Pre-Algebra Examples

$w (40) = {(40 + 125)}^{3}$

Step 1

Add $40$ and $125$ .

$w (40) = 165^{3}$

Step 2

Divide each term in $w (40) = 165^{3}$ by $40$ and simplify.

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Step 2.1

Divide each term in $w (40) = 165^{3}$ by $40$ .

$\frac{w (40)}{40} = \frac{165^{3}}{40}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $40$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{w \cdot 40}{40} = \frac{165^{3}}{40}$

Step 2.2.1.2

Divide $w$ by $1$ .

$w = \frac{165^{3}}{40}$

$w = \frac{165^{3}}{40}$

$w = \frac{165^{3}}{40}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Raise $165$ to the power of $3$ .

$w = \frac{4492125}{40}$

Step 2.3.2

Cancel the common factor of $4492125$ and $40$ .

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Step 2.3.2.1

Factor $5$ out of $4492125$ .

$w = \frac{5 (898425)}{40}$

Step 2.3.2.2

Cancel the common factors.

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Step 2.3.2.2.1

Factor $5$ out of $40$ .

$w = \frac{5 \cdot 898425}{5 \cdot 8}$

Step 2.3.2.2.2

Cancel the common factor.

$w = \frac{5 \cdot 898425}{5 \cdot 8}$

Step 2.3.2.2.3

Rewrite the expression.

$w = \frac{898425}{8}$

$w = \frac{898425}{8}$

$w = \frac{898425}{8}$

$w = \frac{898425}{8}$

$w = \frac{898425}{8}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$