Pre-Algebra Examples

$x^{2} + (\sqrt{2} + \sqrt{3}) x + \sqrt{6} = 0$

Step 1

Apply the distributive property.

$x^{2} + \sqrt{2} x + \sqrt{3} x + \sqrt{6} = 0$

Step 2

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 3

Substitute the values $a = 1$ , $b = \sqrt{2} + \sqrt{3}$ , and $c = \sqrt{6}$ into the quadratic formula and solve for $x$ .

$\frac{- (\sqrt{2} + \sqrt{3}) \pm \sqrt{{(\sqrt{2} + \sqrt{3})}^{2} - 4 \cdot (1 \cdot \sqrt{6})}}{2 \cdot 1}$

Step 4

Simplify.

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Step 4.1

Simplify the numerator.

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Step 4.1.1

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{{(\sqrt{2} + \sqrt{3})}^{2} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.2

Rewrite ${(\sqrt{2} + \sqrt{3})}^{2}$ as $(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3})$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.3

Expand $(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3})$ using the FOIL Method.

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Step 4.1.3.1

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} (\sqrt{2} + \sqrt{3}) + \sqrt{3} (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.3.2

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} \sqrt{2} + \sqrt{2} \sqrt{3} + \sqrt{3} (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.3.3

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} \sqrt{2} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4

Simplify and combine like terms.

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Step 4.1.4.1

Simplify each term.

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Step 4.1.4.1.1

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2 \cdot 2} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.2

Multiply $2$ by $2$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{4} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.3

Rewrite $4$ as $2^{2}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2^{2}} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.4

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.5

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{2 \cdot 3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.6

Multiply $2$ by $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.7

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{3 \cdot 2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.8

Multiply $3$ by $2$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.9

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3 \cdot 3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.10

Multiply $3$ by $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{9} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.11

Rewrite $9$ as $3^{2}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3^{2}} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.1.12

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + 3 - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.2

Add $2$ and $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + \sqrt{6} + \sqrt{6} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.4.3

Add $\sqrt{6}$ and $\sqrt{6}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + 2 \sqrt{6} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.5

Multiply $- 4$ by $1$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + 2 \sqrt{6} - 4 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 4.1.6

Subtract $4 \sqrt{6}$ from $2 \sqrt{6}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 - 2 \sqrt{6}}}{2 \cdot 1}$

Step 4.2

Multiply $2$ by $1$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 5

Simplify the expression to solve for the $+$ portion of the $\pm$ .

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Step 5.1

Simplify the numerator.

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Step 5.1.1

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{{(\sqrt{2} + \sqrt{3})}^{2} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.2

Rewrite ${(\sqrt{2} + \sqrt{3})}^{2}$ as $(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3})$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.3

Expand $(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3})$ using the FOIL Method.

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Step 5.1.3.1

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} (\sqrt{2} + \sqrt{3}) + \sqrt{3} (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.3.2

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} \sqrt{2} + \sqrt{2} \sqrt{3} + \sqrt{3} (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.3.3

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} \sqrt{2} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4

Simplify and combine like terms.

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Step 5.1.4.1

Simplify each term.

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Step 5.1.4.1.1

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2 \cdot 2} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.2

Multiply $2$ by $2$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{4} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.3

Rewrite $4$ as $2^{2}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2^{2}} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.4

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.5

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{2 \cdot 3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.6

Multiply $2$ by $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.7

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{3 \cdot 2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.8

Multiply $3$ by $2$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.9

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3 \cdot 3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.10

Multiply $3$ by $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{9} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.11

Rewrite $9$ as $3^{2}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3^{2}} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.1.12

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + 3 - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.2

Add $2$ and $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + \sqrt{6} + \sqrt{6} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.4.3

Add $\sqrt{6}$ and $\sqrt{6}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + 2 \sqrt{6} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.5

Multiply $- 4$ by $1$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + 2 \sqrt{6} - 4 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 5.1.6

Subtract $4 \sqrt{6}$ from $2 \sqrt{6}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 - 2 \sqrt{6}}}{2 \cdot 1}$

Step 5.2

Multiply $2$ by $1$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 5.3

Change the $\pm$ to $+$ .

$x = \frac{- \sqrt{2} - \sqrt{3} + \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 5.4

Factor $- 1$ out of $- \sqrt{2}$ .

$x = \frac{- (\sqrt{2}) - \sqrt{3} + \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 5.5

Factor $- 1$ out of $- \sqrt{3}$ .

$x = \frac{- (\sqrt{2}) - (\sqrt{3}) + \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 5.6

Factor $- 1$ out of $- (\sqrt{2}) - (\sqrt{3})$ .

