Pre-Algebra Examples

 $\begin{array}{r} h = & 14.5 \\ l = & 4 \\ w = & 4 \end{array}$

Step 1

The surface area of a box is equal to the sum of the areas of each side of the box.

$2 \cdot (l e n g t h) \cdot (w i d t h) + 2 \cdot (l e n g t h) \cdot (h e i g h t) + 2 \cdot (w i d t h) \cdot (h e i g h t)$

Step 2

Substitute the values of the length $l = 4$ , the width $w = 4$ , and the height $h = 14.5$ into the formula.

$2 \cdot 4 \cdot 4 + 2 \cdot 4 \cdot 14.5 + 2 \cdot 4 \cdot 14.5$

Step 3

Simplify each term.

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Step 3.1

Multiply $2 \cdot 4 \cdot 4$ .

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Step 3.1.1

Multiply $2$ by $4$ .

$8 \cdot 4 + 2 \cdot 4 \cdot 14.5 + 2 \cdot 4 \cdot 14.5$

Step 3.1.2

Multiply $8$ by $4$ .

$32 + 2 \cdot 4 \cdot 14.5 + 2 \cdot 4 \cdot 14.5$

Step 3.2

Multiply $2 \cdot 4 \cdot 14.5$ .

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Step 3.2.1

Multiply $2$ by $4$ .

$32 + 8 \cdot 14.5 + 2 \cdot 4 \cdot 14.5$

Step 3.2.2

Multiply $8$ by $14.5$ .

$32 + 116 + 2 \cdot 4 \cdot 14.5$

Step 3.3

Multiply $2 \cdot 4 \cdot 14.5$ .

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Step 3.3.1

Multiply $2$ by $4$ .

$32 + 116 + 8 \cdot 14.5$

Step 3.3.2

Multiply $8$ by $14.5$ .

$32 + 116 + 116$

Step 4

Simplify by adding numbers.

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Step 4.1

Add $32$ and $116$ .

$148 + 116$

Step 4.2

Add $148$ and $116$ .

$264$