

Step 3.43.2

Multiply $5$ by $35$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{175}{3 \cdot 12}$

Step 3.43.3

Multiply $3$ by $12$ .

$\frac{35}{6} + \frac{7 \sqrt{221}}{12} + \frac{175}{36}$

Step 4

To write $\frac{35}{6}$ as a fraction with a common denominator, multiply by $\frac{6}{6}$ .

$\frac{35}{6} \cdot \frac{6}{6} + \frac{175}{36} + \frac{7 \sqrt{221}}{12}$

Step 5

Write each expression with a common denominator of $36$ , by multiplying each by an appropriate factor of $1$ .

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Step 5.1

Multiply $\frac{35}{6}$ by $\frac{6}{6}$ .

$\frac{35 \cdot 6}{6 \cdot 6} + \frac{175}{36} + \frac{7 \sqrt{221}}{12}$

Step 5.2

Multiply $6$ by $6$ .

$\frac{35 \cdot 6}{36} + \frac{175}{36} + \frac{7 \sqrt{221}}{12}$

Step 6

Combine the numerators over the common denominator.

$\frac{35 \cdot 6 + 175}{36} + \frac{7 \sqrt{221}}{12}$

Step 7

Simplify the numerator.

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Step 7.1

Multiply $35$ by $6$ .

$\frac{210 + 175}{36} + \frac{7 \sqrt{221}}{12}$

Step 7.2

Add $210$ and $175$ .

$\frac{385}{36} + \frac{7 \sqrt{221}}{12}$

Step 8

Calculate the approximate solution to $4$ decimal places.

$19.3663$