Pre-Algebra Examples

 $\begin{array}{r} b_{1} = & 17.7 \\ b_{2} = & 23.7 \\ h = & 43.6 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 43.6$ and bases ( $b_{1} = 17.7$ and $b_{2} = 23.7$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 43.6 \cdot (17.7 + 23.7)$

Step 3

Combine $\frac{1}{2}$ and $43.6$ .

$\frac{43.6}{2} \cdot (17.7 + 23.7)$

Step 4

Simplify the expression.

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Step 4.1

Divide $43.6$ by $2$ .

$21.8 \cdot (17.7 + 23.7)$

Step 4.2

Add $17.7$ and $23.7$ .

$21.8 \cdot 41.4$

Step 4.3

Multiply $21.8$ by $41.4$ .

$902.52$