Pre-Algebra Examples

$7 x - y = - 3 x - y^{3}$

Step 1

Find the point at $x = - 2$ .

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Step 1.1

Replace the variable $x$ with $- 2$ in the expression.

$f (- 2) = - 10 \cdot - 2$

Step 1.2

Simplify the result.

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Step 1.2.1

Multiply $- 10$ by $- 2$ .

$f (- 2) = 20$

Step 1.2.2

The final answer is $20$ .

$20$

Step 1.3

Convert $20$ to decimal.

$y = 20$

Step 2

Find the point at $x = - 1$ .

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Step 2.1

Replace the variable $x$ with $- 1$ in the expression.

$f (- 1) = - 10 \cdot - 1$

Step 2.2

Simplify the result.

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Step 2.2.1

Multiply $- 10$ by $- 1$ .

$f (- 1) = 10$

Step 2.2.2

The final answer is $10$ .

$10$

Step 2.3

Convert $10$ to decimal.

$y = 10$

Step 3

Find the point at $x = 0$ .

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Step 3.1

Replace the variable $x$ with $0$ in the expression.

$f (0) = - 10 \cdot 0$

Step 3.2

Simplify the result.

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Step 3.2.1

Multiply $- 10$ by $0$ .

$f (0) = 0$

Step 3.2.2

The final answer is $0$ .

$0$

Step 3.3

Convert $0$ to decimal.

$y = 0$

Step 4

Find the point at $x = 1$ .

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Step 4.1

Replace the variable $x$ with $1$ in the expression.

$f (1) = - 10 \cdot 1$

Step 4.2

Simplify the result.

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Step 4.2.1

Multiply $- 10$ by $1$ .

$f (1) = - 10$

Step 4.2.2

The final answer is $- 10$ .

$- 10$

Step 4.3

Convert $- 10$ to decimal.

$y = - 10$

Step 5

Find the point at $x = 2$ .

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Step 5.1

Replace the variable $x$ with $2$ in the expression.

$f (2) = - 10 \cdot 2$

Step 5.2

Simplify the result.

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Step 5.2.1

Multiply $- 10$ by $2$ .

$f (2) = - 20$

Step 5.2.2

The final answer is $- 20$ .

$- 20$

Step 5.3

Convert $- 20$ to decimal.

$y = - 20$

Step 6

The cubic function can be graphed using the function behavior and the points.

$\begin{array}{c} x & y \\ - 2 & 20 \\ - 1 & 10 \\ 0 & 0 \\ 1 & - 10 \\ 2 & - 20 \end{array}$

Step 7

The cubic function can be graphed using the function behavior and the selected points.

Rises to the left and falls to the right

$\begin{array}{c} x & y \\ - 2 & 20 \\ - 1 & 10 \\ 0 & 0 \\ 1 & - 10 \\ 2 & - 20 \end{array}$

Step 8