Pre-Algebra Examples

$- \frac{3}{8} x = 15$

Step 1

Solve for $y$ .

Tap for more steps...

Step 1.1

Divide each term in $- \frac{3 x}{8} = 15$ by $- 1$ and simplify.

Tap for more steps...

Step 1.1.1

Divide each term in $- \frac{3 x}{8} = 15$ by $- 1$ .

$\frac{- \frac{3 x}{8}}{- 1} = \frac{15}{- 1}$

Step 1.1.2

Simplify the left side.

Tap for more steps...

Step 1.1.2.1

Dividing two negative values results in a positive value.

$\frac{\frac{3 x}{8}}{1} = \frac{15}{- 1}$

Step 1.1.2.2

Divide $\frac{3 x}{8}$ by $1$ .

$\frac{3 x}{8} = \frac{15}{- 1}$

Step 1.1.3

Simplify the right side.

Tap for more steps...

Step 1.1.3.1

Divide $15$ by $- 1$ .

$\frac{3 x}{8} = - 15$

Step 1.2

Multiply both sides of the equation by $\frac{8}{3}$ .

$\frac{8}{3} \cdot \frac{3 x}{8} = \frac{8}{3} \cdot - 15$

Step 1.3

Simplify both sides of the equation.

Tap for more steps...

Step 1.3.1

Simplify the left side.

Tap for more steps...

Step 1.3.1.1

Simplify $\frac{8}{3} \cdot \frac{3 x}{8}$ .

Tap for more steps...

Step 1.3.1.1.1

Cancel the common factor of $8$ .

Tap for more steps...

Step 1.3.1.1.1.1

Cancel the common factor.

$\frac{8}{3} \cdot \frac{3 x}{8} = \frac{8}{3} \cdot - 15$

Step 1.3.1.1.1.2

Rewrite the expression.

$\frac{1}{3} (3 x) = \frac{8}{3} \cdot - 15$

Step 1.3.1.1.2

Cancel the common factor of $3$ .

Tap for more steps...

Step 1.3.1.1.2.1

Factor $3$ out of $3 x$ .

$\frac{1}{3} (3 (x)) = \frac{8}{3} \cdot - 15$

Step 1.3.1.1.2.2

Cancel the common factor.

$\frac{1}{3} (3 x) = \frac{8}{3} \cdot - 15$

Step 1.3.1.1.2.3

Rewrite the expression.

$x = \frac{8}{3} \cdot - 15$

Step 1.3.2

Simplify the right side.

Tap for more steps...

Step 1.3.2.1

Simplify $\frac{8}{3} \cdot - 15$ .

Tap for more steps...

Step 1.3.2.1.1

Cancel the common factor of $3$ .

Tap for more steps...

Step 1.3.2.1.1.1

Factor $3$ out of $- 15$ .

$x = \frac{8}{3} \cdot (3 (- 5))$

Step 1.3.2.1.1.2

Cancel the common factor.

$x = \frac{8}{3} \cdot (3 \cdot - 5)$

Step 1.3.2.1.1.3

Rewrite the expression.

$x = 8 \cdot - 5$

Step 1.3.2.1.2

Multiply $8$ by $- 5$ .

$x = - 40$

Step 2

Since $x = - 40$ is a vertical line, there is no y-intercept and the slope is undefined.

Slope: Undefined

y-intercept: No y-intercept

Step 3

Find two points on the line.

$\begin{array}{c} x & y \\ - 40 & 0 \\ - 40 & 1 \end{array}$

Step 4

Graph the line using the slope, y-intercept, and two points.

Slope: Undefined

y-intercept: No y-intercept

$\begin{array}{c} x & y \\ - 40 & 0 \\ - 40 & 1 \end{array}$

Step 5