Pre-Algebra Examples

$x^{2} + y^{2} + 4 x - 2 y = - 1$

Step 1

Complete the square for $x^{2} + 4 x$ .

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Step 1.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 4$

$c = 0$

Step 1.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 1.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 1.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{4}{2 \cdot 1}$

Step 1.3.2

Cancel the common factor of $4$ and $2$ .

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Step 1.3.2.1

Factor $2$ out of $4$ .

$d = \frac{2 \cdot 2}{2 \cdot 1}$

Step 1.3.2.2

Cancel the common factors.

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Step 1.3.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 2}{2 (1)}$

Step 1.3.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot 2}{2 \cdot 1}$

Step 1.3.2.2.3

Rewrite the expression.

$d = \frac{2}{1}$

Step 1.3.2.2.4

Divide $2$ by $1$ .

$d = 2$

Step 1.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 1.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{4^{2}}{4 \cdot 1}$

Step 1.4.2

Simplify the right side.

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Step 1.4.2.1

Simplify each term.

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Step 1.4.2.1.1

Cancel the common factor of $4^{2}$ and $4$ .

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Step 1.4.2.1.1.1

Factor $4$ out of $4^{2}$ .

$e = 0 - \frac{4 \cdot 4}{4 \cdot 1}$

Step 1.4.2.1.1.2

Cancel the common factors.

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Step 1.4.2.1.1.2.1

Factor $4$ out of $4 \cdot 1$ .

$e = 0 - \frac{4 \cdot 4}{4 (1)}$

Step 1.4.2.1.1.2.2

Cancel the common factor.

$e = 0 - \frac{4 \cdot 4}{4 \cdot 1}$

Step 1.4.2.1.1.2.3

Rewrite the expression.

$e = 0 - \frac{4}{1}$

Step 1.4.2.1.1.2.4

Divide $4$ by $1$ .

$e = 0 - 1 \cdot 4$

Step 1.4.2.1.2

Multiply $- 1$ by $4$ .

$e = 0 - 4$

Step 1.4.2.2

Subtract $4$ from $0$ .

$e = - 4$

Step 1.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 2)}^{2} - 4$ .

${(x + 2)}^{2} - 4$

Step 2

Substitute ${(x + 2)}^{2} - 4$ for $x^{2} + 4 x$ in the equation $x^{2} + y^{2} + 4 x - 2 y = - 1$ .

${(x + 2)}^{2} - 4 + y^{2} - 2 y = - 1$

Step 3

Move $- 4$ to the right side of the equation by adding $4$ to both sides.

${(x + 2)}^{2} + y^{2} - 2 y = - 1 + 4$

Step 4

Complete the square for $y^{2} - 2 y$ .

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Step 4.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 2$

$c = 0$

Step 4.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 4.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 4.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 2}{2 \cdot 1}$

Step 4.3.2

Cancel the common factor of $- 2$ and $2$ .

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Step 4.3.2.1

Factor $2$ out of $- 2$ .

$d = \frac{2 \cdot - 1}{2 \cdot 1}$

Step 4.3.2.2

Cancel the common factors.

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Step 4.3.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot - 1}{2 (1)}$

Step 4.3.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot - 1}{2 \cdot 1}$

Step 4.3.2.2.3

Rewrite the expression.

$d = \frac{- 1}{1}$

Step 4.3.2.2.4

Divide $- 1$ by $1$ .

$d = - 1$

Step 4.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 4.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{{(- 2)}^{2}}{4 \cdot 1}$

Step 4.4.2

Simplify the right side.

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Step 4.4.2.1

Simplify each term.

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Step 4.4.2.1.1

Raise $- 2$ to the power of $2$ .

$e = 0 - \frac{4}{4 \cdot 1}$

Step 4.4.2.1.2

Multiply $4$ by $1$ .

$e = 0 - \frac{4}{4}$

Step 4.4.2.1.3

Cancel the common factor of $4$ .

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Step 4.4.2.1.3.1

Cancel the common factor.

$e = 0 - \frac{4}{4}$

Step 4.4.2.1.3.2

Rewrite the expression.

$e = 0 - 1 \cdot 1$

Step 4.4.2.1.4

Multiply $- 1$ by $1$ .

$e = 0 - 1$

Step 4.4.2.2

Subtract $1$ from $0$ .

$e = - 1$

Step 4.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(y - 1)}^{2} - 1$ .

${(y - 1)}^{2} - 1$

Step 5

Substitute ${(y - 1)}^{2} - 1$ for $y^{2} - 2 y$ in the equation $x^{2} + y^{2} + 4 x - 2 y = - 1$ .

${(x + 2)}^{2} + {(y - 1)}^{2} - 1 = - 1 + 4$

Step 6

Move $- 1$ to the right side of the equation by adding $1$ to both sides.

${(x + 2)}^{2} + {(y - 1)}^{2} = - 1 + 4 + 1$

Step 7

Simplify $- 1 + 4 + 1$ .

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Step 7.1

Add $- 1$ and $4$ .

${(x + 2)}^{2} + {(y - 1)}^{2} = 3 + 1$

Step 7.2

Add $3$ and $1$ .

${(x + 2)}^{2} + {(y - 1)}^{2} = 4$

Step 8

This is the form of a circle. Use this form to determine the center and radius of the circle.

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$

Step 9

Match the values in this circle to those of the standard form. The variable $r$ represents the radius of the circle, $h$ represents the x-offset from the origin, and $k$ represents the y-offset from origin.

$r = 2$

$h = - 2$

$k = 1$

Step 10

The center of the circle is found at $(h, k)$ .

Center: $(- 2, 1)$

Step 11

These values represent the important values for graphing and analyzing a circle.

Center: $(- 2, 1)$

Radius: $2$

Step 12