Pre-Algebra Examples

$(6 x - 17 x - 3) \div (3 x - 9)$

Step 1

Subtract $17 x$ from $6 x$ .

$\frac{- 11 x - 3}{3 x - 9}$

Step 2

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$3 x$

$9$

$11 x$

$3$

Step 3

Divide the highest order term in the dividend $- 11 x$ by the highest order term in divisor $3 x$ .

				-	$\frac{11}{3}$
	$3 x$	-	$9$	-	$11 x$	-	$3$

Step 4

Multiply the new quotient term by the divisor.

Step 5

The expression needs to be subtracted from the dividend, so change all the signs in $- 11 x + 33$

Step 6

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

Step 7

The final answer is the quotient plus the remainder over the divisor.

$- \frac{11}{3} - \frac{36}{3 x - 9}$