Pre-Algebra Examples

 $\begin{array}{r} b_{1} = & 1.5 in \\ b_{2} = & 1.5 \\ h = & x i n \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = x i n$ and bases ( $b_{1} = 1.5$ and $b_{2} = 1.5$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot (x i n) \cdot (1.5 + 1.5)$

Step 3

Multiply $\frac{1}{2} (x i n)$ .

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Step 3.1

Combine $x$ and $\frac{1}{2}$ .

$\frac{x}{2} (i n) \cdot (1.5 + 1.5)$

Step 3.2

Combine $i$ and $\frac{x}{2}$ .

$\frac{i x}{2} n \cdot (1.5 + 1.5)$

Step 3.3

Combine $\frac{i x}{2}$ and $n$ .

$\frac{i x n}{2} \cdot (1.5 + 1.5)$

Step 4

Add $1.5$ and $1.5$ .

$\frac{i x n}{2} \cdot 3$

Step 5

Combine $\frac{i x n}{2}$ and $3$ .

$\frac{i x n \cdot 3}{2}$

Step 6

Cancel the common factor of $3$ and $2$ .

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Step 6.1

Factor $1$ out of $i x n \cdot 3$ .

$\frac{1 (i x n \cdot 3)}{2}$

Step 6.2

Cancel the common factors.

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Step 6.2.1

Rewrite $2$ as $1 (2)$ .

$\frac{1 (i x n \cdot 3)}{1 (2)}$

Step 6.2.2

Cancel the common factor.

$\frac{1 (i x n \cdot 3)}{1 \cdot 2}$

Step 6.2.3

Rewrite the expression.

$\frac{i x n \cdot 3}{2}$

Step 7

Move $3$ to the left of $i x n$ .

$\frac{3 i x n}{2} {(in)}^{2}$