Pre-Algebra Examples



\begin{matrix} b_{1} = & 15 m b_{2} = & 14 m h = & 19 m \end{matrix}

$\begin{array}{r} b_{1} = & 15 m \\ b_{2} = & 14 m \\ h = & 19 m \end{array}$

Step 1

The area of a trapezoid is equal to

\frac{1}{2}

$\frac{1}{2}$ times the height times the sum of the bases

b_{1} + b_{2}

$b_{1} + b_{2}$ .

\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height

h = 19

$h = 19$ and bases (

b_{1} = 15

$b_{1} = 15$ and

b_{2} = 14

$b_{2} = 14$ ) into the formula for the area of a trapezoid.

\frac{1}{2} \cdot 19 \cdot (15 + 14)

$\frac{1}{2} \cdot 19 \cdot (15 + 14)$

Step 3

Combine

\frac{1}{2}

$\frac{1}{2}$ and

19

$19$ .

\frac{19}{2} \cdot (15 + 14)

$\frac{19}{2} \cdot (15 + 14)$

Step 4

Add

15

$15$ and

14

$14$ .

\frac{19}{2} \cdot 29

$\frac{19}{2} \cdot 29$

Step 5

Multiply

\frac{19}{2} \cdot 29

$\frac{19}{2} \cdot 29$ .

Tap for more steps...

Step 5.1

Combine

\frac{19}{2}

$\frac{19}{2}$ and

29

$29$ .

\frac{19 \cdot 29}{2}

$\frac{19 \cdot 29}{2}$

Step 5.2

Multiply

19

$19$ by

29

$29$ .

\frac{551}{2}

$\frac{551}{2}$

\frac{551}{2} m^{2}

$\frac{551}{2} m^{2}$

 $\begin{array}{r} b_{1} = & 15 m \\ b_{2} = & 14 m \\ h = & 19 m \end{array}$

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