$x = \frac{- (\sqrt{2} + \sqrt{3}) + \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 5.7

Factor $- 1$ out of $\sqrt{5 - 2 \sqrt{6}}$ .

$x = \frac{- (\sqrt{2} + \sqrt{3}) - 1 (- \sqrt{5 - 2 \sqrt{6}})}{2}$

Step 5.8

Factor $- 1$ out of $- (\sqrt{2} + \sqrt{3}) - 1 (- \sqrt{5 - 2 \sqrt{6}})$ .

$x = \frac{- (\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}})}{2}$

Step 5.9

Rewrite $- (\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}})$ as $- 1 (\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}})$ .

$x = \frac{- 1 (\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}})}{2}$

Step 5.10

Move the negative in front of the fraction.

$x = - \frac{\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 6

Simplify the expression to solve for the $-$ portion of the $\pm$ .

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Step 6.1

Simplify the numerator.

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Step 6.1.1

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{{(\sqrt{2} + \sqrt{3})}^{2} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.2

Rewrite ${(\sqrt{2} + \sqrt{3})}^{2}$ as $(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3})$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.3

Expand $(\sqrt{2} + \sqrt{3}) (\sqrt{2} + \sqrt{3})$ using the FOIL Method.

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Step 6.1.3.1

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} (\sqrt{2} + \sqrt{3}) + \sqrt{3} (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.3.2

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} \sqrt{2} + \sqrt{2} \sqrt{3} + \sqrt{3} (\sqrt{2} + \sqrt{3}) - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.3.3

Apply the distributive property.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2} \sqrt{2} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4

Simplify and combine like terms.

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Step 6.1.4.1

Simplify each term.

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Step 6.1.4.1.1

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2 \cdot 2} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.2

Multiply $2$ by $2$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{4} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.3

Rewrite $4$ as $2^{2}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{\sqrt{2^{2}} + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.4

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{2} \sqrt{3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.5

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{2 \cdot 3} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.6

Multiply $2$ by $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{3} \sqrt{2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.7

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{3 \cdot 2} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.8

Multiply $3$ by $2$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3} \sqrt{3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.9

Combine using the product rule for radicals.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3 \cdot 3} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.10

Multiply $3$ by $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{9} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.11

Rewrite $9$ as $3^{2}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + \sqrt{3^{2}} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.1.12

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{2 + \sqrt{6} + \sqrt{6} + 3 - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.2

Add $2$ and $3$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + \sqrt{6} + \sqrt{6} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.4.3

Add $\sqrt{6}$ and $\sqrt{6}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + 2 \sqrt{6} - 4 \cdot 1 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.5

Multiply $- 4$ by $1$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 + 2 \sqrt{6} - 4 \cdot \sqrt{6}}}{2 \cdot 1}$

Step 6.1.6

Subtract $4 \sqrt{6}$ from $2 \sqrt{6}$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 - 2 \sqrt{6}}}{2 \cdot 1}$

Step 6.2

Multiply $2$ by $1$ .

$x = \frac{- \sqrt{2} - \sqrt{3} \pm \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 6.3

Change the $\pm$ to $-$ .

$x = \frac{- \sqrt{2} - \sqrt{3} - \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 6.4

Factor $- 1$ out of $- \sqrt{2}$ .

$x = \frac{- (\sqrt{2}) - \sqrt{3} - \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 6.5

Factor $- 1$ out of $- \sqrt{3}$ .

$x = \frac{- (\sqrt{2}) - (\sqrt{3}) - \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 6.6

Factor $- 1$ out of $- (\sqrt{2}) - (\sqrt{3})$ .

$x = \frac{- (\sqrt{2} + \sqrt{3}) - \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 6.7

Factor $- 1$ out of $- \sqrt{5 - 2 \sqrt{6}}$ .

$x = \frac{- (\sqrt{2} + \sqrt{3}) - (\sqrt{5 - 2 \sqrt{6}})}{2}$

Step 6.8

Factor $- 1$ out of $- (\sqrt{2} + \sqrt{3}) - (\sqrt{5 - 2 \sqrt{6}})$ .

$x = \frac{- (\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}})}{2}$

Step 6.9

Rewrite $- (\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}})$ as $- 1 (\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}})$ .

$x = \frac{- 1 (\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}})}{2}$

Step 6.10

Move the negative in front of the fraction.

$x = - \frac{\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 7

The final answer is the combination of both solutions.

$x = - \frac{\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}}}{2}, - \frac{\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}}}{2}$

Step 8

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{\sqrt{2} + \sqrt{3} - \sqrt{5 - 2 \sqrt{6}}}{2}, - \frac{\sqrt{2} + \sqrt{3} + \sqrt{5 - 2 \sqrt{6}}}{2}$

Decimal Form:

$x = - 1.41421356 \dots, - 1.73205080 \dots$