Pre-Algebra Examples

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\begin{matrix} r = & 18 cm \end{matrix}

$\begin{array}{r} r = & 18 cm \end{array}$

Step 1

The volume of a sphere is equal to

\frac{4}{3}

$\frac{4}{3}$ times Pi

π

$π$ times the radius cubed.

\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}

$\frac{4}{3} \cdot π \cdot {(r a d i u s)}^{3}$

Step 2

Substitute the value of the radius

r = 18

$r = 18$ into the formula to find the volume of the sphere. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

\frac{4}{3} \cdot π \cdot 18^{3}

$\frac{4}{3} \cdot π \cdot 18^{3}$

Step 3

Combine

\frac{4}{3}

$\frac{4}{3}$ and

π

$π$ .

\frac{4 π}{3} \cdot 18^{3}

$\frac{4 π}{3} \cdot 18^{3}$

Step 4

Raise

18

$18$ to the power of

3

$3$ .

\frac{4 π}{3} \cdot 5832

$\frac{4 π}{3} \cdot 5832$

Step 5

Cancel the common factor of

3

$3$ .

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Step 5.1

Factor

3

$3$ out of

5832

$5832$ .

\frac{4 π}{3} \cdot (3 (1944))

$\frac{4 π}{3} \cdot (3 (1944))$

Step 5.2

Cancel the common factor.

$\frac{4 π}{3} \cdot (3 \cdot 1944)$

Step 5.3

Rewrite the expression.

$4 π \cdot 1944$

Step 6

Multiply

$1944$ by

$4$ .

$7776 π {(cm)}^{3}$