Pre-Algebra Examples

 $\begin{array}{r} b_{1} = & 78 \\ b_{2} = & 46 \\ h = & 46 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 46$ and bases ( $b_{1} = 78$ and $b_{2} = 46$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 46 \cdot (78 + 46)$

Step 3

Cancel the common factor of $2$ .

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Step 3.1

Factor $2$ out of $46$ .

$\frac{1}{2} \cdot (2 (23)) \cdot (78 + 46)$

Step 3.2

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 23) \cdot (78 + 46)$

Step 3.3

Rewrite the expression.

$23 \cdot (78 + 46)$

Step 4

Simplify the expression.

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Step 4.1

Add $78$ and $46$ .

$23 \cdot 124$

Step 4.2

Multiply $23$ by $124$ .

$2852$