Pre-Algebra Examples

 $\begin{array}{r} h = & h \\ r = & 3 \end{array}$

Step 1

The volume of a cone is equal to $\frac{1}{3}$ times the area of the base $π r^{2}$ times the height $h$ .

$\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)$

Step 2

Substitute the values of the radius $r = 3$ and height $h = h$ into the formula to find the volume of the cone. Pi $π$ is approximately equal to $3.14$ .

$\frac{1}{3} \cdot π \cdot 3^{2} \cdot h$

Step 3

Combine $\frac{1}{3}$ and $π$ .

$\frac{π}{3} \cdot 3^{2} \cdot h$

Step 4

Cancel the common factor of $3$ .

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Step 4.1

Factor $3$ out of $3^{2}$ .

$\frac{π}{3} \cdot (3 \cdot 3) \cdot h$

Step 4.2

Cancel the common factor.

$\frac{π}{3} \cdot (3 \cdot 3) \cdot h$

Step 4.3

Rewrite the expression.

$π \cdot 3 \cdot h$

Step 5

Move $3$ to the left of $π$ .

$3 π h$