Pre-Algebra Examples

 $\begin{array}{r} l = & \frac{30}{3} \\ w = & \frac{5}{15} \end{array}$

Step 1

The area of a rectangle is equal to the length times the width.

$(l e n g t h) \cdot (w i d t h)$

Step 2

Substitute the values of the length $l = \frac{30}{3}$ and width $w = \frac{5}{15}$ into the formula for the area of a rectangle.

$\frac{30}{3} \cdot \frac{5}{15}$

Step 3

Cancel the common factor of $15$ .

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Step 3.1

Factor $15$ out of $30$ .

$\frac{15 (2)}{3} \cdot \frac{5}{15}$

Step 3.2

Cancel the common factor.

$\frac{15 \cdot 2}{3} \cdot \frac{5}{15}$

Step 3.3

Rewrite the expression.

$\frac{2}{3} \cdot 5$

Step 4

Combine $\frac{2}{3}$ and $5$ .

$\frac{2 \cdot 5}{3}$

Step 5

Multiply $2$ by $5$ .

$\frac{10}{3}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$\frac{10}{3}$

Decimal Form:

$3.\overline{3}$

Mixed Number Form:

$3 \frac{1}{3}$