Pre-Algebra Examples

$\frac{16 x^{8} - 48 x^{7} + 40 x^{3}}{- 8 x^{3}}$

Step 1

Factor $8 x^{3}$ out of $16 x^{8} - 48 x^{7} + 40 x^{3}$ .

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Step 1.1

Factor $8 x^{3}$ out of $16 x^{8}$ .

$\frac{8 x^{3} (2 x^{5}) - 48 x^{7} + 40 x^{3}}{- 8 x^{3}}$

Step 1.2

Factor $8 x^{3}$ out of $- 48 x^{7}$ .

$\frac{8 x^{3} (2 x^{5}) + 8 x^{3} (- 6 x^{4}) + 40 x^{3}}{- 8 x^{3}}$

Step 1.3

Factor $8 x^{3}$ out of $40 x^{3}$ .

$\frac{8 x^{3} (2 x^{5}) + 8 x^{3} (- 6 x^{4}) + 8 x^{3} (5)}{- 8 x^{3}}$

Step 1.4

Factor $8 x^{3}$ out of $8 x^{3} (2 x^{5}) + 8 x^{3} (- 6 x^{4})$ .

$\frac{8 x^{3} (2 x^{5} - 6 x^{4}) + 8 x^{3} (5)}{- 8 x^{3}}$

Step 1.5

Factor $8 x^{3}$ out of $8 x^{3} (2 x^{5} - 6 x^{4}) + 8 x^{3} (5)$ .

$\frac{8 x^{3} (2 x^{5} - 6 x^{4} + 5)}{- 8 x^{3}}$

Step 2

Cancel the common factor of $8$ and $- 8$ .

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Step 2.1

Factor $8$ out of $8 x^{3} (2 x^{5} - 6 x^{4} + 5)$ .

$\frac{8 (x^{3} (2 x^{5} - 6 x^{4} + 5))}{- 8 x^{3}}$

Step 2.2

Cancel the common factors.

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Step 2.2.1

Factor $8$ out of $- 8 x^{3}$ .

$\frac{8 (x^{3} (2 x^{5} - 6 x^{4} + 5))}{8 (- x^{3})}$

Step 2.2.2

Cancel the common factor.

$\frac{8 (x^{3} (2 x^{5} - 6 x^{4} + 5))}{8 (- x^{3})}$

Step 2.2.3

Rewrite the expression.

$\frac{x^{3} (2 x^{5} - 6 x^{4} + 5)}{- x^{3}}$

Step 3

Cancel the common factor of $x^{3}$ .

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Step 3.1

Cancel the common factor.

$\frac{x^{3} (2 x^{5} - 6 x^{4} + 5)}{- x^{3}}$

Step 3.2

Rewrite the expression.

$\frac{2 x^{5} - 6 x^{4} + 5}{- 1}$

Step 3.3

Move the negative one from the denominator of $\frac{2 x^{5} - 6 x^{4} + 5}{- 1}$ .

$- 1 \cdot (2 x^{5} - 6 x^{4} + 5)$

Step 4

Rewrite $- 1 \cdot (2 x^{5} - 6 x^{4} + 5)$ as $- (2 x^{5} - 6 x^{4} + 5)$ .

$- (2 x^{5} - 6 x^{4} + 5)$

Step 5

Apply the distributive property.

$- (2 x^{5}) - (- 6 x^{4}) - 1 \cdot 5$

Step 6

Simplify.

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Step 6.1

Multiply $2$ by $- 1$ .

$- 2 x^{5} - (- 6 x^{4}) - 1 \cdot 5$

Step 6.2

Multiply $- 6$ by $- 1$ .

$- 2 x^{5} + 6 x^{4} - 1 \cdot 5$

Step 6.3

Multiply $- 1$ by $5$ .

$- 2 x^{5} + 6 x^{4} - 5$