Pre-Algebra Examples

 $\begin{array}{r} h = & 16.8 \\ r = & 13.5 \end{array}$

Step 1

The surface area of a cone is equal to the area of the base plus the area of the cone.

$(π \cdot (r a d i u s)) \cdot ((r a d i u s) + \sqrt{{(r a d i u s)}^{2} + {(h e i g h t)}^{2}})$

Step 2

Substitute the values of the length $r = 13.5$ and height $h = 16.8$ into the formula. Pi $π$ is approximately equal to $3.14$ .

$(π \cdot 13.5) (13.5 + \sqrt{{(13.5)}^{2} + {(16.8)}^{2}})$

Step 3

Multiply $π$ by $13.5$ .

$42.41150082 (13.5 + \sqrt{{(13.5)}^{2} + {(16.8)}^{2}})$

Step 4

Simplify each term.

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Step 4.1

Raise $13.5$ to the power of $2$ .

$42.41150082 (13.5 + \sqrt{182.25 + {(16.8)}^{2}})$

Step 4.2

Raise $16.8$ to the power of $2$ .

$42.41150082 (13.5 + \sqrt{182.25 + 282.24})$

Step 4.3

Add $182.25$ and $282.24$ .

$42.41150082 (13.5 + \sqrt{464.49})$

Step 5

Simplify by adding terms.

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Step 5.1

Add $13.5$ and $\sqrt{464.49}$ .

$42.41150082 \cdot 35.05203006$

Step 5.2

Multiply $42.41150082$ by $35.05203006$ .

$1486.60920204$