Pre-Algebra Examples

 $\begin{array}{r} b_{1} = & 96 \\ b_{2} = & 100 \\ h = & 125 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 125$ and bases ( $b_{1} = 96$ and $b_{2} = 100$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 125 \cdot (96 + 100)$

Step 3

Combine $\frac{1}{2}$ and $125$ .

$\frac{125}{2} \cdot (96 + 100)$

Step 4

Add $96$ and $100$ .

$\frac{125}{2} \cdot 196$

Step 5

Cancel the common factor of $2$ .

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Step 5.1

Factor $2$ out of $196$ .

$\frac{125}{2} \cdot (2 (98))$

Step 5.2

Cancel the common factor.

$\frac{125}{2} \cdot (2 \cdot 98)$

Step 5.3

Rewrite the expression.

$125 \cdot 98$

Step 6

Multiply $125$ by $98$ .

$12250$