Pre-Algebra Examples

$f (x) = \sqrt{11 - x}$

Step 1

Find the domain for $y = \sqrt{11 - x}$ so that a list of $x$ values can be picked to find a list of points, which will help graphing the radical.

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Step 1.1

Set the radicand in $\sqrt{11 - x}$ greater than or equal to $0$ to find where the expression is defined.

$11 - x \geq 0$

Step 1.2

Solve for $x$ .

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Step 1.2.1

Subtract $11$ from both sides of the inequality.

$- x \geq - 11$

Step 1.2.2

Divide each term in $- x \geq - 11$ by $- 1$ and simplify.

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Step 1.2.2.1

Divide each term in $- x \geq - 11$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} \leq \frac{- 11}{- 1}$

Step 1.2.2.2

Simplify the left side.

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Step 1.2.2.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} \leq \frac{- 11}{- 1}$

Step 1.2.2.2.2

Divide $x$ by $1$ .

$x \leq \frac{- 11}{- 1}$

Step 1.2.2.3

Simplify the right side.

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Step 1.2.2.3.1

Divide $- 11$ by $- 1$ .

$x \leq 11$

Step 1.3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$(- \infty, 11]$

Set-Builder Notation:

${x | x \leq 11}$

Interval Notation:

$(- \infty, 11]$

Set-Builder Notation:

${x | x \leq 11}$

Step 2

To find the radical expression end point, substitute the $x$ value $11$ , which is the least value in the domain, into $f (x) = \sqrt{11 - x}$ .

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Step 2.1

Replace the variable $x$ with $11$ in the expression.

$f (11) = \sqrt{11 - (11)}$

Step 2.2

Simplify the result.

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Step 2.2.1

Multiply $- 1$ by $11$ .

$f (11) = \sqrt{11 - 11}$

Step 2.2.2

Subtract $11$ from $11$ .

$f (11) = \sqrt{0}$

Step 2.2.3

Rewrite $0$ as $0^{2}$ .

$f (11) = \sqrt{0^{2}}$

Step 2.2.4

Pull terms out from under the radical, assuming positive real numbers.

$f (11) = 0$

Step 2.2.5

The final answer is $0$ .

$0$

Step 3

The radical expression end point is $(11, 0)$ .

$(11, 0)$

Step 4

Select a few $x$ values from the domain. It would be more useful to select the values so that they are next to the $x$ value of the radical expression end point.

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Step 4.1

Substitute the $x$ value $9$ into $f (x) = \sqrt{11 - x}$ . In this case, the point is $(9, \sqrt{2})$ .

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Step 4.1.1

Replace the variable $x$ with $9$ in the expression.

$f (9) = \sqrt{11 - (9)}$

Step 4.1.2

Simplify the result.

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Step 4.1.2.1

Multiply $- 1$ by $9$ .

$f (9) = \sqrt{11 - 9}$

Step 4.1.2.2

Subtract $9$ from $11$ .

$f (9) = \sqrt{2}$

Step 4.1.2.3

The final answer is $\sqrt{2}$ .

$y = \sqrt{2}$

Step 4.2

Substitute the $x$ value $10$ into $f (x) = \sqrt{11 - x}$ . In this case, the point is $(10, 1)$ .

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Step 4.2.1

Replace the variable $x$ with $10$ in the expression.

$f (10) = \sqrt{11 - (10)}$

Step 4.2.2

Simplify the result.

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Step 4.2.2.1

Multiply $- 1$ by $10$ .

$f (10) = \sqrt{11 - 10}$

Step 4.2.2.2

Subtract $10$ from $11$ .

$f (10) = \sqrt{1}$

Step 4.2.2.3

Any root of $1$ is $1$ .

$f (10) = 1$

Step 4.2.2.4

The final answer is $1$ .

$y = 1$

Step 4.3

The square root can be graphed using the points around the vertex $(11, 0), (9, 1.41), (10, 1)$

$\begin{array}{c} x & y \\ 9 & 1.41 \\ 10 & 1 \\ 11 & 0 \end{array}$

Step 5