Pre-Algebra Examples

$(k^{4} + 7 k^{3} + 8 k^{2} + 14 k + 12) \div (k^{2} + 2)$

Step 1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

Step 2

Divide the highest order term in the dividend $k^{4}$ by the highest order term in divisor $k^{2}$ .

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

Step 3

Multiply the new quotient term by the divisor.

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

Step 4

The expression needs to be subtracted from the dividend, so change all the signs in $k^{4} + 0 + 2 k^{2}$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

Step 5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

Step 6

Pull the next terms from the original dividend down into the current dividend.

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

Step 7

Divide the highest order term in the dividend $7 k^{3}$ by the highest order term in divisor $k^{2}$ .

$k^{2}$

$7 k$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

Step 8

Multiply the new quotient term by the divisor.

$k^{2}$

$7 k$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

Step 9

The expression needs to be subtracted from the dividend, so change all the signs in $7 k^{3} + 0 + 14 k$

$k^{2}$

$7 k$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

Step 10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$k^{2}$

$7 k$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

$6 k^{2}$

$0$

Step 11

Pull the next term from the original dividend down into the current dividend.

$k^{2}$

$7 k$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

$6 k^{2}$

$0$

$12$

Step 12

Divide the highest order term in the dividend $6 k^{2}$ by the highest order term in divisor $k^{2}$ .

$k^{2}$

$7 k$

$6$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

$6 k^{2}$

$0$

$12$

Step 13

Multiply the new quotient term by the divisor.

$k^{2}$

$7 k$

$6$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

$6 k^{2}$

$0$

$12$

$6 k^{2}$

$0$

$12$

Step 14

The expression needs to be subtracted from the dividend, so change all the signs in $6 k^{2} + 0 + 12$

$k^{2}$

$7 k$

$6$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

$6 k^{2}$

$0$

$12$

$6 k^{2}$

$0$

$12$

Step 15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

$k^{2}$

$7 k$

$6$

$k^{2}$

$0 k$

$2$

$k^{4}$

$7 k^{3}$

$8 k^{2}$

$14 k$

$12$

$k^{4}$

$0$

$2 k^{2}$

$7 k^{3}$

$6 k^{2}$

$14 k$

$7 k^{3}$

$0$

$14 k$

$6 k^{2}$

$0$

$12$

$6 k^{2}$

$0$

$12$

$0$

Step 16

Since the remander is $0$ , the final answer is the quotient.

$k^{2} + 7 k + 6$