Pre-Algebra Examples

 $\begin{array}{r} h = & \frac{1}{3} \\ r = & 12 \end{array}$

Step 1

The volume of a cone is equal to $\frac{1}{3}$ times the area of the base $π r^{2}$ times the height $h$ .

$\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)$

Step 2

Substitute the values of the radius $r = 12$ and height $h = \frac{1}{3}$ into the formula to find the volume of the cone. Pi $π$ is approximately equal to $3.14$ .

$\frac{1}{3} \cdot π \cdot 12^{2} \cdot \frac{1}{3}$

Step 3

Combine $\frac{1}{3}$ and $π$ .

$\frac{π}{3} \cdot 12^{2} \cdot \frac{1}{3}$

Step 4

Raise $12$ to the power of $2$ .

$\frac{π}{3} \cdot 144 \cdot \frac{1}{3}$

Step 5

Cancel the common factor of $3$ .

Tap for more steps...

Step 5.1

Factor $3$ out of $\frac{π}{3} \cdot 144$ .

$3 (\frac{π}{3} \cdot 48) \cdot \frac{1}{3}$

Step 5.2

Cancel the common factor.

$3 (\frac{π}{3} \cdot 48) \cdot \frac{1}{3}$

Step 5.3

Rewrite the expression.

$\frac{π}{3} \cdot 48$

Step 6

Combine $\frac{π}{3}$ and $48$ .

$\frac{π \cdot 48}{3}$

Step 7

Cancel the common factor of $48$ and $3$ .

Tap for more steps...

Step 7.1

Factor $3$ out of $π \cdot 48$ .

$\frac{3 (π \cdot 16)}{3}$

Step 7.2

Cancel the common factors.

Tap for more steps...

Step 7.2.1

Factor $3$ out of $3$ .

$\frac{3 (π \cdot 16)}{3 (1)}$

Step 7.2.2

Cancel the common factor.

$\frac{3 (π \cdot 16)}{3 \cdot 1}$

Step 7.2.3

Rewrite the expression.

$\frac{π \cdot 16}{1}$

Step 7.2.4

Divide $π \cdot 16$ by $1$ .

$π \cdot 16$

Step 8

Move $16$ to the left of $π$ .

$16 π$

Step 9

The result can be shown in multiple forms.

Exact Form:

$16 π$

Decimal Form:

$50.26548245 \dots$