Pre-Algebra Examples

$\frac{4 k^{3} + 12 k^{2} + 11 k - 3}{k + 2}$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$k$

$2$

$4 k^{3}$

$12 k^{2}$

$11 k$

$3$

Step 2

Divide the highest order term in the dividend $4 k^{3}$ by the highest order term in divisor $k$ .

					$4 k^{2}$
	$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$

Step 3

Multiply the new quotient term by the divisor.

				$4 k^{2}$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			+	$4 k^{3}$	+	$8 k^{2}$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $4 k^{3} + 8 k^{2}$

				$4 k^{2}$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$4 k^{2}$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$

Step 6

Pull the next terms from the original dividend down into the current dividend.

				$4 k^{2}$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$

Step 7

Divide the highest order term in the dividend $4 k^{2}$ by the highest order term in divisor $k$ .

				$4 k^{2}$	+	$4 k$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$

Step 8

Multiply the new quotient term by the divisor.

				$4 k^{2}$	+	$4 k$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					+	$4 k^{2}$	+	$8 k$

Step 9

The expression needs to be subtracted from the dividend, so change all the signs in $4 k^{2} + 8 k$

				$4 k^{2}$	+	$4 k$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$

Step 10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$4 k^{2}$	+	$4 k$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$
							+	$3 k$

Step 11

Pull the next terms from the original dividend down into the current dividend.

				$4 k^{2}$	+	$4 k$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$
							+	$3 k$	-	$3$

Step 12

Divide the highest order term in the dividend $3 k$ by the highest order term in divisor $k$ .

				$4 k^{2}$	+	$4 k$	+	$3$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$
							+	$3 k$	-	$3$

Step 13

Multiply the new quotient term by the divisor.

				$4 k^{2}$	+	$4 k$	+	$3$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$
							+	$3 k$	-	$3$
							+	$3 k$	+	$6$

Step 14

The expression needs to be subtracted from the dividend, so change all the signs in $3 k + 6$

				$4 k^{2}$	+	$4 k$	+	$3$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$
							+	$3 k$	-	$3$
							-	$3 k$	-	$6$

Step 15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$4 k^{2}$	+	$4 k$	+	$3$
$k$	+	$2$		$4 k^{3}$	+	$12 k^{2}$	+	$11 k$	-	$3$
			-	$4 k^{3}$	-	$8 k^{2}$
					+	$4 k^{2}$	+	$11 k$
					-	$4 k^{2}$	-	$8 k$
							+	$3 k$	-	$3$
							-	$3 k$	-	$6$
									-	$9$

Step 16

The final answer is the quotient plus the remainder over the divisor.

$4 k^{2} + 4 k + 3 - \frac{9}{k + 2}$