Pre-Algebra Examples

$\frac{12 a^{3} - 3 a^{2} \cdot (5 a) + 10}{4 a + 3}$

Step 1

Expand $12 a^{3} - 3 a^{2} \cdot (5 a) + 10$ .

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Step 1.1

Remove parentheses.

$\frac{12 a^{3} - 3 a^{2} \cdot (5 a) + 10}{4 a + 3}$

Step 1.2

Move $a^{2}$ .

$\frac{12 a^{3} - 3 \cdot (5 a^{2} a) + 10}{4 a + 3}$

Step 1.3

Multiply $- 3$ by $5$ .

$\frac{12 a^{3} - 15 a^{2} a + 10}{4 a + 3}$

Step 1.4

Raise $a$ to the power of $1$ .

$\frac{12 a^{3} - 15 (a^{2} a) + 10}{4 a + 3}$

Step 1.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{12 a^{3} - 15 a^{2 + 1} + 10}{4 a + 3}$

Step 1.6

Add $2$ and $1$ .

$\frac{12 a^{3} - 15 a^{3} + 10}{4 a + 3}$

Step 1.7

Subtract $15 a^{3}$ from $12 a^{3}$ .

$\frac{- 3 a^{3} + 10}{4 a + 3}$

Step 2

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$4 a$

$3$

$3 a^{3}$

$0 a^{2}$

$0 a$

$10$

Step 3

Divide the highest order term in the dividend $- 3 a^{3}$ by the highest order term in divisor $4 a$ .

				-	$\frac{3 a^{2}}{4}$
	$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$

Step 4

Multiply the new quotient term by the divisor.

			-	$\frac{3 a^{2}}{4}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			-	$3 a^{3}$	-	$\frac{9 a^{2}}{4}$

Step 5

The expression needs to be subtracted from the dividend, so change all the signs in $- 3 a^{3} - \frac{9 a^{2}}{4}$

			-	$\frac{3 a^{2}}{4}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$

Step 6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

			-	$\frac{3 a^{2}}{4}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$

Step 7

Pull the next terms from the original dividend down into the current dividend.

			-	$\frac{3 a^{2}}{4}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$

Step 8

Divide the highest order term in the dividend $\frac{9 a^{2}}{4}$ by the highest order term in divisor $4 a$ .

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$

Step 9

Multiply the new quotient term by the divisor.

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					+	$\frac{9 a^{2}}{4}$	+	$\frac{27 a}{16}$

Step 10

The expression needs to be subtracted from the dividend, so change all the signs in $\frac{9 a^{2}}{4} + \frac{27 a}{16}$

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$

Step 11

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$
							-	$\frac{27 a}{16}$

Step 12

Pull the next terms from the original dividend down into the current dividend.

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$
							-	$\frac{27 a}{16}$	+	$10$

Step 13

Divide the highest order term in the dividend $- \frac{27 a}{16}$ by the highest order term in divisor $4 a$ .

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$	-	$\frac{27}{64}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$
							-	$\frac{27 a}{16}$	+	$10$

Step 14

Multiply the new quotient term by the divisor.

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$	-	$\frac{27}{64}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$
							-	$\frac{27 a}{16}$	+	$10$
							-	$\frac{27 a}{16}$	-	$\frac{81}{64}$

Step 15

The expression needs to be subtracted from the dividend, so change all the signs in $- \frac{27 a}{16} - \frac{81}{64}$

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$	-	$\frac{27}{64}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$
							-	$\frac{27 a}{16}$	+	$10$
							+	$\frac{27 a}{16}$	+	$\frac{81}{64}$

Step 16

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

			-	$\frac{3 a^{2}}{4}$	+	$\frac{9 a}{16}$	-	$\frac{27}{64}$
$4 a$	+	$3$	-	$3 a^{3}$	+	$0 a^{2}$	+	$0 a$	+	$10$
			+	$3 a^{3}$	+	$\frac{9 a^{2}}{4}$
					+	$\frac{9 a^{2}}{4}$	+	$0 a$
					-	$\frac{9 a^{2}}{4}$	-	$\frac{27 a}{16}$
							-	$\frac{27 a}{16}$	+	$10$
							+	$\frac{27 a}{16}$	+	$\frac{81}{64}$
									+	$\frac{721}{64}$

Step 17

The final answer is the quotient plus the remainder over the divisor.

$- \frac{3 a^{2}}{4} + \frac{9 a}{16} - \frac{27}{64} + \frac{721}{64 (4 a + 3)}$